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Outdoor air \(\left(c_{p}=1.005 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) is to be preheated by hot exhaust gases in a cross-flow heat exchanger before it enters the furnace. Air enters the heat exchanger at \(101 \mathrm{kPa}\) and \(30^{\circ} \mathrm{C}\) at a rate of \(0.5 \mathrm{m}^{3} / \mathrm{s}\). The combustion gases \(\left(c_{p}=\right.\) \(\left.1.10 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) enter at \(350^{\circ} \mathrm{C}\) at a rate of \(0.85 \mathrm{kg} / \mathrm{s}\) and leave at \(260^{\circ} \mathrm{C}\). Determine the rate of heat transfer to the air and the rate of exergy destruction in the heat exchanger.

Short Answer

Expert verified
Answer: To find the rate of heat transfer to the air (\(\dot{Q}\)), we first calculate the mass flow rate of the air using the ideal gas law. Then, we apply the energy balance equation for the heat exchanger, considering the temperature changes and specific heat capacities of both streams. Finally, to calculate the rate of exergy destruction (\(\dot{E}D_\text{hx}\)), we determine the exergy changes for both air and gas streams and apply the exergy balance equation.

Step by step solution

01

Calculate the mass flow rate of air

Use the ideal gas law to find the mass flow rate of air. The ideal gas law is: \(PV = mRT \Rightarrow m = \frac{PV}{RT}\) Given the air enters at \(101 \,\text{kPa}\) and \(30^\circ\mathrm{C}\), and its flow rate is \(0.5 \,\text{m}^3/\text{s}\): \(P = 101\, \mathrm{kPa} = 101\times10^3\, \mathrm{Pa}\) \(V = 0.5 \, \mathrm{m}^3 / \mathrm{s}\) \(T = 30 + 273.15 = 303.15\, \mathrm{K}\) \(R_\text{air} = 0.287 \, \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}\) (specific gas constant for air) Now, we can find the mass flow rate of air: \(m_\text{air} = \frac{PV}{RT} = \frac{101\times10^3\mathrm{Pa} \times 0.5\, \mathrm{m}^3/\mathrm{s}}{0.287\, \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K} \times 303.15\, \mathrm{K}}\)
02

Calculate the heat transfer rate to the air

Use the energy balance equation for a heat exchanger: \(\dot{Q} = m_\text{air} \cdot c_{p_\text{air}} \cdot \Delta T_\text{air} = m_\text{gas} \cdot c_{p_{\text{gas}}} \cdot \Delta T_\text{gas}\) Solve for the temperature difference of the air: \(\Delta T_\text{air} = \frac{m_\text{gas} \cdot c_{p_{\text{gas}}} \cdot \Delta T_\text{gas}}{m_\text{air} \cdot c_{p_\text{air}}}\) Now, we can find the exit temperature of the air, since we know its inlet temperature is \(30^\circ\mathrm{C}\): \(T_{\text{air},\text{exit}} = T_{\text{air},\text{inlet}} + \Delta T_\text{air}\) Finally, the heat transfer rate to the air is: \(\dot{Q} = m_\text{air} \cdot c_{p_\text{air}} \cdot (T_{\text{air},\text{exit}} - T_{\text{air},\text{inlet}})\)
03

Calculate the rate of exergy destruction

We first need to find the exergy changes for both air and gas streams: Exergy change for air: \(\Delta E_\text{air} = m_\text{air} \cdot c_{p_\text{air}} \cdot (T_{\text{air},\text{exit}} - T_{\text{air},\text{inlet}}) \cdot \left(1-\frac{T_0}{T_{\text{air},\text{exit}}}\right)\) Exergy change for gas: \(\Delta E_\text{gas} = m_\text{gas} \cdot c_{p_\text{gas}} \cdot (T_{\text{gas},\text{inlet}} - T_{\text{gas},\text{exit}}) \cdot \left(1-\frac{T_0}{T_{\text{gas},\text{inlet}}}\right)\) Now we can write the exergy balance equation for the heat exchanger: \(\dot{E}D_\text{hx} = \Delta E_\text{gas} - \Delta E_\text{air}\) Plug in the calculated expressions for \(\Delta E_\text{air}\) and \(\Delta E_\text{gas}\) to find the rate of exergy destruction in the heat exchanger: \(\dot{E}D_\text{hx} = m_\text{gas} \cdot c_{p_\text{gas}} \cdot (T_{\text{gas},\text{inlet}} - T_{\text{gas},\text{exit}}) \cdot \left(1-\frac{T_0}{T_{\text{gas},\text{inlet}}}\right) - m_\text{air} \cdot c_{p_\text{air}} \cdot (T_{\text{air},\text{exit}} - T_{\text{air},\text{inlet}}) \cdot \left(1-\frac{T_0}{T_{\text{air},\text{exit}}}\right)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-Flow Heat Exchanger
A cross-flow heat exchanger is a device where two fluids move perpendicular to each other as they transfer heat. In this type of heat exchanger, one fluid usually moves horizontally and the other vertically, promoting efficient heat transfer due to the crossing flows and increased turbulence. They are extensively used in various applications, including air conditioning systems, power plants, and automotive radiators. Understanding how heat is transferred in a cross-flow heat exchanger requires consideration of the specific heat capacities of the fluids involved, the mass flow rates, and the temperature differences between the inlet and outlet streams.
Mass Flow Rate Calculation
The mass flow rate is a measure of the amount of mass flowing through a given cross-section per unit time and is crucial for the analysis of any heat exchanger. To calculate the mass flow rate of a gas, we often employ the ideal gas law, which relates the volume, pressure, and temperature of an ideal gas with its mass. Given air density can be affected by both temperature and pressure, the ideal gas law allows us to deduce the mass of the air from its flow rate in volume per time, using the specific gas constant for air. This step is fundamental as the mass flow rate directly influences the rate of heat transfer in a heat exchanger.

