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You have a linear (following Hooke's Law) spring with an unknown spring constant, a standard mass, and a timer. Explain carefully how you could most practically use these to measure masses in the absence of gravity. Be as quantitative as you can. Regard the mass of the spring as negligible

Short Answer

Expert verified
Answer: You can measure masses in the absence of gravity by first determining the spring constant (k) using Hooke's Law and the standard mass. Then, set up the mass-spring system in zero gravity, attach the unknown mass to the spring and oscillate it, measuring the period of oscillation (T). Next, calculate the angular frequency (ω) and use it, along with the spring constant (k), to solve for the unknown mass (M).

Step by step solution

01

Determine the spring constant (k) using Hooke's Law

Place the standard mass on the spring and measure the displacement (d) caused by the attached standard mass. According to Hooke's Law, F = -k * d, where F is the force exerted by the spring, k is the spring constant, and d is the displacement. In this case, F is the gravitational force acting on the standard mass (F = m * g), where m is the mass, and g is the acceleration due to gravity. Therefore, we can find the spring constant k by rearranging the equation: k = -(m * g) / d.
02

Set up the mass-spring system in zero gravity

For the given problem, we have to operate in the absence of gravity. Set up the mass-spring system in such a way that gravity is no longer a factor, meaning the spring will only provide the restoring force for any attached mass.
03

Oscillate the spring and measure the period

Attach the unknown mass (M) to the spring and slightly displace it from its equilibrium position to set it into oscillation. Using the timer, measure the time it takes for the mass to complete one full oscillation. This time is known as the period of oscillation (T).
04

Calculate the angular frequency

Since we have the period of oscillation, we can calculate the angular frequency of oscillations (ω) using the following equation: ω = (2 * π) / T.
05

Calculate the unknown mass (M) using the angular frequency

The angular frequency (ω) is related to the spring constant (k) and the unknown mass (M) with the following equation: ω² = k / M. Use the previously calculated values of k and ω to solve for the unknown mass (M): M = k / ω². By following these steps, one could practically use a linear spring following Hooke's Law, a standard mass, and a timer to measure masses in the absence of gravity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The spring constant, denoted by \( k \), is a fundamental parameter that characterizes a spring's stiffness. According to Hooke's Law, the force exerted by a spring is directly proportional to its displacement from the equilibrium position. This is mathematically expressed as \( F = -k \, d \), where \( F \) is the force applied, \( k \) is the spring constant, and \( d \) is the displacement.

In practice, you can determine the spring constant by using a standard mass. When you hang this mass on the spring, it will exert a gravitational force that causes displacement. By measuring this displacement, you can rearrange the Hooke's Law formula to solve for \( k \), as \( k = -(m \cdot g) / d \), where \( m \) is the mass, \( g \) is the acceleration due to gravity, and \( d \) is the displacement.

It's important to remember that the spring constant remains the same regardless of the environment, whether in normal gravity or zero gravity.
Oscillations
Oscillations occur when a system moves back and forth repeatedly through a central equilibrium position. In the context of a spring-mass system, you can initiate oscillations by slightly displacing the mass from its rest position, allowing it to move.

The repeated motion follows a regular cycle known as the period of oscillation. Each complete cycle involves the mass moving to one side and returning back to its original position. Observing these oscillations is crucial when attempting to measure unknown masses in situations where gravity is not present.
  • Key characteristic: periodic and repeating motion.
  • Equilibrium position: center point where the system naturally returns.
  • Useful in determining properties such as angular frequency and mass.
Angular Frequency
Angular frequency, represented by \( \omega \), describes how rapidly a system completes cycles of oscillation. It's closely related to the period \( T \), which is the time taken for one cycle to complete.

The relationship between these quantities can be calculated as \( \omega = \frac{2 \pi}{T} \). This formula illustrates that the angular frequency is the reciprocal of the period scaled by the factor \( 2 \pi \), which adjusts for circular motion.
  • Measure of rotational speed: how fast oscillations occur.
  • Expressed in radians per second.
  • Essential for calculating unknown masses using Hooke's Law in zero gravity.
Zero Gravity
Zero gravity, also known as microgravity, is an environment in which gravitational forces are negligible. Under this condition, objects appear weightless, removing gravitational influence from the equation.

In the absence of gravity, when you attach a mass to a spring, only the spring's restoring force acts on the mass. This unique condition allows the mass-spring system to perfectly oscillate without gravitational interference, making it ideal for measuring masses based only on spring properties.
  • No gravitational force influences the movement.
  • Allows pure oscillatory motion driven by spring force.
  • Facilitates accurate measurement of unknown masses through spring oscillations.
Mass Measurement
Mass measurement in zero gravity using a spring involves determining the unknown mass based on its oscillatory behavior when attached to a known spring.

After determining the spring constant \( k \) and measuring the period of oscillation \( T \), you can calculate the angular frequency \( \omega \) using \( \omega = \frac{2 \pi}{T} \). With these, you can find the unknown mass \( M \) using the equation \( M = \frac{k}{\omega^2} \).
  • Uses known spring parameters to deduce mass.
  • Relies on pure oscillatory motion in a zero-gravity setup.
  • Effective and practical method for mass determination in absence of gravitational pull.

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Most popular questions from this chapter

A shock absorber that provides critical damping with \(\omega_{\gamma}=72.4 \mathrm{~Hz}\) is compressed by \(6.41 \mathrm{~cm} .\) How far from the equilibrium position is it after \(0.0247 \mathrm{~s} ?\)

If you kick a harmonic oscillator sharply, you impart to it an initial velocity but no initial displacement. For a weakly damped oscillator with mass \(m\), spring constant \(k\). and damping force \(F_{y}=-b v,\) find \(x(t),\) if the total impulse delivered by the kick is \(J_{0}\).

A mass of \(10.0 \mathrm{~kg}\) is hanging by a steel wire \(1.00 \mathrm{~m}\) long and \(1.00 \mathrm{~mm}\) in diameter. If the mass is pulled down slightly and released, what will be the frequency of the resulting oscillations? Young's modulus for steel is \(2.0 \cdot 10^{11} \mathrm{~N} / \mathrm{m}^{2}\)

A mass \(m=1.00 \mathrm{~kg}\) in a spring-mass system with \(k=\) \(1.00 \mathrm{~N} / \mathrm{m}\) is observed to be moving to the right, past its equi. librium position with a speed of \(1.00 \mathrm{~m} / \mathrm{s}\) at time \(t=0 .\) a) Ignoring all damping, determine the equation of motion. b) Suppose the initial conditions are such that at time \(t=0\), the mass is at \(x=0.500 \mathrm{~m}\) and moving to the right with a speed of \(1.00 \mathrm{~m} / \mathrm{s}\). Determine the new equation of motion. Assume the same spring constant and mass.

The figure shows a mass \(m_{2}=20.0\) g resting on top of a mass \(m_{1}=20.0 \mathrm{~g}\) which is attached to a spring with \(k=10.0 \mathrm{~N} / \mathrm{m}\) The coefficient of static friction between the two masses is 0.600 . The masses are oscillating with simple harmonic motion on a frictionless surface. What is the maximum amplitude the oscillation can have without \(m_{2}\) slipping off \(m_{1} ?\)

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