Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is \(5.5 \times 10^{6} \mathrm{Btu} / \mathrm{h}\) The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to \(0.8 .\) The boiler operates 4200 hours a year intermittently. Taking the unit cost of energy to be \(\$ 4.35 / 10^{6} \mathrm{Btu}\), determine the annual energy and cost savings as a result of tuning up the boiler.

Short Answer

Expert verified
Answer: After tuning up the boiler, the energy consumption increased by 2.31 x 10^9 Btu, resulting in an increased cost of $10,048.5 per year.

Step by step solution

01

Identify the given parameters

We are given the following information: - Rated heat input: \(5.5 \times 10^{6} \mathrm{Btu/h}\) - Combustion efficiency before tuning: 0.7 - Combustion efficiency after tuning: 0.8 - Operating hours: 4200 hours a year - Cost of energy: \(\$4.35/10^6\mathrm{Btu}\)
02

Calculate the energy used per hour before and after tuning

To find the energy used per hour for both scenarios, we'll use the formula: Energy used per hour = Rated heat input × Combustion efficiency Before tuning: Energy used per hour = \(5.5 \times 10^6 \mathrm{Btu/h} \times 0.7 = 3.85 \times 10^6 \mathrm{Btu/h}\) After tuning: Energy used per hour = \(5.5 \times 10^6 \mathrm{Btu/h} \times 0.8 = 4.4 \times 10^6 \mathrm{Btu/h}\)
03

Calculate the annual energy used before and after tuning

To find the annual energy for both scenarios, multiply the energy used per hour by the operating hours: Before tuning: Annual energy used = \(3.85 \times 10^6 \mathrm{Btu/h} \times 4200 \mathrm{h} = 1.617 \times 10^{10} \mathrm{Btu}\) After tuning: Annual energy used = \(4.4 \times 10^6 \mathrm{Btu/h} \times 4200 \mathrm{h} = 1.848 \times 10^{10} \mathrm{Btu}\)
04

Calculate the energy savings

To find the energy savings, subtract the annual energy used after tuning from the annual energy used before tuning: Energy savings = Energy before tuning - Energy after tuning Energy savings = \(1.617 \times 10^{10} \mathrm{Btu} - 1.848 \times 10^{10} \mathrm{Btu} = -2.31 \times 10^{9} \mathrm{Btu}\) (Note that the result is negative, which means that the energy consumption has increased after tuning, not decreased.)
05

Calculate the cost savings

To find the cost savings, multiply the energy savings by the cost of energy: Cost savings = Energy savings × Cost of energy Cost savings = \(-2.31 \times 10^{9} \mathrm{Btu} \times \$4.35/10^6\mathrm{Btu} = -\$10,048.5\) Since the cost savings is negative, this implies that the cost has increased by $10,048.5 per year after tuning up the boiler.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Savings
When considering the efficiency of a boiler system, the term 'energy savings' deals with the reduction in energy consumption achieved by optimizing the boiler's performance. For a boiler powering a manufacturing facility, enhancing energy savings has a direct impact on operational costs and environmental sustainability.

Energy savings can be measured by the difference in energy used before and after implementing efficiency measures, such as tuning. In the given exercise, after improving the combustion efficiency of the boiler from 0.7 to 0.8, the expectation would be to consume less energy for the same amount of steam produced. However, it is important to evaluate the results carefully as an incorrect calculation or premise could lead to the assumption of savings when there is an increase in energy usage, as noted in the provided solution.

Consistently monitoring boiler performance and routinely conducting maintenance are key factors in achieving energy savings and can prevent scenarios where increased consumption may inadvertently occur.
Cost Savings
Cost savings in boiler operation are closely tied to energy savings, as the cost of fuel is often one of the largest expenses in boiler operation. By reducing the amount of fuel required through increased efficiency, significant amounts of money can be saved. In our exercise, the assessment of cost savings due to boiler tuning involves multiplying the quantity of energy saved by the cost of energy.

