Question

Assuming that 1 mole $(6.02\cdot {10}^{23}$ molecules) of an ideal gas has a volume of $22.4\mathrm{L}$ at standard temperature and pressure (STP) and that nitrogen, which makes up $80.0\mathrm{\%}$ of the air we breathe, is an ideal gas, how many nitrogen molecules are there in an average $0.500\mathrm{L}$ breath at STP?

Short answer

Answer: Approximately $1.075\cdot {10}^{22}$ nitrogen molecules are in a 0.500 L breath at STP.

Step-by-step solution

Calculate the moles of air in a 0.500 L breath at STP

To determine the moles of air in a 0.500 L breath, we will use the given information that 1 mole of an ideal gas has a volume of 22.4 L at STP. We can set up a proportion as follows: $\frac{1\text{ mole}}{22.4\mathrm{L}}=\frac{n}{0.500\mathrm{L}}$ Where "n" represents the moles of air in the 0.500 L breath.

Solve for "n"

To find the moles of air in the 0.500 L breath, we'll solve for "n" in the proportion: $n=\frac{1\text{ mole}\times 0.500\mathrm{L}}{22.4\mathrm{L}}$ $n=0.02232$ moles

Calculate the moles of nitrogen in the 0.500 L breath

Since nitrogen makes up 80.0% of the air, we can multiply the moles of air by 80.0% to find the moles of nitrogen in the 0.500 L breath: Moles of nitrogen = $0.02232\text{ moles}\times 0.8$ Moles of nitrogen = $0.01786$ moles

Find the number of nitrogen molecules in the 0.500 L breath

To find the number of nitrogen molecules in the breath, we'll multiply the moles of nitrogen by Avogadro's number $\text{Missing or unrecognized delimiter for right}$. molecules per mole): Number of nitrogen molecules = $0.01786\text{ moles}\times 6.02\cdot {10}^{23}$ molecules/mole Number of nitrogen molecules = $1.075\cdot {10}^{22}$ molecules There are approximately $1.075\cdot {10}^{22}$ nitrogen molecules in an average 0.500 L breath at STP.

Key concepts

Avogadro's Number

Avogadro's number is a fundamental constant in chemistry which represents the number of particles, usually atoms or molecules, in one mole of a substance. It is typically denoted as $6.02\times {10}^{23}$. This constant was named after the Italian scientist Amedeo Avogadro.

Understanding Avogadro's number is crucial when dealing with mole concepts in chemistry. It allows chemists to count particles by weighing them. For example, one mole of carbon-12 atoms—a precisely defined number—weighs 12 grams, and because of Avogadro's number, we know that there are exactly $6.02\times {10}^{23}$ carbon-12 atoms in that sample. In our nitrogen molecule problem from the exercise, we used Avogadro’s number to convert the number of moles of nitrogen to the actual number of nitrogen molecules present in a 0.500 L breath at standard temperature and pressure (STP).

Ideal Gas Law

The ideal gas law is an equation that correlates the pressure, volume, temperature, and amount (in moles) of an ideal gas. The formula is represented as PV = nRT, where P is the pressure of the gas, V is the volume it occupies, n is the amount in moles, R is the ideal gas constant, and T is the temperature in Kelvin.

For a given amount of gas at constant temperature and pressure, this law simplifies to the direct proportionality between the volume and the number of moles, V $\propto$ n. This concept is critical to finding the moles of nitrogen in the mentioned problem, where we assumed standard conditions for temperature and pressure. The ideal gas law provides the theoretic backdrop for calculating amounts in everyday life examples, like the volume of a breath.

Standard Temperature and Pressure

Standard temperature and pressure (STP) are conditions used as standard points of reference for expressing the properties of gases. The standard temperature is 0 degrees Celsius (273.15 Kelvin), and standard pressure is one atmosphere (101.325 kPa).

At STP, one mole of an ideal gas occupies a volume of 22.4 liters, which is the basis we used to calculate moles in our exercise. The concept of STP helps standardize measurements so chemists can compare data and results are consistent, regardless of when or where the measurements were made. When we talk about an average 0.500 L breath, considering it is at STP allows us to use the 22.4 L/mole volume as a reference point for calculations.