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Reconsider Prob. \(7-194 .\) Using EES (or other) software, determine the isentropic efficiencies for the compressor and turbine. Then use EES to study how varying the compressor efficiency over the range 0.6 to 0.8 and the turbine efficiency over the range 0.7 to 0.95 affect the net work for the cycle and the entropy generated for the process. Plot the net work as a function of the compressor efficiency for turbine efficiencies of \(0.7,0.8,\) and \(0.9,\) and discuss your results.

Short Answer

Expert verified
Answer: We are expected to analyze the isentropic efficiencies of the compressor and turbine, the effect of varying these efficiencies on the net work and entropy generation, and create a plot of net work as a function of the compressor efficiency for different turbine efficiencies (0.7, 0.8, and 0.9).

Step by step solution

01

Determine the isentropic efficiencies of the compressor and the turbine

To calculate the isentropic efficiencies of the compressor and turbine, we need to use engineering software like EES. First, we input the given parameters and the equations governing the system, including the energy and mass balance equations. Then, we solve those equations and obtain the isentropic efficiencies of the compressor and turbine, as well as the net work and entropy generated for the process. This will give us the baseline values for the further analysis.
02

Study the effect of varying compressor and turbine efficiencies on net work and entropy generation

Now that we have the isentropic efficiencies of the compressor and the turbine, we can proceed with studying the effect of varying these efficiencies on the net work and entropy generation. We should create a loop in the EES software that increments the compressor efficiency from 0.6 to 0.8 and the turbine efficiency from 0.7 to 0.95. Inside the loop, we will calculate the net work and entropy generation for each combination of compressor and turbine efficiencies.
03

Plot the net work as a function of compressor efficiency for different turbine efficiencies

Using the data obtained from Step 2, we can create a plot of the net work as a function of the compressor efficiency for different turbine efficiencies (0.7, 0.8, and 0.9). The plot will help us visualize the relationships among these parameters and make conclusions based on those relationships.
04

Analyze and discuss the results obtained

Upon obtaining the isentropic efficiencies of the compressor and turbine, and studying the effect of varying their efficiencies on net work and entropy generation, we can now analyze the results. Typically, we can expect that increasing the efficiencies of the compressor and turbine will result in an increase in the net work and a decrease in the entropy generated. Also, from the plot, we can make specific observations regarding how the net work changes with respect to the compressor efficiency for different turbine efficiencies. We should discuss these results and their implications for the performance of the cycle, as well as suggestions for possible improvements and optimizations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Cycle Analysis
Understanding a thermodynamic cycle requires analyzing the processes that the working fluid undergoes from one state to another and back to the initial state. This analysis includes evaluating parameters like temperature, pressure, and volume at different stages. For instance, an idealized cycle like the Rankine or Brayton cycle portrays the theoretical performance of steam and gas turbine power plants, respectively.

During the cycle analysis, one of the key focus points is to assess the performance of the cycle's major components, such as compressors, turbines, and heat exchangers, under various operating conditions. This evaluation can help determine the cycle's efficiency and identify areas for improvement. By doing so, one can optimize the system for better performance and output.
Compressor and Turbine Performance
Compressors and turbines serve pivotal roles in many thermodynamic cycles, dictating the overall efficiency and effectiveness of the system. The performance of these components is often measured in terms of isentropic efficiency. This efficiency is the ratio of the actual work to the ideal work as defined by an isentropic process, where no entropy is generated.

Higher isentropic efficiencies indicate that the components are performing closer to their ideal, lossless counterparts. Thus, achieving high isentropic efficiencies in compressors and turbines is crucial in reducing fuel consumption and operational costs. Real-world factors such as friction, heat losses, and irreversible processes inevitably affect the efficiencies, which is why ongoing monitoring and adjustment are necessary to maintain an energy-efficient operation.
EES Software Usage
Engineering Equation Solver (EES) is a versatile software tool that is widely used for solving complex problems in thermodynamics. It provides a platform to input equations that represent the physical model and solve them numerically. EES is particularly useful in cycle analysis because it can handle the simultaneous equations that describe energy and mass balances.

