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A \(1000-\mathrm{W}\) iron is left on the ironing board with its base exposed to the air at \(20^{\circ} \mathrm{C}\). If the temperature of the base of the iron is \(150^{\circ} \mathrm{C}\), determine the rate of exergy destruction for this process due to heat transfer, in steady operation.

Short Answer

Expert verified
Answer: R = hA(130) (0.3075)

Step by step solution

01

Convert the given temperatures to Kelvin

To work with temperatures in thermodynamic equations, we need to convert them to the Kelvin scale. To do this, we add 273.15 to the given Celsius temperatures. T0 (air temperature) = 20°C + 273.15 = 293.15 K T (iron base temperature) = 150°C + 273.15 = 423.15 K
02

Calculate the heat transfer rate (Q)

The heat transfer rate (Q) is not provided in the exercise, but we can estimate it using the Newton's law of cooling which states that the rate of heat transfer (Q) is proportional to the temperature difference between the iron base and the surrounding air (ΔT). Therefore, we can write Q as: Q = hAΔT Where h is the heat transfer coefficient, A is the surface area of the iron base, and ΔT is the temperature difference between the iron base and the surrounding air. In this exercise, we don't have enough information to find the exact value of Q. But since we are only interested in the rate of exergy destruction, we can rewrite the formula for the exergy destruction rate (R) in terms of Q: R = hAΔT (1 - T0 / T)
03

Calculate the rate of exergy destruction (R)

Now, using the formula derived in the previous step, we can calculate the rate of exergy destruction (R): R = hAΔT (1 - T0 / T) = hA(423.15 - 293.15) (1 - 293.15 / 423.15) R = hA(130) (1 - 0.6925) = hA(130) (0.3075) We couldn't find the exact value of exergy destruction rate (R) as it depends on h (heat transfer coefficient) and A (surface area). However, the expression for the exergy destruction rate in terms of h and A has been derived using the given temperatures and steady operation assumption. Once we know the values of h and A, we can substitute them into the expression to find the exergy destruction rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics
Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, radiation, and physical properties of matter. The fundamental principles of thermodynamics are expressed in four laws. These laws describe how thermal energy is converted to and from other forms of energy and how it affects matter.

The first law, also known as the law of energy conservation, states that energy cannot be created or destroyed in an isolated system. The second law of thermodynamics is particularly pertinent to our exercise as it introduces the concept of entropy and explains that total entropy can only increase over time in an isolated system, meaning that processes are irreversible. In our problem, exergy destruction is directly tied to the second law, as it is a measure of the irreversibility of the process and the lost potential to do work due to heat transfer.
The Kelvin Temperature Scale
The Kelvin temperature scale is an absolute temperature scale that is a fundamental part of thermodynamics. It starts at absolute zero, the theoretical point where molecular motion ceases. Unlike the Celsius and Fahrenheit scales, where temperatures can be negative, the Kelvin scale sets absolute zero as 0 K, which is equivalent to -273.15°C or -459.67°F.

In thermodynamic calculations, it is essential to use the Kelvin scale to ensure accuracy in mathematical formulations, as seen when converting the temperatures for our exergy destruction rate problem. To convert Celsius to Kelvin, as shown in the solution, you add 273.15 to the Celsius temperature.
Newton's Law of Cooling
Newton's law of cooling is an empirical relationship that describes the rate at which an exposed body changes temperature through radiation. It asserts that the rate of heat loss of a body is proportional to the difference in temperatures between the body and its surroundings. The law makes it easier to calculate heat transfer rates, especially in situations where we know the temperature difference and the heat transfer coefficient.

The importance of Newton's law of cooling in our problem is evident, as it provides a basis for estimating the heat transfer rate (Q) through the relationship Q = hAΔT, connecting the temperature difference and the heat transfer characteristics of the iron's surface and the surrounding air.
Heat Transfer Coefficient
The heat transfer coefficient, h, is a parameter that describes the convective heat transfer properties of a fluid in contact with a solid. It is a measure of the convective heat transfer capability from the solid surface to the fluid and vice versa, which depends on the properties of the fluid, the flow characteristics, and the surface geometry. The higher the coefficient, the more efficient is the heat transfer.

