Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The density of a sample of air is \(1.205 \mathrm{~kg} / \mathrm{m}^{3}\), and the bulk modulus is \(1.42 \cdot 10^{5} \mathrm{~N} / \mathrm{m}^{2}\) a) Find the speed of sound in the air sample. b) Find the temperature of the air sample.

Short Answer

Expert verified
Answer: The speed of sound in the air sample is approximately 331.25 m/s, and the temperature is approximately 273.1 K.

Step by step solution

01

Find the speed of sound in the air sample

To find the speed of sound in the air sample, we will use the following formula: v = sqrt(B/ρ) Where v is the speed of sound, B is the bulk modulus, and ρ is the density. Given values: B = 1.42 * 10^5 N/m^2 ρ = 1.205 kg/m^3 Plug in the given values into the formula: v = sqrt((1.42 * 10^5 N/m^2) / (1.205 kg/m^3)) Now, calculate the speed of sound (v): v ≈ 331.25 m/s The speed of sound in the air sample is approximately 331.25 m/s.
02

Find the temperature of the air sample

To find the temperature of the air sample, we will use the following formula: v = sqrt(γRT / ρ) Where v is the speed of sound, γ is the adiabatic index, R is the specific gas constant for air, T is the temperature, and ρ is the density. Given values: v = 331.25 m/s γ = 1.4 (adiabatic index for air) R = 287 J/(kg*K) (specific gas constant for air) ρ = 1.205 kg/m^3 Rewrite the formula to isolate T: T = (v^2 * ρ) / (γR) Plug in the known values into the formula: T = ((331.25 m/s)^2 * (1.205 kg/m^3)) / (1.4 * 287 J/(kg*K)) Now, calculate the temperature (T): T ≈ 273.1 K The temperature of the air sample is approximately 273.1 K.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bulk Modulus
The bulk modulus is a fundamental concept in understanding how materials compress under pressure. It measures a material's resistance to uniform compression. Essentially, it tells us how difficult it is to change the volume of a substance when applying pressure. In the context of sound waves traveling through a medium like air, the bulk modulus is crucial.
  • When sound waves travel, they create regions of compression and rarefaction in the medium.
  • The bulk modulus determines how these regions affect the medium's volume.
  • A high bulk modulus means the medium is less compressible and can support faster sound waves.
In the original exercise, the given bulk modulus of the air sample is used to calculate the speed of sound, illustrating its direct impact on sound propagation.
Density of Air
Density is a measure of how much mass is present in a given volume. In air, density affects how sound moves through it. In simple terms, the denser the air, the closer together its molecules are, impacting the speed of sound.
  • More molecules in a given space lead to more collisions, potentially slowing the sound down.
  • However, increased density also means more energy is transferred per collision, offsetting the slowing effect.
In the provided exercise, we have the air density at 1.205 kg/m³. This value is plugged into the formula for sound speed, showing how density works hand in hand with bulk modulus to determine the speed. Understanding air density is crucial to predicting and modeling sound propagation in different atmospheres.
Adiabatic Index
The adiabatic index, commonly represented as \( \gamma \) (gamma), is vital in thermodynamics and plays a role in sound speed calculations. It represents the ratio of specific heats at constant pressure and volume. For air, \( \gamma \) is typically 1.4, but here's why it matters:
  • It reflects how air pressure changes with volume without heat transfer (adiabatic process).
  • This index is crucial when calculating sound speed because sound propagation is an adiabatic process.
  • The adiabatic index impacts how efficiently pressure changes translate to volume changes in sound waves.
In the exercise, \( \gamma \) is used to find the air temperature through the relationship with speed, revealing its tie to both thermodynamics and acoustic dynamics.
Specific Gas Constant
The specific gas constant, denoted as \( R \), ties temperature, volume, and pressure in a gas. Each distinct gas has its specific gas constant, and for air, this value is 287 J/(kg*K). This constant is crucial when determining properties like temperature via the ideal gas law and sound speed estimation.
  • \( R \) represents energy per degree increase for one mole of the gas.
  • In terms of sound, it helps relate the speed of sound to temperature through the equation \( v = \sqrt{\gamma RT / \rho} \).
  • This relationship suggests that as temperature increases, the speed of sound increases, due to higher kinetic energy of air molecules.
Understanding the specific gas constant is essential for linking thermodynamic properties to acoustic phenomena, as shown in calculating the temperature from sound speed in the exercise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A half-open pipe is constructed to produce a fundamental frequency of \(262 \mathrm{~Hz}\) when the air temperature is \(22^{\circ} \mathrm{C} .\) It is used in an overheated building when the temperature is \(35^{\circ} \mathrm{C} .\) Neglecting thermal expansion in the pipe, what frequency will be heard?

A bugle can be represented by a cylindrical pipe of length \(L=1.35 \mathrm{~m} .\) Since the ends are open, the standing waves produced in the bugle have antinodes at the open ends, where the air molecules move back and forth the most. Calculate the longest three wavelengths of standing waves inside the bugle. Also calculate the three lowest frequencies and the three longest wavelengths of the sound that is produced in the air around the bugle.

The sound level in decibels is typically expressed as \(\beta=10 \log \left(I / I_{0}\right),\) but since sound is a pressure wave, the sound level can be expressed in terms of a pressure difference. Intensity depends on the amplitude squared, so the expression is \(\beta=20 \log \left(P / P_{0}\right),\) where \(P_{0}\) is the smallest pressure difference noticeable by the ear: \(P_{0}=2.00 \cdot 10^{-5} \mathrm{~Pa}\). A loud rock concert has a sound level of \(110 . \mathrm{dB}\), find the amplitude of the pressure wave generated by this concert.

A source traveling to the right at a speed of \(10.00 \mathrm{~m} / \mathrm{s}\) emits a sound wave at a frequency of \(100.0 \mathrm{~Hz}\). The sound wave bounces off of a reflector, which is traveling to the left at a speed of \(5.00 \mathrm{~m} / \mathrm{s}\). What is the frequency of the reflected sound wave detected by a listener back at the source?

If you blow air across the mouth of an empty soda bottle, you hear a tone. Why is it that if you put some water in the bottle, the pitch of the tone increases?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free