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You have a meter stick that balances at the \(55-\mathrm{cm}\) mark. Is your meter stick homogeneous?

Short Answer

Expert verified
Answer: No, the meter stick is not homogeneous as the balance point (center of mass) is located at the 55 cm mark, which is different from its geometrical center (50 cm mark).

Step by step solution

01

Understand the Problem

First, we need to determine the center of mass of a homogeneous object. In this case, the object is a meter stick. If the meter stick is homogeneous, its center of mass should be located exactly at its geometrical center.
02

Find the Balance Point

The given information states that the balance point (i.e., the center of mass) is at the 55 cm mark on the meter stick.
03

Compare the Balance Point to the Geometrical Center

Since the length of the meter stick is 100 cm, its geometrical center is located at the 50 cm mark. To determine if the meter stick is homogeneous, we need to compare the balance point (center of mass) to the geometrical center.
04

Conclusion

As the balance point is located at the 55 cm mark, which is different from its geometrical center (50 cm mark), we can conclude that the meter stick is not homogeneous.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Homogeneous Object
When we refer to a homogeneous object, we're talking about an object with a uniform composition throughout. This means that the material making up the object is distributed evenly, resulting in no variation in density from one part of the object to another.

For instance, consider a perfectly made metal rod. If it's homogeneous, every segment of the rod — no matter how small — has precisely the same density and weight per unit length. In the classroom, we might use a meter stick as an example. If the meter stick were indeed homogeneous, the material that composes the stick would be spread out in such a way that each centimeter of the stick has the same mass as the next.

In our exercise, the expectation was that if the meter stick was homogeneous, its center of mass should align with its geometrical center, assuming uniform density.
Balance Point
The balance point of an object, often referred to as the center of mass, is a crucial concept in physics. This point represents the location where the mass of an object is considered to be concentrated. For practical purposes, if you were to support the object at its balance point, the object would remain in equilibrium and not tip over.

To find the balance point, various methods can be employed depending on the object's shape and density distribution. With our meter stick example, the balance point is naturally where the stick rests horizontally without tilting, which is at the 55 cm mark as per the information given.

This balance point is a telltale indicator of how the mass is distributed along the stick. If the balance point is not at the center, it implies that there is an uneven distribution of mass — meaning, the object isn't homogeneous.
Geometrical Center
The geometrical center of an object is also known as its centroid. It's the 'average' position of all the points of an object. Imagine folding a shape along every possible axis; the place where it balances perfectly each time is its geometrical center.

For two-dimensional figures like squares or circles, it's quite simple to find this point because of their symmetry. But even in three dimensions, like cubes or spheres, the concept remains intact. A meter stick, being a long, thin rectangle, has its geometrical center at the midway point — at the 50 cm mark, as it's 100 cm long.

The geometrical center assumes an important requirement: that the material of the object is uniformly distributed. However, in real-life applications, finding the true geometrical center may not always indicate the balance point of an object as external factors or material inconsistencies can shift the actual center of mass away from the geometrical center.

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Most popular questions from this chapter

In the absence of any symmetry or other constraints on the forces involved, how many unknown force components can be determined in a situation of static equilibrium in each of the following cases? a) All forces and objects lie in a plane. b) Forces and objects are in three dimensions. c) Forces act in \(n\) spatial dimensions.

An SUV has a height \(h\) and a wheelbase of length b. Its center of mass is midway between the wheels and at a distance \(\alpha h\) above the ground, where \(0<\alpha<1\). The SUV enters a turn at a dangerously high speed, \(v\). The radius of the turn is \(R(R \gg b)\), and the road is flat. The coefficient of static friction between the road and the properly inflated tires is \(\mu_{s}\). After entering the turn, the SUV will either skid out of the turn or begin to tip. a) The SUV will skid out of the turn if the friction force reaches its maximum value, \(F \rightarrow \mu_{\mathrm{s}} N\). Determine the speed, \(v_{\text {skid }},\) for which this will occur. Assume no tipping occurs. b) The torque keeping the SUV from tipping acts on the outside wheel. The highest value this force can have is equal to the entire normal force. Determine the speed, \(v_{\text {tip }}\), at which this will occur. Assume no skidding occurs. c) It is safer if the SUV skids out before it tips. This will occur as long as \(v_{\text {skid }}

A uniform, equilateral triangle of side length \(2.00 \mathrm{~m}\) and weight \(4.00 \cdot 10^{3} \mathrm{~N}\) is placed across a gap. One point is on the north end of the gap, and the opposite side is on the south end. Find the force on each side.

A uniform rectangular bookcase of height \(H\) and width \(W=H / 2\) is to be pushed at a constant velocity across a level floor. The bookcase is pushed horizontally at its top edge, at the distance \(H\) above the floor. What is the maximum value the coefficient of kinetic friction between the bookcase and the floor can have if the bookcase is not to tip over while being pushed?

A 600.0-N bricklayer is \(1.5 \mathrm{~m}\) from one end of a uniform scaffold that is \(7.0 \mathrm{~m}\) long and weighs \(800.0 \mathrm{~N}\). A pile of bricks weighing \(500.0 \mathrm{~N}\) is \(3.0 \mathrm{~m}\) from the same end of the scaffold. If the scaffold is supported at both ends, calculate the force on each end.

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