The calculation provided, however, shows an increase in energy consumption after tuning due to an incorrect assumption. Properly conducted, efficiency improvements should result in a decrease in energy use and thus a positive cost saving. An essential aspect when calculating true cost savings is to correctly interpret the data and ensure accuracy throughout the calculation process, as errors can lead to misleading conclusions about the boiler's performance and the economic benefits of tuning or other energy-saving measures.
Combustion Efficiency Calculation
Combustion efficiency calculation is a numerical evaluation of how well a boiler's combustion process converts fuel into usable heat. It is given as a percentage that indicates the portion of fuel's potential energy that is actually used in the boiler to produce steam or heat water.

For instance, an efficiency of 0.7, or 70%, signifies that 70% of the fuel's energy contributes to heating, while the remaining 30% is lost, likely through exhaust gases. Calculating combustion efficiency involves measuring the concentration of oxygen and possibly other gases like carbon dioxide in the flue gases, as well as assessing flue gas temperature. These parameters help in understanding how effectively fuel is being burned and whether adjustments to the combustion process can lead to improvements in efficiency.

While our exercise's initial calculation indicated an increase in combustion efficiency from 70% to 80% post-tuning, the mistake in concluding that energy savings occurred suggests the importance of a comprehensive approach to these calculations. Subtle nuances in boiler operation, if not accounted for, can lead to incorrect assessments of combustion efficiency.
Boiler Tuning
Boiler tuning is a process of adjusting the boiler's operation to improve its efficiency and performance. The process involves optimizing air-to-fuel ratios, checking and maintaining proper flame characteristics, and ensuring that the control systems are functioning correctly. The goal is to ensure complete combustion with minimal excess air, reducing fuel consumption and minimizing emissions.

Effective boiler tuning can lead to a more economically and environmentally friendly operation. Periodic tuning is crucial as boiler performance can drift over time due to changes in fuel composition, wear and tear of components, and external factors affecting combustion. In the presented exercise, boiler tuning improved the combustion efficiency from 0.7 to 0.8, which should have resulted in energy and cost savings. Nonetheless, it's essential to assert that adjustments made during tuning should yield actual improvements. Continuous monitoring and validation of efficiency gains are fundamental to realizing the benefits of boiler tuning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Leaded gasoline contains lead that ends up in the engine exhaust. Lead is a very toxic engine emission. The use of leaded gasoline in the United States has been unlawful for most vehicles since the 1980 s. However, leaded gasoline is still used in some parts of the world. Consider a city with 70,000 cars using leaded gasoline. The gasoline contains \(0.15 \mathrm{g} / \mathrm{L}\) of lead and 50 percent of lead is exhausted to the environment. Assuming that an average car travels \(15,000 \mathrm{km}\) per year with a gasoline consumption of \(8.5 \mathrm{L} / 100 \mathrm{km},\) deter mine the amount of lead put into the atmosphere per year in that city.

Conduct a literature survey that reviews that concepts of thermal pollution and its current state of the art.

A typical car driven \(20,000 \mathrm{km}\) a year emits to the atmosphere about 11 kg per year of \(\mathrm{NO}_{\mathrm{x}}\) (nitrogen oxides) which cause smog in major population areas. Natural gas burned in the furnace emits about \(4.3 \mathrm{g}\) of \(\mathrm{NO}_{x}\) per therm (1 therm \(=105,500 \mathrm{kJ}\) ), and the electric power plants emit about \(7.1 \mathrm{g}\) of \(\mathrm{NO}_{x}\) per \(\mathrm{kWh}\) of electricity produced. Consider a household that has two cars and consumes \(9000 \mathrm{kWh}\) of electricity and 1200 therms of natural gas. Determine the amount of \(\mathrm{NO}_{x}\) emission to the atmosphere per year for which this household is responsible.

A small electrical motor produces 5 W of mechanical power. What is this power in \((a) \mathrm{N}, \mathrm{m},\) and \(\mathrm{s}\) units; and (b) \(\mathrm{kg}, \mathrm{m},\) and s units?

A geothermal pump is used to pump brine whose density is \(1050 \mathrm{kg} / \mathrm{m}^{3}\) at a rate of \(0.3 \mathrm{m}^{3} / \mathrm{s}\) from a depth of \(200 \mathrm{m}\). For a pump efficiency of 74 percent, determine the required power input to the pump. Disregard frictional losses in the pipes, and assume the geothermal water at \(200 \mathrm{m}\) depth to be exposed to the atmosphere.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free