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The different colors of light we perceive are a result of the varying frequencies (and wavelengths) of the electromagnetic radiation. Infrared radiation has lower frequencies than does visible light, and ultraviolet radiation has higher frequencies than visible light does. The primary colors are red (R), yellow (Y), and blue (B). Order these colors by their wavelength, shortest to longest. a) \(\mathrm{B}, \mathrm{Y}, \mathrm{R}\) b) \(B, R, Y\) c) \(\mathrm{R}, \mathrm{Y}, \mathrm{B}\) d) \(R, B, Y\)

Short Answer

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Question: Order the primary colors from shortest to longest wavelength. Answer: Blue, Yellow, Red.

Step by step solution

01

General Knowledge: Color Wavelengths

The electromagnetic radiation can be represented by waves with different wavelengths. The colors we see are determined by the wavelengths of these waves. Wavelengths are inversely proportional to frequencies. So, a higher frequency corresponds to a shorter wavelength and vice versa. The order of the colors in the light spectrum i.e Visible light from shortest to longest wavelength can be remembered as ROYGBIV. It represents: - Red (R) - Orange (O) - Yellow (Y) - Green (G) - Blue (B) - Indigo (I) - Violet (V) From this, we can deduce that the wavelength increases from V to R.
02

Analyze Given Colors

We are given the primary colors Red (R), Yellow (Y), and Blue (B) and are tasked with ordering them by their wavelength from shortest to longest. Using the knowledge from the previous step, we can conclude the order - B, Y, R.
03

Matching the Order with Options

From the Step 1, we have the order as follows: B, Y, R (wavelength from shortest to longest). This corresponds to option (a). So, the correct answer is (a) \(\mathrm{B}, \mathrm{Y}, \mathrm{R}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Visible Light Wavelengths
Visible light wavelengths are the portion of the electromagnetic spectrum that can be detected by the human eye. Our perception of color comes from this narrow band of frequencies. In the visible spectrum, which ranges from about 380 nanometers to 750 nanometers, each color has a distinct wavelength.

For example, violet has the shortest wavelength, around 380 nm, and red has the longest wavelength, around 750 nm. The order of colors by increasing wavelength is commonly remembered by the mnemonic ROYGBIV — Red, Orange, Yellow, Green, Blue, Indigo, Violet. Within this sequence, each color smoothly transitions into the next, creating what we know as the 'rainbow' of visible light.

Understanding the order of light wavelengths is crucial not only for scientific study but also for practical applications such as color printing and display technology, where accurate color representation is essential.
Color Perception in Physics
Color perception in physics is rooted in the way our eyes detect light and how different wavelengths correspond to our experience of color. Inside our eyes, we have two types of photoreceptor cells: rods and cones.

Rods are responsible for vision at low light levels, while cones are active at higher light levels and enable us to see color. Humans typically have three types of cones, each sensitive to different wavelengths of light: one for long wavelengths (red), one for medium (green), and one for short wavelengths (blue).

Color Mixing

When light of different wavelengths stimulates these cones to varying degrees, we perceive a mixture of colors. For instance, yellow light stimulates both the red and green cones, which our brain interprets as the color yellow. This is also how televisions and monitors use red, green, and blue (RGB) pixels to create the range of colors we see on screens.
Frequency-Wavelength Relationship
The frequency-wavelength relationship is a cornerstone of understanding electromagnetic waves. This relationship is expressed by the equation \( c = \lambda \times f \) where \( c \) is the speed of light (\( approximately 3 \times 10^8 \) meters per second), \( \lambda \) is the wavelength, and \( f \) is the frequency.

Since the speed of light is constant in a vacuum, an increase in frequency means a decrease in wavelength, and vice versa. This inverse relationship means that electromagnetic waves with higher frequencies (like ultraviolet light) have shorter wavelengths, while those with lower frequencies (like infrared) have longer wavelengths.

Thus, knowing the frequency of a wave allows us to calculate its wavelength and vice versa, a principle crucial for many technologies, from radio broadcasting to medical imaging.

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Most popular questions from this chapter

Why do circular water waves on the surface of a pond decrease in amplitude as they travel away from the source?

A sinusoidal wave traveling in the positive \(x\) -direction has a wavelength of \(12 \mathrm{~cm},\) a frequency of \(10.0 \mathrm{~Hz},\) and an amplitude of \(10.0 \mathrm{~cm}\). The part of the wave that is at the origin at \(t=0\) has a vertical displacement of \(5.00 \mathrm{~cm} .\) For this wave, determine the a) wave number, d) speed, b) period, e) phase angle, and c) angular frequency, f) equation of motion.

Students in a lab produce standing waves on stretched strings connected to vibration generators. One such wave is described by the wave function \(y(x, t)=(2.00 \mathrm{~cm}) \sin \left[\left(20.0 \mathrm{~m}^{-1}\right) x\right] \cos \left[\left(150 . \mathrm{s}^{-1}\right) t\right],\) where \(y\) is the transverse displacement of the string, \(x\) is the position along the string, and \(t\) is time. Rewrite this wave function in the form for a right- moving and a left-moving wave: \(y(x, t)=\) \(f(x-v t)+g(x+v t)\); that is, find the functions \(f\) and \(g\) and the speed, \(v\)

Two steel wires are stretched under the same tension. The first wire has a diameter of \(0.500 \mathrm{~mm}\), and the second wire has a diameter of \(1.00 \mathrm{~mm}\). If the speed of waves traveling along the first wire is \(50.0 \mathrm{~m} / \mathrm{s}\), what is the speed of waves traveling along the second wire?

The tension in a 2.7 -m-long, 1.0 -cm-diameter steel cable \(\left(\rho=7800 \mathrm{~kg} / \mathrm{m}^{3}\right)\) is \(840 \mathrm{~N}\). What is the fundamental frequency of vibration of the cable?

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