In educational exercises, these calculations offer students practical understanding of how thermodynamic principles apply to real-world engineering problems.
Ideal Gas Law
The ideal gas law is a well-known equation in thermodynamics, represented by the formula \(PV = nRT\), where \(P\) is the pressure, \(V\) is the volume, \(n\) is the number of moles, \(R\) is the ideal gas constant, and \(T\) is the temperature in Kelvin. For engineering applications, this formula is often rearranged to find the mass \(m\) of the gas: \(PV = mRT\), where \(R\) in this context is the specific gas constant for the gas in question, and \(m\) is the mass of the gas. Constantly we use this equation to connect the physical properties of a gas, enabling us to calculate the mass flow rate, as seen in heat exchanger problems. It's important for students to grasp this concept to solve practical questions regarding gas-related processes.
Energy Balance Equation
The energy balance equation is at the heart of thermodynamics and heat transfer. It states that the rate of heat transfer into a system must equal the rate of heat transfer out of the system, plus any heat generation within the system, minus any heat losses, in steady-state conditions. This principle ensures energy conservation within the system being evaluated.

In the context of a heat exchanger, such as the cross-flow type, the energy balance equation is used to equate the energy entering and leaving with the heat transfer rates of the respective fluids. By evaluating the mass flow rate and specific heat of each fluid alongside their temperature changes, we can determine the total heat transfer rate. This concept is critical for students as it provides the link between theoretical thermodynamics and applied heat exchange processes.
Exergy Destruction Rate
Exergy destruction rate is a measure of irreversibility within a system, a crucial concept in the second law of thermodynamics. It represents the loss of work potential due to energy conversion processes and inherent inefficiencies. In heat exchangers, exergy destruction is caused by the mixing of streams at different temperatures, resulting in entropy generation. Calculating the exergy destruction rate involves determining the changes in exergy of the fluid streams, considering the environmental reference temperature, and utilizing the energy balance for exergy.

This calculation helps identify areas where a heat exchanger's performance can be improved. For students, understanding the exergy destruction rate not only enhances their grasp of energy efficiency and sustainability but also provides valuable insights into the design and operation of thermal systems.

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Most popular questions from this chapter

A steam turbine is equipped to bleed 6 percent of the inlet steam for feedwater heating. It is operated with 500 psia and \(600^{\circ} \mathrm{F}\) steam at the inlet, a bleed pressure of 100 psia, and an exhaust pressure of 5 psia. The turbine efficiency between the inlet and bleed point is 97 percent, and the efficiency between the bleed point and exhaust is 95 percent. Calculate this turbine's second-law efficiency. Take \(T_{0}=77^{\circ} \mathrm{F}\).

Steam enters an adiabatic turbine at \(6 \mathrm{MPa}, 600^{\circ} \mathrm{C}\) and \(80 \mathrm{m} / \mathrm{s}\) and leaves at \(50 \mathrm{kPa}, 100^{\circ} \mathrm{C},\) and \(140 \mathrm{m} / \mathrm{s}\). If the power output of the turbine is \(5 \mathrm{MW}\), determine \((a)\) the reversible power output and ( \(b\) ) the second-law efficiency of the turbine. Assume the surroundings to be at \(25^{\circ} \mathrm{C}\).

Argon gas enters an adiabatic compressor at \(120 \mathrm{kPa}\) and \(30^{\circ} \mathrm{C}\) with a velocity of \(20 \mathrm{m} / \mathrm{s}\) and exits at \(1.2 \mathrm{MPa}\) \(530^{\circ} \mathrm{C},\) and \(80 \mathrm{m} / \mathrm{s}\). The inlet area of the compressor is \(130 \mathrm{cm}^{2} .\) Assuming the surroundings to be at \(25^{\circ} \mathrm{C}\), determine the reversible power input and exergy destroyed.

Obtain the following information about a power plant that is closest to your town: the net power output; the type and amount of fuel used; the power consumed by the pumps, fans, and other auxiliary equipment; stack gas losses; temperatures at several locations; and the rate of heat rejection at the condenser. Using these and other relevant data, determine the rate of irreversibility in that power plant.

Consider a 20 -L evacuated rigid bottle that is surrounded by the atmosphere at \(100 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\). A valve at the neck of the bottle is now opened and the atmospheric air is allowed to flow into the bottle. The air trapped in the bottle eventually reaches thermal equilibrium with the atmosphere as a result of heat transfer through the wall of the bottle. The valve remains open during the process so that the trapped air also reaches mechanical equilibrium with the atmosphere. Determine the net heat transfer through the wall of the bottle and the exergy destroyed during this filling process.

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