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Two children are on adjacent playground swings of the same height. They are given pushes by an adult and then left to swing. Assuming that each child on a swing can be treated as a simple pendulum and that friction is negligible, which child takes the longer time for one complete swing (has a longer period)? a) the bigger child d) the child given the b) the lighter child biggest push c) neither child

Short Answer

Expert verified
Answer: (c) Neither child has a longer period.

Step by step solution

01

Understand what a simple pendulum is

A simple pendulum consists of a small, heavy object (the “pendulum bob”) suspended by a light, inextensible string. The motion of the pendulum is determined by the length of the string and the angle it makes with the vertical, called the displacement angle.
02

Derive the equation for the period of a simple pendulum

The equation for the period T (the time it takes for one full oscillation) of a simple pendulum can be derived from the equation of motion using the small angle approximation. The equation for the period of a simple pendulum is given by: T = 2\pi\sqrt{\frac{L}{g}} where L is the length of the pendulum, and g is the acceleration due to gravity.
03

Identify the relevant parameters from the exercise

The exercise asks about the period of a pendulum that is affected by two factors: the mass of the child and the initial push given. According to the equation in step 2, the period T of a simple pendulum depends only on the length L and acceleration due to gravity g. The mass of the child and the initial push are not included in the equation.
04

Determine which child has a longer period

Since the period of a simple pendulum does not depend on its mass or the initial push given, both children will have the same period, assuming they are on swings of the same height (length). Thus, neither child has a longer period. #Conclusion# The correct answer is (c): neither child has a longer period, as the period of a simple pendulum depends only on its length and the acceleration due to gravity, and not on the mass of the child or the initial push given.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pendulum Period
The period of a simple pendulum refers to the time it takes for the pendulum to complete one full swing, going from one side to the other and back. It's an essential concept in understanding pendulum motion and is determined by the physical properties of the pendulum itself.
In the context of a simple pendulum, the period \( T \) is given by the formula:\[ T = 2\pi\sqrt{\frac{L}{g}} \]where:
  • \( L \) is the length of the pendulum.
  • \( g \) is the acceleration due to gravity, typically about \( 9.81 \text{ m/s}^2 \) on Earth.

Interestingly, this formula shows that the period of a simple pendulum is independent of the mass of the pendulum bob or the initial push given. Therefore, two pendulums of equal length will have the same period, regardless of their masses or how hard they are swung. This principle simplifies the understanding of pendulum motion significantly, as you only need to consider the length of the pendulum to predict its period.
Small Angle Approximation
In the study of pendulums, especially simple pendulums, the small angle approximation is a useful concept. It states that for small angles (usually less than 15 degrees), the sine of the angle is approximately equal to the angle itself when measured in radians. This makes the mathematics involved much simpler.
For a pendulum, the angle refers to the initial angular displacement from the vertical position. If this angle is small, we can use the small angle approximation to simplify the equations of motion. Specifically, we get:
\[ \sin(\theta) \approx \theta \] for small \( \theta \) (in radians).
This approximation allows us to derive the expression for the period of a pendulum without needing complex trigonometric functions. It's worth noting that as the angle of displacement increases, this approximation becomes less accurate, potentially affecting the precision of the period calculation slightly.
Equation of Motion
The equation of motion for a simple pendulum describes how it moves over time. It is derived from Newton's laws of motion and involves variables like the acceleration due to gravity, the length of the pendulum, and the angle of displacement.
The fundamental differential equation for a simple pendulum is:\[ \frac{d^2\theta}{dt^2} + \frac{g}{L} \sin(\theta) = 0 \]where:
  • \( \theta \) is the angular displacement.
  • \( t \) represents time.
  • \( g \) is the acceleration due to gravity.
  • \( L \) is the length of the pendulum.

Using the small angle approximation, this equation simplifies to the simple harmonic motion form:
\[ \frac{d^2\theta}{dt^2} + \frac{g}{L} \theta = 0 \]
This equation resembles that of other harmonic oscillators like springs, making it easier to study pendulums using established methods. The solution to this equation helps determine how a pendulum's angle changes with time, ultimately leading to understanding the pendulum's behavior and predicting its period accurately.

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Most popular questions from this chapter

A physical pendulum consists of a uniform rod of mass \(M\) and length \(L\) The pendulum is pivoted at a point that is a distance \(x\) from the center of the rod, so the period for oscillation of the pendulum depends on \(x: T(x)\). a) What value of \(x\) gives the maximum value for \(T ?\) b) What value of \(x\) gives the minimum value for \(T ?\)

A mass of \(0.404 \mathrm{~kg}\) is attached to a spring with a spring constant of \(206.9 \mathrm{~N} / \mathrm{m}\). Its oscillation is damped. with damping constant \(b=14.5 \mathrm{~kg} / \mathrm{s}\). What is the frequency of this damped oscillation?

The figure shows a mass \(m_{2}=20.0\) g resting on top of a mass \(m_{1}=20.0 \mathrm{~g}\) which is attached to a spring with \(k=10.0 \mathrm{~N} / \mathrm{m}\) The coefficient of static friction between the two masses is 0.600 . The masses are oscillating with simple harmonic motion on a frictionless surface. What is the maximum amplitude the oscillation can have without \(m_{2}\) slipping off \(m_{1} ?\)

A spring is hanging from the ceiling with a mass attached to it. The mass is pulled downward, causing it to oscillate vertically with simple harmonic motion. Which of the following will increase the frequency of oscillation? a) adding a second, identical spring with one end attached to the mass and the other to the ceiling b) adding a second, identical spring with one end attached to the mass and the other to the floor c) increasing the mass d) adding both springs, as described in (a) and (b)

A mass \(m=1.00 \mathrm{~kg}\) in a spring-mass system with \(k=\) \(1.00 \mathrm{~N} / \mathrm{m}\) is observed to be moving to the right, past its equi. librium position with a speed of \(1.00 \mathrm{~m} / \mathrm{s}\) at time \(t=0 .\) a) Ignoring all damping, determine the equation of motion. b) Suppose the initial conditions are such that at time \(t=0\), the mass is at \(x=0.500 \mathrm{~m}\) and moving to the right with a speed of \(1.00 \mathrm{~m} / \mathrm{s}\). Determine the new equation of motion. Assume the same spring constant and mass.

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