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A Carnot heat engine operates between a source at \(1000 \mathrm{K}\) and a sink at \(300 \mathrm{K}\). If the heat engine is supplied with heat at a rate of \(800 \mathrm{kJ} / \mathrm{min}\), determine \((a)\) the thermal efficiency and \((b)\) the power output of this heat engine.

Short Answer

Expert verified
Based on the given information, we can conclude the following: (a) The thermal efficiency of the Carnot heat engine is 70%. (b) The power output of the heat engine is 9,333.33 W.

Step by step solution

01

Calculate the thermal efficiency of the Carnot heat engine.

To calculate the thermal efficiency of a Carnot heat engine, we use the formula: Thermal efficiency = \(1 - \dfrac{T_C}{T_H}\), where \(T_C\) is the temperature of the cold sink and \(T_H\) is the temperature of the hot source. In this case, \(T_C = 300\mathrm{K}\) and \(T_H = 1000\mathrm{K}\). Plugging these values into the formula: Thermal efficiency = \(1 - \dfrac{300}{1000} = 1 - 0.3 = 0.7\) The thermal efficiency of the Carnot heat engine is 0.7 or 70%.
02

Convert the heat input rate to watts.

The heat input rate is given in kJ/min, and we need to convert it to watts (W) to calculate the power output of the heat engine. We can do this by multiplying the given heat input rate by the conversion factor \(\dfrac{1000 \mathrm{J}}{1\mathrm{kJ}}\) and dividing by the conversion factor \(\dfrac{60\mathrm{s}}{1\mathrm{min}}\): Heat input rate = \(\dfrac{800\,\mathrm{kJ}\:/\: \mathrm{min} \times \dfrac{1000\,\mathrm{J}}{1\,\mathrm{kJ}}}{\dfrac{60\,\mathrm{s}}{1\,\mathrm{min}}} = \dfrac{800,000\,\mathrm{J/min}}{60\,\mathrm{s/min}} = 13,333.3\,\mathrm{W}\) The heat input rate is equal to 13,333.3 W.
03

Calculate the power output of the heat engine.

To find the power output of the heat engine, we'll use the following formula: Power output = Efficiency × Heat input rate We already found the thermal efficiency (0.7) and heat input rate (13,333.3 W), so we can plug them into the formula: Power output = 0.7 × 13,333.3 = 9,333.33 W The power output of the Carnot heat engine is 9,333.33 W. #Answer# (a) The thermal efficiency of the Carnot heat engine is 70%. (b) The power output of the heat engine is 9,333.33 W.

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Most popular questions from this chapter

The cargo space of a refrigerated truck whose inner dimensions are \(12 \mathrm{m} \times 2.3 \mathrm{m} \times 3.5 \mathrm{m}\) is to be precooled from \(25^{\circ} \mathrm{C}\) to an average temperature of \(5^{\circ} \mathrm{C}\). The construction of the truck is such that a transmission heat gain occurs at a rate of \(120 \mathrm{W} /^{\circ} \mathrm{C}\). If the ambient temperature is \(25^{\circ} \mathrm{C}\) determine how long it will take for a system with a refrigeration capacity of \(11 \mathrm{kW}\) to precool this truck.

\(6-76 \quad\) A Carnot heat engine receives \(650 \mathrm{kJ}\) of heat from a source of unknown temperature and rejects \(250 \mathrm{kJ}\) of it to a \(\operatorname{sink}\) at \(24^{\circ} \mathrm{C} .\) Determine \((a)\) the temperature of the source and (b) the thermal efficiency of the heat engine.

Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at \(1400 \mathrm{K}\) and rejects the waste heat to another reservoir at temperature \(T\) The second engine receives this energy rejected by the first one, converts some of it to work, and rejects the rest to a reservoir at \(300 \mathrm{K}\). If the thermal efficiencies of both engines are the same, determine the temperature \(T .\)

Using EES (or other) software, determine the maximum work that can be extracted from a pond containing \(10^{5} \mathrm{kg}\) of water at \(350 \mathrm{K}\) when the temperature of the surroundings is \(300 \mathrm{K}\). Notice that the temperature of water in the pond will be gradually decreasing as energy is extracted from it; therefore, the efficiency of the engine will be decreasing. Use temperature intervals of \((a) 5 \mathrm{K},(b) 2 \mathrm{K}\) and \((c) 1 \mathrm{K}\) until the pond temperature drops to \(300 \mathrm{K}\). Also solve this problem exactly by integration and compare the results.

A typical electric water heater has an efficiency of 95 percent and costs \(\$ 350\) a year to operate at a unit cost of electricity of \(\$ 0.11 / \mathrm{kWh}\). A typical heat pump-powered water heater has a COP of 3.3 but costs about \(\$ 800\) more to install. Determine how many years it will take for the heat pump water heater to pay for its cost differential from the energy it saves.

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