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What are the air-standard assumptions?

Short Answer

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**Question:** List and briefly explain the air-standard assumptions used to simplify the analysis of internal combustion engines. **Answer:** The air-standard assumptions are as follows: 1. *Working Fluid is an Ideal Gas:* The working fluid (air) is considered an ideal gas, meaning it follows the ideal gas law, which simplifies the thermodynamic analysis of the engine cycle. 2. *Air Standard Cycle is Reversible:* The air-standard cycle assumes all processes are reversible, either adiabatic or isothermal, which helps determine the theoretical maximum efficiency for the engine cycle. In reality, engine cycles are not entirely reversible due to factors like friction and heat losses. 3. *Constant Specific Heat:* The specific heat of air is assumed to be constant throughout the engine cycle. This simplifies calculations and analysis, although specific heat can vary with temperature in real-world conditions. This assumption is considered acceptable for analysis purposes.

Step by step solution

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1. Working Fluid is an Ideal Gas

Under air-standard assumptions, the working fluid in the engine (air) is considered an ideal gas. This means the air's behavior will follow the ideal gas law, which is PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the specific gas constant, and T is the temperature. Considering ideal gas behavior simplifies the thermodynamic analysis of the engine cycle.
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2. Air Standard Cycle is Reversible

The air-standard cycle is assumed to be a reversible process. This means that every operation in the cycle can be reversed, and all processes are adiabatic (no heat transfer) or isothermal (constant temperature). In reality, engine cycles are not completely reversible due to irreversibilities like friction and heat losses, but assuming reversibility helps in understanding the theoretical maximum efficiency for the engine cycle.
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3. Constant Specific Heat

In an air-standard analysis, the specific heat of air is assumed to be constant throughout the entire cycle of the engine. This assumption greatly simplifies the calculations and analysis of the engine cycle. However, the specific heat of air can vary with the temperature in real-world conditions, but this assumption is considered acceptable for the analysis purposes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
Understanding the ideal gas law is crucial for many engineering applications, particularly in thermodynamics, where it helps in analyzing the behavior of gases within various cycles and systems. The ideal gas law is a fundamental equation expressed as \( PV = nRT \), which describes the relationship among pressure (\( P \)), volume (\( V \)), number of moles (\( n \)), the gas constant (\( R \)), and temperature (\( T \)). This equation provides a good approximation of the behavior of many gases under a range of conditions.

To apply the ideal gas law to an air-standard assumption helps simplify complex engines and their cycles into a more approachable format for calculations. By considering air as an ideal gas, it's presumed that the interactions amongst its molecules are negligible and the size of the molecules themselves is insignificant compared to the distance between them. These simplifications make it easier for students to grasp the basic principles without getting lost in the complexities of real gas behavior.
Reversible Process
Imagine a process that could be undone without leaving a trace, a system returning to its original state without any change in the rest of the universe. This is the essence of a reversible process. In thermodynamics, we use this idealized concept to determine the limits of efficiency and to understand the natural progression of energy systems. In a reversible process, such a heat engine cycle experiences no entropy increase; it's a perfect, lossless sequence of steps. This concept is often paired with adiabatic processes, where no heat is transferred, or isothermal processes, where temperature remains constant.

Now, remember that no real process is truly reversible due to natural phenomena such as friction and thermal gradients. But embracing the idea of reversibility sharpens the theoretical target for engineers and students, setting a benchmark for what’s theoretically possible. It propels learners toward a deeper comprehension of energy conservation and the limitations imposed by the second law of thermodynamics.
Specific Heat
Every substance absorbs heat energy in its own unique way. The specific heat is a property of material that tells us how much heat is needed to raise the temperature of a unit mass by one degree Celsius. In formal terms, we define the specific heat capacity, \( c \), as the amount of heat per unit mass required to raise the temperature by one degree Celsius (\( c = \frac{q}{m\Delta T} \) where \( q \) is heat absorbed or released, \( m \) is the mass, and \( \Delta T \) is the temperature change).

For air-standard assumptions, we consider air’s specific heat to be constant. In the real world, however, the specific heat can vary with temperature, particularly at higher temperatures relevant to combustion engines. Despite this, keeping specific heat constant is a useful simplification for basic studies of thermodynamic systems. It allows students to more easily calculate the energy required for heating or cooling processes without having to account for the changing heat absorption properties of a substance due to temperature variations.

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Most popular questions from this chapter

A turbojet is flying with a velocity of \(900 \mathrm{ft} / \mathrm{s}\) at an altitude of \(20,000 \mathrm{ft}\), where the ambient conditions are 7 psia and \(10^{\circ} \mathrm{F}\). The pressure ratio across the compressor is \(13,\) and the temperature at the turbine inlet is 2400 R. Assuming ideal operation for all components and constant specific heats for air at room temperature, determine ( \(a\) ) the pressure at the turbine exit, \((b)\) the velocity of the exhaust gases, and \((c)\) the propulsive efficiency.

Consider the ideal regenerative Brayton cycle. Determine the pressure ratio that maximizes the thermal efficiency of the cycle and compare this value with the pressure ratio that maximizes the cycle net work. For the same maximumto- minimum temperature ratios, explain why the pressure ratio for maximum efficiency is less than the pressure ratio for maximum work.

Somebody claims that at very high pressure ratios, the use of regeneration actually decreases the thermal efficiency of a gas-turbine engine. Is there any truth in this claim? Explain.

In an ideal Brayton cycle, air is compressed from \(100 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\) to \(1 \mathrm{MPa}\), and then heated to \(927^{\circ} \mathrm{C}\) before entering the turbine. Under cold-air-standard conditions, the air temperature at the turbine exit is \((a) 349^{\circ} \mathrm{C}\) (b) \(426^{\circ} \mathrm{C}\) \((c) 622^{\circ} \mathrm{C}\) \((d) 733^{\circ} \mathrm{C}\) \((e) 825^{\circ} \mathrm{C}\)

What is propulsive efficiency? How is it determined?

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