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Would you expect the temperature of air to drop as it undergoes a steady-flow throttling process? Explain.

Short Answer

Expert verified
Answer: Yes, the temperature of air would be expected to drop during a steady-flow throttling process due to its deviation from ideal gas behavior and its positive Joule-Thomson coefficient.

Step by step solution

01

Understanding the throttling process and Ideal Gas Law

A throttling process typically involves a fluid passing through a valve, nozzle, or other restriction that results in changes to its pressure, temperature, and/or velocity without doing any work or transferring any heat to the surroundings. For an ideal gas, we can use the Ideal Gas Law equation: PV=nRT, where P is the pressure, V is the volume, n is the amount of substance, R is the gas constant, and T is the temperature. In this process, the specific enthalpy (h) will remain constant.
02

Applying the constant enthalpy principle

In a steady-flow throttling process, the specific enthalpy (h) remains the same before and after the process. For an ideal gas, the specific enthalpy can be expressed as h = cpT, where cp is the specific heat at constant pressure and T is the temperature. Since the specific enthalpy remains constant, cpT1 = cpT2, which simplifies to T1 = T2.
03

Analyzing the change in temperature for an ideal gas

For an ideal gas undergoing a throttling process, we found that the temperature should remain constant (T1 = T2). This means that the temperature of an ideal gas would not be expected to drop during a steady-flow throttling process.
04

Considering the behavior of a real gas

Real gases deviate from ideal gas behavior due to intermolecular forces and non-zero molecular sizes. One of the parameters that can help us understand the deviation from ideality is the Joule-Thomson coefficient (µ), which describes the rate of change of temperature with pressure during a throttling process. For air, the Joule-Thomson coefficient is positive, which means that the temperature decreases as pressure decreases during a throttling process.
05

Answering the question

By analyzing the behavior of both ideal and real gases, we can conclude that the temperature of air would be expected to drop as it undergoes a steady-flow throttling process. This is due to the fact that, as a real gas, air deviates from the ideal gas behavior, and its positive Joule-Thomson coefficient indicates that its temperature would decrease as its pressure decreases during the throttling process.

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Most popular questions from this chapter

Air at \(27^{\circ} \mathrm{C}\) and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible, the exit temperature of air will be \((a) 10^{\circ} \mathrm{C}\) \((b) 15^{\circ} \mathrm{C}\) \((c) 20^{\circ} \mathrm{C}\) \((d) 23^{\circ} \mathrm{C}\) \((e) 27^{\circ} \mathrm{C}\)

Refrigerant-134a at \(1.4 \mathrm{MPa}\) and \(90^{\circ} \mathrm{C}\) is throttled to a pressure of 0.6 MPa. The temperature of the refrigerant after throttling is \((a) 22^{\circ} \mathrm{C}\) \((b) 56^{\circ} \mathrm{C}\) \((c) 82^{\circ} \mathrm{C}\) \((d) 80^{\circ} \mathrm{C}\) \((e) 90^{\circ} \mathrm{C}\)

A sealed electronic box is to be cooled by tap water flowing through the channels on two of its sides. It is specified that the temperature rise of the water not exceed \(4^{\circ} \mathrm{C}\) The power dissipation of the box is \(2 \mathrm{kW}\), which is removed entirely by water. If the box operates 24 hours a day, 365 days a year, determine the mass flow rate of water flowing through the box and the amount of cooling water used per year.

Refrigerant-134a is compressed by a compressor from the saturated vapor state at \(0.14 \mathrm{MPa}\) to \(0.9 \mathrm{MPa}\) and \(60^{\circ} \mathrm{C}\) at a rate of \(0.108 \mathrm{kg} / \mathrm{s} .\) The refrigerant is cooled at a rate of \(1.10 \mathrm{kJ} / \mathrm{s}\) during compression. The power input to the compressor is \((a) 4.94 \mathrm{kW}\) \((b) 6.04 \mathrm{kW}\) \((c) 7.14 \mathrm{kW}\) \((d) 7.50 \mathrm{kW}\) \((e) 8.13 \mathrm{kW}\)

A thin-walled double-pipe counter-flow heat exchanger is used to cool oil \(\left(c_{p}=2.20 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) from 150 to \(40^{\circ} \mathrm{C}\) at a rate of \(2 \mathrm{kg} / \mathrm{s}\) by water \(\left(c_{p}=4.18 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) that enters at \(22^{\circ} \mathrm{C}\) at a rate of \(1.5 \mathrm{kg} / \mathrm{s}\). Determine the rate of heat transfer in the heat exchanger and the exit temperature of water.

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