Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Why do circular water waves on the surface of a pond decrease in amplitude as they travel away from the source?

Short Answer

Expert verified
Answer: The amplitude of circular water waves decreases as they travel away from the source because the energy of the waves is distributed over expanding circular wavefronts. As the wavefronts expand in radius, they cover a larger surface area, causing the energy density to decrease, which in turn leads to a decrease in amplitude.

Step by step solution

01

Define amplitude

Amplitude refers to the maximum displacement of a wave from its equilibrium position. It is a measure of the wave's energy, as a wave with a higher amplitude has more energy than a wave with a lower amplitude.
02

Understand the circular wavefront

A circular wavefront is produced when a disturbance (e.g., a stone thrown into a pond) occurs at a single point on the surface of the water. The energy from this disturbance produces circular wavefronts, centered on the point of disturbance. As the wavefronts travel away from the source, they expand in a concentric and roughly circular pattern.
03

Explain energy distribution in circular wavefront

The energy from the disturbance is spread evenly over the surface of each successive wavefront. As a wavefront expands, its surface area increases; specifically, the surface area of a wavefront is proportional to the square of its radius (A = 4πr^2). Consequently, at a greater distance from the source, the same amount of energy is distributed over a larger area, resulting in a reduced energy density.
04

Relate energy density to amplitude

Since the amplitude of a wave is directly related to its energy, a decrease in energy density leads to a decrease in amplitude. As the wavefronts expand and travel away from the source, they encounter a larger area to cover. This causes the energy to be spread thinner, leading to a reduction in the amplitude of the waves.
05

Conclusion

Circular water waves on the surface of a pond decrease in amplitude as they travel away from the source because the energy of the waves is distributed over expanding circular wavefronts. As the wavefronts expand in radius, they cover a larger surface area, causing the energy density to decrease, which in turn leads to a decrease in amplitude.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an acoustics experiment, a piano string with a mass of \(5.00 \mathrm{~g}\) and a length of \(70.0 \mathrm{~cm}\) is held under tension by running the string over a frictionless pulley and hanging a \(250 .-\mathrm{kg}\) weight from it. The whole system is placed in an elevator. a) What is the fundamental frequency of oscillation for the string when the elevator is at rest? b) With what acceleration and in what direction (up or down) should the elevator move for the string to produce the proper frequency of \(440 .\) Hz, corresponding to middle A?

Fans at a local football stadium are so excited that their team is winning that they start "the wave" in celebration. Which of the following four statements is (are) true? I. This wave is a traveling wave. II. This wave is a transverse wave. III. This wave is a longitudinal wave. IV. This wave is a combination of a longitudinal wave and a transverse wave. a) I and II c) III only e) I and III b) II only d) I and IV

The equation for a standing wave on a string with mass density \(\mu\) is \(y(x, t)=2 A \cos (\omega t) \sin (\kappa x) .\) Show that the average kinetic energy and potential energy over time for this wave per unit length are given by \(K_{\text {ave }}(x)=\mu \omega^{2} A^{2} \sin ^{2} \kappa x\) and \(U_{\text {ave }}(x)=T(\kappa A)^{2}\left(\cos ^{2} \kappa x\right)\)

Which of the following transverse waves has the greatest power? a) a wave with velocity \(v\), amplitude \(A\), and frequency \(f\) b) a wave of velocity \(v\), amplitude \(2 A\), and frequency \(f / 2\) c) a wave of velocity \(2 v\), amplitude \(A / 2\), and frequency \(f\) d) a wave of velocity \(2 v\), amplitude \(A\), and frequency \(f / 2\) e) a wave of velocity \(v\), amplitude \(A / 2\), and frequency \(2 f\)

The speed of light waves in air is greater than the speed of sound in air by about a factor of a million. Given a sound wave and a light wave of the same wavelength, both traveling through air, which statement about their frequencies is true? a) The frequency of the sound wave will be about a million times greater than that of the light wave. b) The frequency of the sound wave will be about a thousand times greater than that of the light wave. c) The frequency of the light wave will be about a thousand times greater than that of the sound wave. d) The frequency of the light wave will be about a million times greater than that of the sound wave. e) There is insufficient information to determine the relationship between the two frequencies.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free