Chapter 18: Problem 61
The human body transports heat from the interior tissues, at temperature \(37.0^{\circ} \mathrm{C},\) to the skin surface, at temperature \(27.0^{\circ} \mathrm{C},\) at a rate of \(100 . \mathrm{W}\). If the skin area is \(1.5 \mathrm{~m}^{2}\) and its thickness is \(3.0 \mathrm{~mm}\), what is the effective thermal conductivity, \(\kappa,\) of skin?
Short Answer
Step by step solution
Identify the given values
Convert all values to SI units
Calculate the temperature difference
Rearrange Fourier's Law to find the thermal conductivity
Calculate the effective thermal conductivity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat Transfer
- Conduction: The transfer of heat through a material without the movement of the material itself.
- Convection: The transfer of heat by the movement of fluid (liquid or gas).
- Radiation: The transfer of heat in the form of electromagnetic waves.
In the context of the exercise, we focus on heat transfer by conduction through the skin. Conduction occurs when there is a temperature difference between two points. Here, heat moves from the warm interior tissues to the cooler skin surface. Understanding this transfer is crucial as it helps in calculating the thermal properties of materials, like the thermal conductivity of skin.
Fourier's Law
Fourier's Law can be mathematically expressed as:\[Q = -abla(T) imes A imes abla d \]Where:
- \( Q \) is the rate of heat transfer (Watts).
- \( abla(T) \) is the temperature gradient (difference in temperature over distance).
- \( A \) is the area through which heat is flowing (square meters).
- \( abla d \) is the direction of heat flow.
In practical terms, the law helps to connect how efficiently a material can conduct heat, given its intrinsic properties. For the given problem, Fourier’s Law is used to determine the effective thermal conductivity.
SI Units Conversion
- Temperature in Celsius can be converted to Kelvin by adding 273.15. For example, \(37.0 ^{\circ} C\) becomes \(310.15 K\).
- Length in millimeters can be converted to meters by multiplying by the factor \( \frac{1 \text{ m}}{1000 \text{ mm}} \). Hence, \(3.0 \text{ mm}\) turns into \(0.003 \text{ m}\).
Ensuring all your measurements are in the appropriate SI units is crucial for standardizing calculations and communicating results effectively. This conversion is an important step especially in fields like heat transfer, where precision is key.
Temperature Difference
To calculate temperature difference, subtract the temperature at one point from the temperature at another:\[\Delta T = T_1 - T_2\]Where:
- \( T_1 \) is the temperature at the interior tissues expressed in Kelvin.
- \( T_2 \) is the temperature at the skin surface also in Kelvin.
In this exercise, the temperature difference was found to be 10 K (Kelvin). This difference is crucial as it determines the rate at which heat is conducted through the skin, impacting the calculation of its thermal conductivity.