Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A piston-cylinder device initially contains \(15 \mathrm{ft}^{3}\) of helium gas at 25 psia and \(70^{\circ} \mathrm{F}\). Helium is now compressed in a polytropic process \(\left(P V^{n}=\text { constant }\right)\) to 70 psia and \(300^{\circ} \mathrm{F}\). Determine \((a)\) the entropy change of helium, \((b)\) the entropy change of the surroundings, and (c) whether this process is reversible, irreversible, or impossible. Assume the surroundings are at \(70^{\circ} \mathrm{F}\).

Short Answer

Expert verified
Question: Determine if the given polytropic process of helium gas inside a piston-cylinder device is reversible, irreversible, or impossible based on the entropy change. The initial and final states are provided, and the process follows a polytropic equation \(PV^n=\text{constant}\). Solution: After converting the temperatures to the absolute scale (Rankine), applying the ideal gas law to find the mass of helium, calculating the polytropic exponent n, and finding the entropy changes of the gas and surroundings, we determine the total entropy change. Based on this value, we can conclude if the process is reversible (total entropy change = 0), irreversible (total entropy change > 0), or impossible (total entropy change < 0).

Step by step solution

01

Converting temperature to absolute temperature scale

The first step is to convert the given initial and final temperatures in Fahrenheit to the absolute temperature scale (Rankine): Initial Temperature \(T_1 = 70^\circ \mathrm{F} + 459.67 = 529.67\,\mathrm{R}\) Final Temperature \(T_2 = 300^\circ \mathrm{F} + 459.67 = 759.67\,\mathrm{R}\)
02

Applying the ideal gas law

Now we will apply the ideal gas law, \(PV = mRT\), to find the mass of the helium gas: \(P_1 V_1 = m R T_1\) where, \(P_1 = 25\,\text{psia}\), \(V_1 = 15\,\text{ft}^3\), \(R = 1545/({29\text{lb}_m}/{\text{lb}_m\text{R}})\) is the specific gas constant for helium, and \(T_1 = 529.67\,\mathrm{R}\). Solving the equation for \(m\), we have the mass of the helium gas.
03

Determining the polytropic exponent n

Using the polytropic process equation, \(P_1 V_1^n = P_2 V_2^n\), we can find the exponent n. Given \(P_2 = 70\, \text{psia}\) and \(T_2 = 759.67\,\mathrm{R}\), we can find \(V_2\) using the ideal gas law: \(P_2 V_2 = m R T_2\) Solving for \(V_2\) and plugging the values in the polytropic process equation, we can find the value of n.
04

Finding the entropy change of the helium gas

The entropy change for an ideal gas undergoing a polytropic process is given by: \(\Delta s_{\text{gas}} = m C_v \ln\frac{T_2}{T_1} - n m R \ln\frac{P_2}{P_1}\) where \(C_v\) is the specific heat at constant volume for helium. Using the values of \(T_1\), \(T_2\), \(P_1\), \(P_2\), and \(m\) calculated before and n, we can calculate the entropy change of the gas.
05

Finding the entropy change of the surroundings

The heat transfer in an internally reversible polytropic process is: \(q_{rev}=-\frac{n}{n-1}mR(T_1-T_2)\) Now we can find the entropy change of the surroundings by considering the transfer of heat into it: \(\Delta s_{\text{surroundings}} = \frac{q_{rev}}{T_{\text{surroundings}}}\) Given \(T_{\text{surroundings}}= 70^\circ \mathrm{F} + 459.67 = 529.67\,\mathrm{R}\) and using the calculated value of \(q_{rev}\), we can find the entropy change of the surroundings.
06

Determine whether the process is reversible, irreversible, or impossible

Now we can determine the nature of the process based on the total entropy change: \(\Delta s_{\text{total}} = \Delta s_{\text{gas}} + \Delta s_{\text{surroundings}}\) If \(\Delta s_{\text{total}} = 0\), then the process is reversible. If \(\Delta s_{\text{total}} > 0\), then the process is irreversible. If \(\Delta s_{\text{total}} < 0\), then the process is impossible. Using the calculated values of \(\Delta s_{\text{gas}}\) and \(\Delta s_{\text{surroundings}}\), we can determine the nature of the process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piston-Cylinder Device
The piston-cylinder device is a fundamental component often used to illustrate thermodynamic processes in physics and engineering. This apparatus consists of a cylinder that is sealed by a moveable piston. Inside, it can contain various gases or fluids. The piston is designed to move freely within the cylinder, allowing for changes in volume as force is applied or as the internal state of the gas alters. This change in volume directly impacts parameters such as pressure and temperature within the gas, based on the principles of thermodynamics.

