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(a) Water flows through a shower head steadily at a rate of \(10 \mathrm{L} / \mathrm{min}\). An electric resistance heater placed in the water pipe heats the water from 16 to \(43^{\circ} \mathrm{C}\). Taking the density of water to be \(1 \mathrm{kg} / \mathrm{L},\) determine the electric power input to the heater, in \(\mathrm{kW}\), and the rate of entropy generation during this process, in \(\mathrm{kW} / \mathrm{K}\). (b) In an effort to conserve energy, it is proposed to pass the drained warm water at a temperature of \(39^{\circ} \mathrm{C}\) through a heat exchanger to preheat the incoming cold water. If the heat exchanger has an effectiveness of 0.50 (that is, it recovers only half of the energy that can possibly be transferred from the drained water to incoming cold water), determine the electric power input required in this case and the reduction in the rate of entropy generation in the resistance heating section.

Short Answer

Expert verified
How do these values change when a heat exchanger is introduced? Answer: The electric power input to the heater is 18.81 kW, and the rate of entropy generation is 0.0195 kW/K. When a heat exchanger is introduced, the electric power input reduces to 9.4 kW, and the rate of entropy generation decreases by 0.00975 kW/K.

Step by step solution

01

Calculate the mass flow rate of the water

Since water flows at a rate of 10 L/min and the density of water is given as 1 kg/L, we can determine the mass flow rate as follows: Mass flow rate = Flow rate × Density= 10 L/min × 1 kg/L = 10 kg/min
02

Calculate the energy required to heat the water

We will use the specific heat capacity formula to find the energy required to heat the water: Q = m × c × ΔT where Q is the energy required, m is the mass of water, c is the specific heat capacity of water (4.18 kJ/kg·K), and ΔT is the temperature difference. We can substitute the values: ΔT = 43°C - 16°C = 27°C Q = 10 kg/min × 4.18 kJ/kg·K × 27°C = 1128.6 kJ/min
03

Calculate the electric power input

To calculate the electric power input, we will use the formula Power (P) = Energy (Q) / Time (t) P = 1128.6 kJ/min ÷ 60 s/min = 18.81 kW
04

Calculate the rate of entropy generation

The rate of entropy generation can be calculated as follows: Rate of entropy generation = m × c × ln(T2 / T1)/T Entropy rate = 10 kg/min × 4.18 kJ/kg·K × ln((43+273)/(16+273)) / (43-16) Entropy rate = (1/60)×10 kg/min × 4.18 kJ/kg·K × ln((316)/(289)) / 27 = 0.0195 kW/K
05

Using the heat exchanger

When introducing a heat exchanger with an effectiveness of 0.50, the reduction in energy provided to the heater will be: Q_reduced = 0.5 × Q Q_reduced = 0.5 × 1128.6 kJ/min = 564.3 kJ/min
06

Calculate the new electric power input

The new electric power input will be: P_new = 564.3 kJ/min ÷ 60 s/min = 9.4 kW
07

Calculate the reduction in the rate of entropy generation

The reduction in entropy rate will be half the original rate: Entropy rate reduction = 0.5 × Entropy rate Entropy rate reduction = 0.5 × 0.0195 kW/K = 0.00975 kW/K The electric power input to the heater is 18.81 kW, and the rate of entropy generation is 0.0195 kW/K. With the heat exchanger installed, the electric power input reduces to 9.4 kW, and the rate of entropy generation decreases by 0.00975 kW/K.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Flow Rate
Understanding the mass flow rate is crucial when examining processes involving fluid flow, such as heating water in a shower system. It quantifies the amount of mass passing through a given surface per unit time. Commonly expressed in kilograms per second (kg/s), mass flow rate is vital for calculating the energy required to heat a fluid and, subsequently, the heater's power requirement.

According to the exercise, to determine the mass flow rate of water, we multiply the flow rate (in liters per minute) by the density of water (in kilograms per liter). Since the density is 1 kg/L, the mass flow rate directly corresponds to the flow rate in liters, resulting in a mass flow rate of 10 kg/min. This value serves as the foundation for subsequent calculations involving the heating process of water.
Specific Heat Capacity
The concept of specific heat capacity is fundamental in thermodynamics. It represents the amount of energy required to raise the temperature of one kilogram of a substance by one degree Celsius (or Kelvin). The specific heat capacity of water, typically 4.18 kJ/kg·K, allows us to calculate the amount of energy required to heat a specific quantity of water.

