Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A fuel is completely burned first with the stoichiometric amount of air and then with the stoichiometric amount of pure oxygen. For which case will the adiabatic flame temperature be higher?

Short Answer

Expert verified
Answer: The adiabatic flame temperature will be higher for the case when the fuel is burned with the stoichiometric amount of pure oxygen. This is because, in this case, there are no inert gases present to absorb heat from the combustion process, allowing the heat to be used solely for increasing the combustion product temperature.

Step by step solution

01

Stoichiometric Combustion with Air

Combustion with air means that the fuel is burned with the presence of nitrogen (N2), oxygen (O2), trace amounts of carbon dioxide (CO2), and other trace gases. Air consists of approximately 21% oxygen and 78% nitrogen. Nitrogen is considered inert during the combustion process, meaning it doesn't participate in the reaction but absorbs some amount of heat. This leads to a lower flame temperature as some of the heat is used to heat up this inert gas.
02

Stoichiometric Combustion with Pure Oxygen

Combustion with pure oxygen means that the fuel is burned with only oxygen gas and no presence of nitrogen or other trace gases. Therefore, the heat released during combustion can be used solely to increase the temperature of the combustion products. As a result, a higher flame temperature is expected when burning with pure oxygen compared to burning with air.
03

Adiabatic Flame Temperature Comparison

The adiabatic flame temperature is the temperature achieved when combustion occurs under adiabatic conditions, meaning no heat is lost to the surroundings. Since the heat released during combustion with pure oxygen is not absorbed by any inert gases (unlike the case with air), we can expect that the adiabatic flame temperature will be higher when the fuel is burned with the stoichiometric amount of pure oxygen. So, the adiabatic flame temperature will be higher for the case when the fuel is burned with the stoichiometric amount of pure oxygen.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometric Combustion
Understanding stoichiometric combustion is critical for unraveling the mystery behind adiabatic flame temperatures. Stoichiometric combustion refers to the ideal reaction where fuel is burned with the exact amount of oxygen needed for a complete combustion process. In simpler terms, it's like baking a cake with the precise amount of ingredients—no more, no less—leading to the perfect outcome without any leftovers.In the realm of chemistry, it's a balanced equation with all reactants being consumed to produce only carbon dioxide (CO2) and water (H2O) when dealing with hydrocarbon fuels. There are no excess reactants or remaining fuel, and this precise mixture is key to achieving the most efficient combustion possible. However, in real-world applications, we rarely utilize stoichiometric mixtures as it could lead to higher temperatures that might damage engines or reactors. But for the purpose of academic exercises and controlled environments, understanding stoichiometric combustion sets the stage for exploring variations like combustion with air or pure oxygen.
Combustion with Air
Combustion with air is the typical scenario we encounter in everyday life. When fuels such as gasoline burn in the engine of a car or when grilling on a barbecue, it's the air around us that provides the oxygen for combustion. Air, however, is not pure oxygen. It contains about 21% oxygen and 78% nitrogen, alongside minute amounts of other gases. During combustion, that nitrogen doesn't just sit idly by; it absorbs some of the heat without reacting, behaving as an excess baggage that shares the energy without contributing to the reaction. This process deceptively 'steals' heat and results in a lower adiabatic flame temperature as compared to combustion with pure oxygen.To put it more visually: imagine throwing a party where you've prepared food just for your invited guests (the oxygen), but uninvited guests (the nitrogen) show up and consume some of the food without adding to the fun—the overall satisfaction (flame temperature) decreases because of these party crashers.
Combustion with Pure Oxygen
On the other hand, combustion with pure oxygen is akin to hosting that party with an exclusive guest list—no uninvited guests allowed. Only having oxygen present, without the nitrogen or trace gases, means that the heat from the combustion is used more effectively. This exclusive arrangement leads to a higher flame temperature because all the energy released during combustion is solely devoted to heating the products of combustion (CO2 and H2O), without any loss to inert gases such as nitrogen.This scenario, albeit less common in everyday situations, is crucial in industrial processes where higher temperatures are necessary for certain reactions or for achieving a more complete burn of fuels. Whether it's for cutting metals with precision in welding or in specialized furnaces, using pure oxygen can significantly increase efficiency. Whenever we opt for combustion with pure oxygen, we deliver all the energy right to the intended 'guests,' enabling the highest possible adiabatic flame temperature.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which is more likely to be found in the products of an incomplete combustion of a hydrocarbon fuel, \(\mathrm{CO}\) or OH? Why?