Understanding how the piston-cylinder operates is crucial when analyzing thermodynamic cycles, such as those found in engines or refrigeration systems. Processes like expansion, compression, heat transfer, and work done can all be modeled using this device. In the example problem provided, helium gas is compressed, which would mean that the piston is pushing down, decreasing the volume and increasing pressure and temperature, leading to questions about entropy change during this polytropic process.
Polytropic Process
A polytropic process is a thermodynamic process that follows the relation \(PV^n = \text{constant}\), where \(P\) represents pressure, \(V\) is the volume, and \(n\) is the polytropic exponent. Depending on the value of \(n\), this process can represent a variety of different physical scenarios. For example, when \(n=0\), it corresponds to an isobaric process (constant pressure), \(n=1\) to an isothermal process (constant temperature), and \(n=\infty\) to an isochoric process (constant volume). Understanding the characteristics of a polytropic process can help predict how a system behaves when pressure, volume, and temperature change.

In the context of the exercise, the helium gas undergoing a polytropic compression means that the relation between the initial and final states can be used to find the polytropic exponent \(n\). This is important, as it influences how we understand the system's behavior and calculate the entropy change. The value of \(n\) determines how energy is transferred within the system, and considering entropy, which is a measure of disorder or randomness, we can determine how ordered or disordered the system becomes during this specific process.
Ideal Gas Law
The ideal gas law, represented as \(PV = mRT\), is pivotal in understanding the behavior of gases under varying conditions of pressure (\(P\)), volume (\(V\)), and temperature (\(T\)). Here, \(m\) denotes the gas mass, and \(R\) is the specific gas constant unique to each gas. The ideal gas law combines Boyle's Law, Charles's Law, and Avogadro's Law and assumes that the molecules of the gas are point particles that interact with each other only through elastic collisions.

The law is extremely useful when dealing with problems like the exercise provided, as it allows us to compute the mass of the gas when the pressure, volume, and temperature are known. When combined with the concept of a polytropic process, the ideal gas law provides a foundation for calculating changes in the system, such as entropy change. However, it is crucial to note that the ideal gas law is an approximation. It assumes no intermolecular forces and that the volume occupied by the gas molecules themselves is negligible, which holds true under normal conditions but not for all gases at all temperatures and pressures.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Heat is lost through a plane wall steadily at a rate of \(600 \mathrm{W}\). If the inner and outer surface temperatures of the wall are \(20^{\circ} \mathrm{C}\) and \(5^{\circ} \mathrm{C},\) respectively, the rate of entropy generation within the wall is \((a) 0.11 \mathrm{W} / \mathrm{K}\) \((b) 4.21 \mathrm{W} / \mathrm{K}\) \((c) 2.10 \mathrm{W} / \mathrm{K}\) \((d) 42.1 \mathrm{W} / \mathrm{K}\) \((e) 90.0 \mathrm{W} / \mathrm{K}\)

\(1-1 \mathrm{bm}\) of air at 10 psia and \(70^{\circ} \mathrm{F}\) is contained in a piston-cylinder device. Next, the air is compressed reversibly to 100 psia while the temperature is maintained constant. Determine the total amount of heat transferred to the air during this compression.

A heat engine whose thermal efficiency is 35 percent uses a hot reservoir at \(1100 \mathrm{R}\) and a cold reservoir at \(550 \mathrm{R}\) Calculate the entropy change of the two reservoirs when 1 Btu of heat is transferred from the hot reservoir to the engine. Does this engine satisfy the increase of entropy principle? If the thermal efficiency of the heat engine is increased to 60 percent, will the increase of entropy principle still be satisfied?

In order to cool 1 -ton of water at \(20^{\circ} \mathrm{C}\) in an insulated tank, a person pours \(80 \mathrm{kg}\) of ice at \(-5^{\circ} \mathrm{C}\) into the water. Determine ( \(a\) ) the final equilibrium temperature in the \(\operatorname{tank}\) and \((b)\) the entropy generation during this process. The melting temperature and the heat of fusion of ice at atmospheric pressure are \(0^{\circ} \mathrm{C}\) and \(333.7 \mathrm{kJ} / \mathrm{kg}\).

A hot-water stream at \(70^{\circ} \mathrm{C}\) enters an adiabatic mixing chamber with a mass flow rate of \(3.6 \mathrm{kg} / \mathrm{s}\), where it is mixed with a stream of cold water at \(20^{\circ} \mathrm{C}\). If the mixture leaves the chamber at \(42^{\circ} \mathrm{C}\), determine ( \(a\) ) the mass flow rate of the cold water and \((b)\) the rate of entropy generation during this adiabatic mixing process. Assume all the streams are at a pressure of \(200 \mathrm{kPa}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free