To calculate the energy (Q) needed to heat the water from one temperature to another, multiply the mass (m), specific heat capacity (c), and temperature change (ΔT). In the exercise, the specific heat capacity plays a pivotal role in determining both the electric power input to the heater and the rate of entropy generation, as it relates energy to the temperature change in water.
Entropy Generation
The term entropy generation is intertwined with the second law of thermodynamics and signifies the degree of energy dispersion or irreversibility in a process. It's a measure of how much useful energy is lost in the form of unrecoverable heat. In heating applications, higher entropy generation typically indicates less efficiency since more energy is unusable for work.

In the exercise, the rate of entropy generation during the water heating process demonstrates the system's inefficiency. It's calculated by multiplying the mass flow rate, specific heat capacity, and the natural logarithm of the temperature ratio, all divided by the average temperature over which the heating occurs. This metric is significant in identifying opportunities for energy conservation, such as using a heat exchanger to preheat incoming water.
Heat Exchanger Effectiveness
The heat exchanger effectiveness is a measure of how well the heat exchanger performs relative to its theoretical maximum performance. An effectiveness of 1 implies that the heat exchanger transfers all the available thermal energy from the hot side to the cold one, which is often not achievable due to practical limitations like imperfect thermal contact or finite element sizes.

In our exercise, a heat exchanger with an effectiveness of 0.50 means it can only recover half the energy that could be transferred. When integrating such a heat exchanger into the system, we see a reduction in the required electric power input for heating the water. Effectiveness is a key design parameter that affects not only energy efficiency but also the size and cost of a heat exchanger. The usage of this concept helps students understand the impact of design choices and system efficiency on energy usage and conservation.

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Most popular questions from this chapter

Compressed air is one of the key utilities in manufacturing facilities, and the total installed power of compressed-air systems in the United States is estimated to be about 20 million horsepower. Assuming the compressors to operate at full load during one-third of the time on average and the average motor efficiency to be 90 percent, determine how much energy and money will be saved per year if the energy consumed by compressors is reduced by 5 percent as a result of implementing some conservation measures. Take the unit cost of electricity to be \(\$ 0.11 / \mathrm{kWh}\).

An ordinary egg can be approximated as a \(5.5-\mathrm{cm}-\) diameter sphere. The egg is initially at a uniform temperature of \(8^{\circ} \mathrm{C}\) and is dropped into boiling water at \(97^{\circ} \mathrm{C}\). Taking the properties of the egg to be \(\rho=1020 \mathrm{kg} / \mathrm{m}^{3}\) and \(c_{p}=3.32 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C},\) determine \((a)\) how much heat is transferred to the egg by the time the average temperature of the egg rises to \(70^{\circ} \mathrm{C}\) and \((b)\) the amount of entropy generation associated with this heat transfer process.

Liquid water at \(200 \mathrm{kPa}\) and \(15^{\circ} \mathrm{C}\) is heated in a chamber by mixing it with superheated steam at \(200 \mathrm{kPa}\) and \(150^{\circ} \mathrm{C} .\) Liquid water enters the mixing chamber at a rate of \(4.3 \mathrm{kg} / \mathrm{s},\) and the chamber is estimated to lose heat to the surrounding air at \(20^{\circ} \mathrm{C}\) at a rate of \(1200 \mathrm{kJ} / \mathrm{min}\). If the mixture leaves the mixing chamber at \(200 \mathrm{kPa}\) and \(80^{\circ} \mathrm{C}\) determine \((a)\) the mass flow rate of the superheated steam and \((b)\) the rate of entropy generation during this mixing process.

Consider a \(50-\mathrm{L}\) evacuated rigid bottle that is surrounded by the atmosphere at \(95 \mathrm{kPa}\) and \(27^{\circ} \mathrm{C}\). A valve at the neck of the bottle is now opened and the atmospheric air is allowed to flow into the bottle. The air trapped in the bottle eventually reaches thermal equilibrium with the atmosphere as a result of heat transfer through the wall of the bottle. The valve remains open during the process so that the trapped air also reaches mechanical equilibrium with the atmosphere. Determine the net heat transfer through the wall of the bottle and the entropy generation during this filling process.

Reconsider Prob. \(7-194 .\) Using EES (or other) software, determine the isentropic efficiencies for the compressor and turbine. Then use EES to study how varying the compressor efficiency over the range 0.6 to 0.8 and the turbine efficiency over the range 0.7 to 0.95 affect the net work for the cycle and the entropy generated for the process. Plot the net work as a function of the compressor efficiency for turbine efficiencies of \(0.7,0.8,\) and \(0.9,\) and discuss your results.

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