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A subsonic airplane is flying at a \(5000-\mathrm{m}\) altitude where the atmospheric conditions are \(54 \mathrm{kPa}\) and \(256 \mathrm{K}\). A Pitot static probe measures the difference between the static and stagnation pressures to be 16 kPa. Calculate the speed of the airplane and the flight Mach number.

Short Answer

Expert verified
Answer: The speed of the airplane is approximately 195.1 m/s and the flight Mach number is approximately 0.616.

Step by step solution

01

1. Calculate the speed of sound

To determine the speed of sound, we can use the following equation: \( a = \sqrt{\gamma R T} \) Where \(a\) is the speed of sound, \(\gamma\) is the ratio of specific heats (1.4 for air), \(R\) is the specific gas constant for air (287 J/kg·K), and \(T\) is the temperature in Kelvin. Given the temperature, T = 256 K: \( a = \sqrt{1.4 \cdot 287 \cdot 256} \approx 316.3 \;\text{m/s} \)
02

2. Calculate the static pressure at the altitude

We are given the atmospheric conditions at the altitude - the pressure is 54 kPa. Thus, the static pressure \(P_{static} = 54\;\text{kPa}\)
03

3. Determine the stagnation pressure

We are given the difference between the static and stagnation pressures as 16 kPa. Thus, the stagnation pressure \(P_{stag}\) can be found by adding this difference to the static pressure: \(P_{stag} = P_{static} + \Delta P = 54\;\text{kPa} + 16\;\text{kPa} = 70\;\text{kPa}\)
04

4. Calculate the airplane's speed

We can now use the Bernoulli equation relating static and stagnation pressures to find the airplane's speed, \(V\). The Bernoulli equation in this case is: \(P_{stag} = P_{static} + \frac{1}{2} \rho V^2\) First, we need to find the air density (\(\rho\)) at the given altitude using the ideal gas law: \(\rho = \frac{P_{static}}{R T} = \frac{54\times 10^3\;\text{Pa}}{287\;\text{J/kg·K}\cdot 256\;\text{K}} \approx 0.73\;\text{kg/m^3}\) Now, we can use the Bernoulli equation and solve for \(V\): \(V = \sqrt{\frac{2(P_{stag} - P_{static})}{\rho}} = \sqrt{\frac{2(70\times 10^3\;\text{Pa} - 54\times 10^3\;\text{Pa})}{0.73\;\text{kg/m^3}}} \approx 195.1\;\text{m/s}\)
05

5. Calculate the flight Mach number

Finally, we calculate the flight Mach number using the airplane's speed and the speed of sound found in step 1: \(M = \frac{V}{a} = \frac{195.1\;\text{m/s}}{316.3\;\text{m/s}} \approx 0.616\) So, the speed of the airplane is approximately 195.1 m/s and the flight Mach number is approximately 0.616.

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