Chapter 5: Problem 59
Would you expect the temperature of air to drop as it undergoes a steady-flow throttling process? Explain.
Chapter 5: Problem 59
Would you expect the temperature of air to drop as it undergoes a steady-flow throttling process? Explain.
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Get started for freeAir at \(27^{\circ} \mathrm{C}\) and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible, the exit temperature of air will be \((a) 10^{\circ} \mathrm{C}\) \((b) 15^{\circ} \mathrm{C}\) \((c) 20^{\circ} \mathrm{C}\) \((d) 23^{\circ} \mathrm{C}\) \((e) 27^{\circ} \mathrm{C}\)
Refrigerant-134a at \(1.4 \mathrm{MPa}\) and \(90^{\circ} \mathrm{C}\) is throttled to a pressure of 0.6 MPa. The temperature of the refrigerant after throttling is \((a) 22^{\circ} \mathrm{C}\) \((b) 56^{\circ} \mathrm{C}\) \((c) 82^{\circ} \mathrm{C}\) \((d) 80^{\circ} \mathrm{C}\) \((e) 90^{\circ} \mathrm{C}\)
A sealed electronic box is to be cooled by tap water flowing through the channels on two of its sides. It is specified that the temperature rise of the water not exceed \(4^{\circ} \mathrm{C}\) The power dissipation of the box is \(2 \mathrm{kW}\), which is removed entirely by water. If the box operates 24 hours a day, 365 days a year, determine the mass flow rate of water flowing through the box and the amount of cooling water used per year.
Refrigerant-134a is compressed by a compressor from the saturated vapor state at \(0.14 \mathrm{MPa}\) to \(0.9 \mathrm{MPa}\) and \(60^{\circ} \mathrm{C}\) at a rate of \(0.108 \mathrm{kg} / \mathrm{s} .\) The refrigerant is cooled at a rate of \(1.10 \mathrm{kJ} / \mathrm{s}\) during compression. The power input to the compressor is \((a) 4.94 \mathrm{kW}\) \((b) 6.04 \mathrm{kW}\) \((c) 7.14 \mathrm{kW}\) \((d) 7.50 \mathrm{kW}\) \((e) 8.13 \mathrm{kW}\)
A thin-walled double-pipe counter-flow heat exchanger is used to cool oil \(\left(c_{p}=2.20 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) from 150 to \(40^{\circ} \mathrm{C}\) at a rate of \(2 \mathrm{kg} / \mathrm{s}\) by water \(\left(c_{p}=4.18 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) that enters at \(22^{\circ} \mathrm{C}\) at a rate of \(1.5 \mathrm{kg} / \mathrm{s}\). Determine the rate of heat transfer in the heat exchanger and the exit temperature of water.
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