In practical applications, such as calculating the rate of exergy destruction for the iron, the heat transfer coefficient is crucial. The exact rate of exergy destruction can't be determined without the value of h, along with the surface area A. These coefficients are often determined experimentally or by following guidelines provided for similar physical systems and materials.

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Most popular questions from this chapter

Hot exhaust gases leaving an internal combustion engine at \(400^{\circ} \mathrm{C}\) and \(150 \mathrm{kPa}\) at a rate of \(0.8 \mathrm{kg} / \mathrm{s}\) is to be used to produce saturated steam at \(200^{\circ} \mathrm{C}\) in an insulated heat exchanger. Water enters the heat exchanger at the ambient temperature of \(20^{\circ} \mathrm{C},\) and the exhaust gases leave the heat exchanger at \(350^{\circ} \mathrm{C}\). Determine \((a)\) the rate of steam production, \((b)\) the rate of exergy destruction in the heat exchanger, and \((c)\) the second-law efficiency of the heat exchanger.

The radiator of a steam heating system has a volume of \(20 \mathrm{L}\) and is filled with superheated water vapor at \(200 \mathrm{kPa}\) and \(200^{\circ} \mathrm{C}\). At this moment both the inlet and the exit valves to the radiator are closed. After a while it is observed that the temperature of the steam drops to \(80^{\circ} \mathrm{C}\) as a result of heat transfer to the room air, which is at \(21^{\circ} \mathrm{C}\). Assuming the surroundings to be at \(0^{\circ} \mathrm{C}\), determine ( \(a\) ) the amount of heat transfer to the room and \((b)\) the maximum amount of heat that can be supplied to the room if this heat from the radiator is supplied to a heat engine that is driving a heat pump. Assume the heat engine operates between the radiator and the surroundings.

Air enters a compressor at ambient conditions of \(100 \mathrm{kPa}\) and \(20^{\circ} \mathrm{C}\) at a rate of \(4.5 \mathrm{m}^{3} / \mathrm{s}\) with a low velocity, and exits at \(900 \mathrm{kPa}, 60^{\circ} \mathrm{C},\) and \(80 \mathrm{m} / \mathrm{s}\). The compressor is cooled by cooling water that experiences a temperature rise of \(10^{\circ} \mathrm{C}\). The isothermal efficiency of the compressor is 70 percent. Determine \((a)\) the actual and reversible power inputs, \((b)\) the second-law efficiency, and \((c)\) the mass flow rate of the cooling water.

An iron block of unknown mass at \(85^{\circ} \mathrm{C}\) is dropped into an insulated tank that contains \(100 \mathrm{L}\) of water at \(20^{\circ} \mathrm{C}\). At the same time, a paddle wheel driven by a 200 -W motor is activated to stir the water. It is observed that thermal equilibrium is established after 20 min with a final temperature of \(24^{\circ} \mathrm{C} .\) Assuming the surroundings to be at \(20^{\circ} \mathrm{C}\), determine (a) the mass of the iron block and ( \(b\) ) the exergy destroyed during this process. Answers: (a) \(52.0 \mathrm{kg},\) (b) \(375 \mathrm{kJ}\)

Steam is to be condensed on the shell side of a heat exchanger at \(120^{\circ} \mathrm{F}\). Cooling water enters the tubes at \(60^{\circ} \mathrm{F}\) at a rate of \(115.3 \mathrm{lbm} / \mathrm{s}\) and leaves at \(73^{\circ} \mathrm{F}\). Assuming the heat exchanger to be well insulated, determine ( \(a\) ) the rate of heat transfer in the heat exchanger and \((b)\) the rate of exergy destruction in the heat exchanger. Take \(T_{0}=77^{\circ} \mathrm{F}\)

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