Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In one of your rigorous workout sessions, you lost 150 g of water through evaporation. Assume that the amount of work done by your body was 1.80105 J and that the heat required to evaporate the water came from your body. a) Find the loss in internal energy of your body, assuming the latent heat of vaporization is 2.42106 J/kg. b) Determine the minimum number of food calories that must be consumed to replace the internal energy lost (1 food calorie =4186 J).

Short Answer

Expert verified
Answer: 44 food calories.

Step by step solution

01

Calculate the energy required to evaporate the given amount of water

To calculate the energy required to evaporate the given amount of water, we use the formula: Energy = Mass x Latent heat of vaporization where Mass = 150g (converted to kg) and Latent heat of vaporization = 2.42106J/kg. Converting the mass of water to kg: 150g×1kg1000g=0.15kg. Energy = 0.15kg×2.42106J/kg Energy = 3.63105J
02

Determine the loss in internal energy

According to the conservation of energy, the work done by the body is equal to the energy required to evaporate the water plus the change in the internal energy of your body, Work done = Energy + Loss in internal energy Rearranging the equation, we get: Loss in internal energy = Work done - Energy Loss in internal energy = 1.80105J3.63105J Loss in internal energy = 1.83105J The negative sign indicates that the internal energy of your body has decreased. b) Determine the minimum number of food calories
03

Convert the Joules to food calories

To convert the lost energy from Joules to food calories, we use the conversion factor given, 1 food calorie = 4186 J Lost energy in food calories = 1.83105J4186J/foodcalorie Lost energy in food calories = 43.77food calories
04

Find the minimum number of food calories needed to replace the lost internal energy

Since energy cannot be negative, we must consume at least 43.77 food calories to replace the lost internal energy. Minimum number of food calories = 44 (rounded up)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
Internal energy is a concept in thermodynamics that represents the total energy contained within a system due to both its thermal and molecular motion. It is a critical aspect when considering energy changes during processes like phase transitions or chemical reactions.

In the context of the exercise, the internal energy of your body changes as a result of evaporating sweat. When you sweat, the body uses its stored thermal energy to convert liquid sweat into vapor, which results in a loss of internal energy.

The solution outlines how the loss of internal energy is calculated. By applying the principle of energy conservation, we know:
  • Energy needed to evaporate water + Work done by body = Change in internal energy.
  • If the energy for evaporation exceeds the work done, internal energy decreases.
In our example, the internal energy loss calculated is negative, indicating an actual decrease in the body's internal energy, highlighting the energy expended in evaporating the sweat.
Latent Heat of Vaporization
Latent heat of vaporization is the amount of heat energy required to turn a substance from a liquid into a vapor without changing its temperature. It's an important concept in understanding phase changes in thermodynamics.

This heat is absorbed from the environment, or in the case of your body, from the internal energy stores, allowing the substance (sweat) to transition into gaseous form. In this specific exercise, we examine the latent heat of vaporization of water, quantified as 2.42×106 J/kg.

Using the formula for energy needed in phase transition:
Energy = Mass × Latent heat of vaporization,
we can calculate the amount of energy required for the evaporation of 150 g of water. By converting grams to kilograms, and applying the latent heat value, the energy required is 3.63×105 J. Understanding this can help appreciate why sweating cools you down – it removes a substantial amount of heat from your body!
Energy Conservation
Energy conservation is a fundamental principle in physics, indicating that energy in a closed system remains constant. It implies that within such a system, energy can neither be created nor destroyed, only transformed from one form to another.

In the scenario of a workout, your body acts as this closed system. As you exercise and sweat, the energy transformation occurs in several stages:
  • Internal energy is transformed to evaporate sweat (as discussed with internal energy).
  • Work done by the body contributes to the energy balance equation.
The formula representing this is:
Work done = Energy for evaporation + Loss in internal energy. By rearranging this formula, it helps us understand how much internal energy the body loses, answering part of the exercise's question.

The exercise further emphasizes energy conservation by converting the lost energy into food calories. This step shows what is required to restore the internal energy balance. In doing so, it reinforces how energy is budgeted and used in our daily physiological processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Knife blades are often made of hardened carbon steel. The hardening process is a heat treatment in which the blade is first heated to a temperature of 1346F and then cooled down rapidly by immersing it in a bath of water. To achieve the desired hardness, after heating to 1346F, a blade needs to be brought to a temperature below 5.00102F. If the blade has a mass of 0.500 kg and the water is in an open copper container of mass 2.000 kg and sufficiently large volume, what is the minimum quantity of water that needs to be in the container for this hardening process to be successful? Assume the blade is not in direct mechanical (and thus thermal) contact with the container, and neglect cooling through radiation into the air. Assume no water boils but reaches 100C. The heat capacity of copper around room temperature is ccopper =386 J/(kgK). Use the data in the table below for the heat capacity of carbon steel

The internal energy of a gas is 500. J. The gas is compressed adiabatically, and its volume decreases by 100.cm3. If the pressure applied on the gas during compression is 3.00 atm, what is the internal energy of the gas after the adiabatic compression?

Suppose 0.010 kg of steam (at 100.00C ) is added to 0.10 kg of water (initially at 19.0C). The water is inside an aluminum cup of mass 35 g. The cup is inside a perfectly insulated calorimetry container that prevents heat flow with the outside environment. Find the final temperature of the water after equilibrium is reached.

A 2.0102 g piece of copper at a temperature of 450 K and a 1.0102 g piece of aluminum at a temperature of 2.0102 K are dropped into an insulated bucket containing 5.0102 g of water at 280 K. What is the equilibrium temperature of the mixture?

You were lost while hiking outside wearing only a bathing suit. a) Calculate the power radiated from your body, assuming that your body's surface area is about 2.00 m2 and your skin temperature is about 33.0C. Also, assume that your body has an emissivity of 1.00 . b) Calculate the net radiated power from your body when you were inside a shelter at 20.0C. c) Calculate the net radiated power from your body when your skin temperature dropped to 27.0C.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free