By using functions to iterate over ranges of variables (such as compressor and turbine isentropic efficiencies), EES allows for the analysis of how changes in these variables impact cycle performance. Additionally, it offers plotting capabilities which simplify the visualization of relationships between parameters, aiding in interpretation and decision-making.
Entropy Generation
Entropy generation is a measure of the irreversibility present within a thermodynamic process. It is a key concept when it comes to efficiency analysis, as no real-world process is entirely reversible. The Second Law of Thermodynamics dictates that the entropy of the universe increases over time, and this principle manifests in the increase in entropy during energy transformations.

Minimizing entropy generation in a cycle is critical for maximizing efficiency. As entropy generation decreases, the process moves closer to being isentropic, which is a reversible adiabatic process. The efficiency of the components, like compressors and turbines, plays a direct role in the amount of entropy generated. Thus, understanding and controlling entropy generation is an essential part of optimizing thermodynamic cycle performance.
Net Work Output
Net work output is the total usable work produced by a thermodynamic cycle, subtracting the work input required by components like compressors. It's an essential metric for evaluating the performance of power systems. A high net work output indicates a more effective cycle, capable of generating more power for the same amount of input energy.

The goal of optimizing the performance of the compressor and turbine through improved isentropic efficiencies directly relates to increasing net work output. In an exercise where students explore the relationship between efficiencies and net work using EES, the result is a practical understanding of how engineering designs and operating decisions influence power production. This hands-on approach can facilitate a deeper grasp of thermodynamic principles.

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Most popular questions from this chapter

Water at 20 psia and \(50^{\circ} \mathrm{F}\) enters a mixing chamber at a rate of 300 lbm/min where it is mixed steadily with steam entering at 20 psia and \(240^{\circ} \mathrm{F}\). The mixture leaves the chamber at 20 psia and \(130^{\circ} \mathrm{F}\), and heat is lost to the surrounding air at \(70^{\circ} \mathrm{F}\) at a rate of \(180 \mathrm{Btu} / \mathrm{min}\). Neglecting the changes in kinetic and potential energies, determine the rate of entropy generation during this process?

Carbon-steel balls \(\left(\rho=7833 \quad \mathrm{kg} / \mathrm{m}^{3} \text { and } c_{p}=\right.\) \(\left.0.465 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right) 8 \mathrm{mm}\) in diameter are annealed by heating them first to \(900^{\circ} \mathrm{C}\) in a furnace and then allowing them to cool slowly to \(100^{\circ} \mathrm{C}\) in ambient air at \(35^{\circ} \mathrm{C}\). If 2500 balls are to be annealed per hour, determine \((a)\) the rate of heat transfer from the balls to the air and ( \(b\) ) the rate of entropy generation due to heat loss from the balls to the air.

Can saturated water vapor at \(200 \mathrm{kPa}\) be condensed to a saturated liquid in an isobaric, closed system process while only exchanging heat with an isothermal energy reservoir at \(90^{\circ} \mathrm{C} ?\) (Hint: Determine the entropy generation.)

A constant volume tank filled with 2 kg of air rejects heat to a heat reservoir at \(300 \mathrm{K}\). During the process the temperature of the air in the tank decreases to the reservoir temperature. Determine the expressions for the entropy changes for the tank and reservoir and the total entropy change or entropy generated of this isolated system. Plot these entropy changes as functions of the initial temperature of the air. Comment on your results. Assume constant specific heats for air at \(300 \mathrm{K}\).

\(7-245\) Helium gas is compressed steadily from \(90 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\) to \(800 \mathrm{kPa}\) at a rate of \(2 \mathrm{kg} / \mathrm{min}\) by an adiabatic compressor. If the compressor consumes \(80 \mathrm{kW}\) of power while operating, the isentropic efficiency of this compressor is \((a) 54.0 \%\) \((b) 80.5 \%\) \((c) 75.8 \%\) \((d) 90.1 \%\) \((e) 100 \%\)

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