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An inventor claims to have devised a cyclical engine for use in space vehicles that operates with a nuclear-fuel-generated energy source whose temperature is \(920 \mathrm{R}\) and a sink at \(490 \mathrm{R}\) that radiates waste heat to deep space. He also claims that this engine produces 4.5 hp while rejecting heat at a rate of \(15,000 \mathrm{Btu} / \mathrm{h}\). Is this claim valid?

Short Answer

Expert verified
Answer: Yes, the claim is valid as the claimed engine efficiency (0.4327) is less than the maximum possible efficiency (0.4674).

Step by step solution

01

Convert Given Power Output to BTU/h

To compare the given efficiency and maximum efficiency, we should have both values in the same unit. Convert the given power output (4.5 hp) to BTU/h using the conversion factor 1 hp = 2544.43 BTU/h. 4.5 hp = 4.5 * 2544.43 = 11449.935 \mathrm{Btu}/ \mathrm{h}
02

Calculate the Heat Input

To calculate the heat input, add the heat rejected (15000 BTU/h) to the power output (11449.935 BTU/h). Heat input = Power output + Heat rejected Heat input = 11449.935 \mathrm{Btu} / \mathrm{h} + 15000 \mathrm{Btu} / \mathrm{h} = 26449.935 \mathrm{Btu} / \mathrm{h}
03

Calculate the Claimed Engine Efficiency

Calculate the claimed engine efficiency using the formula: Claimed Engine Efficiency = Power output / Heat input Claimed Engine Efficiency = 11449.935 \mathrm{Btu}/\mathrm{h} / 26449.935 \mathrm{Btu}/\mathrm{h} = 0.4327
04

Calculate the Carnot Efficiency

Calculate the maximum possible efficiency using the Carnot efficiency formula: Carnot Efficiency = 1 - (Temperature of sink / Temperature of source) Carnot Efficiency = 1 - (490 \mathrm{R} / 920 \mathrm{R}) = 1 - 0.5326 = 0.4674
05

Compare Claimed Engine Efficiency with Carnot Efficiency

Compare the claimed efficiency with the maximum possible efficiency to determine if the claim is valid. If the claimed engine efficiency is less than or equal to the maximum possible efficiency, the claim is valid. Otherwise, it is not valid. In this case, the claimed engine efficiency (0.4327) is less than the maximum possible efficiency (0.4674). So, the claim is valid.

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Most popular questions from this chapter

An inventor claims to have developed a refrigerator that maintains the refrigerated space at \(40^{\circ} \mathrm{F}\) while operating in a room where the temperature is \(85^{\circ} \mathrm{F}\) and that has a COP of \(13.5 .\) Is this claim reasonable?

A heat engine operates between two reservoirs at 800 and \(20^{\circ} \mathrm{C} .\) One-half of the work output of the heat engine is used to drive a Carnot heat pump that removes heat from the cold surroundings at \(2^{\circ} \mathrm{C}\) and transfers it to a house maintained at \(22^{\circ} \mathrm{C}\). If the house is losing heat at a rate of \(62,000 \mathrm{kJ} / \mathrm{h}\) determine the minimum rate of heat supply to the heat engine required to keep the house at \(22^{\circ} \mathrm{C}\).

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Consider a Carnot refrigerator and a Carnot heat pump operating between the same two thermal energy reservoirs. If the COP of the refrigerator is \(3.4,\) the COP of the heat pump is \((a) 1.7\) (b) 2.4 \((c) 3.4\) \((d) 4.4\) \((e) 5.0\)

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