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Somebody claims to have developed a new reversible heat-engine cycle that has a higher theoretical efficiency than the Carnot cycle operating between the same temperature limits. How do you evaluate this claim?

Short Answer

Expert verified
Answer: To evaluate this claim, we must compare the efficiency of the new heat-engine cycle (\(\eta_{new}\)) with the efficiency of the Carnot cycle (\(\eta_{Carnot}\)). If \(\eta_{new} > \eta_{Carnot}\), then it is possible for the new heat-engine cycle to have a higher theoretical efficiency. However, it is essential to consider that the Carnot cycle represents the best possible achievable efficiency, and surpassing it in practice might be unlikely.

Step by step solution

01

Understand the Carnot cycle and efficiency

The Carnot cycle is a theoretically perfect thermodynamic cycle that serves as an ideal benchmark for heat engines. It consists of two isothermal processes and two adiabatic processes. The efficiency of a Carnot cycle depends only on the temperatures of the hot and cold reservoirs, which are denoted as \(T_H\) and \(T_C\), respectively. The theoretical maximum efficiency of a heat engine operating between these two temperature limits can be calculated using the Carnot efficiency formula: Carnot efficiency (\(\eta_{Carnot}\)) = \(1 - \frac{T_C}{T_H}\)
02

Obtain the efficiency of the new heat-engine cycle

Get the claimed efficiency of the new heat-engine cycle. Let's denote the efficiency of the new heat-engine cycle as \(\eta_{new}\).
03

Compare the new cycle efficiency with the Carnot efficiency

To evaluate the claim that the new heat-engine cycle has a higher theoretical efficiency than the Carnot cycle operating between the same temperature limits, we need to compare \(\eta_{new}\) with \(\eta_{Carnot}\). If \(\eta_{new} > \eta_{Carnot}\), then the claim is true, and the new heat-engine cycle has a higher theoretical efficiency than the Carnot cycle. If \(\eta_{new} \leq \eta_{Carnot}\), then the claim is false, as the new heat-engine cycle has a lower or equal theoretical efficiency when compared to the Carnot cycle operating between the same temperature limits.
04

Conclusion

By comparing the efficiencies of both the new heat-engine cycle and the Carnot cycle, we can determine if this claim is true or false. A higher theoretical efficiency for the new heat-engine cycle would indicate the possibility of increased performance compared to the Carnot cycle; however, it is essential to keep in mind that the Carnot cycle represents the best possible achievable efficiency, and it might be unlikely to surpass it in practice.

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Most popular questions from this chapter

The \(\mathrm{COP}\) of a refrigerator decreases as the temperature of the refrigerated space is decreased. That is, removing heat from a medium at a very low temperature will require a large work input. Determine the minimum work input required to remove \(1 \mathrm{kJ}\) of heat from liquid helium at \(3 \mathrm{K}\) when the outside temperature is 300 K.

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The cargo space of a refrigerated truck whose inner dimensions are \(12 \mathrm{m} \times 2.3 \mathrm{m} \times 3.5 \mathrm{m}\) is to be precooled from \(25^{\circ} \mathrm{C}\) to an average temperature of \(5^{\circ} \mathrm{C}\). The construction of the truck is such that a transmission heat gain occurs at a rate of \(120 \mathrm{W} /^{\circ} \mathrm{C}\). If the ambient temperature is \(25^{\circ} \mathrm{C}\) determine how long it will take for a system with a refrigeration capacity of \(11 \mathrm{kW}\) to precool this truck.

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