Constant-volume vessels that contain flammable mixtures of hydrocarbon vapors and air at low pressures are frequently used. Although the ignition of such mixtures is very unlikely as there is no source of ignition in the tank, the Safety and Design Codes require that the tank withstand four times the pressure that may occur should an explosion take place in the tank. For operating gauge pressures under \(25 \mathrm{kPa}\), determine the pressure for which these vessels must be designed in order to meet the requirements of the codes for \((a)\) acetylene \(\mathrm{C}_{2} \mathrm{H}_{2}(g),(b)\) propane \(\mathrm{C}_{3} \mathrm{H}_{8}(g),\) and \((c) n\) -octane \(\mathrm{C}_{8} \mathrm{H}_{18}(g) .\) Justify any assumptions that you make.

A coal from Texas which has an ultimate analysis (by mass \()\) as 39.25 percent \(C, 6.93\) percent \(H_{2}, 41.11\) percent \(O_{2}\) 0.72 percent \(\mathrm{N}_{2}, 0.79\) percent \(\mathrm{S},\) and 11.20 percent ash (non combustibles) is burned steadily with 40 percent excess air in a power plant boiler. The coal and air enter this boiler at standard conditions and the products of combustion in the smokestack are at \(127^{\circ} \mathrm{C}\). Calculate the heat transfer, in \(\mathrm{kJ} / \mathrm{kg}\) fuel, in this boiler. Include the effect of the sulfur in the energy analysis by noting that sulfur dioxide has an enthalpy of formation of \(-297,100 \mathrm{kJ} / \mathrm{kmol}\) and an average specific heat at constant pressure of \(c_{p}=41.7 \mathrm{kJ} / \mathrm{kmol} \cdot \mathrm{K}\).

Liquid propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}(\ell)\right)\) enters a combustion chamber at \(25^{\circ} \mathrm{C}\) and 1 atm at a rate of \(0.4 \mathrm{kg} / \mathrm{min}\) where it is mixed and burned with 150 percent excess air that enters the combustion chamber at \(25^{\circ} \mathrm{C}\). The heat transfer from the combustion process is \(53 \mathrm{kW}\). Write the balanced combustion equation and determine \((a)\) the mass flow rate of air; \((b)\) the average molar mass (molecular weight) of the product gases; \((c)\) the average specific heat at constant pressure of the product gases; and ( \(d\) ) the temperature of the products of combustion.

Gaseous E10 fuel is 10 percent ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\right)\) and 90 percent octane \(\left(\mathrm{C}_{8} \mathrm{H}_{18}\right)\) on a kmol basis. This fuel is burned with 110 percent theoretical air. During the combustion process, 90 percent of the carbon in the fuel is converted to \(\mathrm{CO}_{2}\) and 10 percent is converted to CO. Determine \((a)\) the balanced combustion equation, (b) the dew-point temperature of the products, in \(^{\circ} \mathrm{C}\), for a product pressure of \(100 \mathrm{kPa}\) (c) the heat transfer for the process, in \(\mathrm{kJ}\), after \(2.5 \mathrm{kg}\) of fuel are burned and the reactants and products are at \(25^{\circ} \mathrm{C}\) with the water in the products remaining a gas, and (d) the relative humidity of atmospheric air for the case where the atmospheric air is at \(25^{\circ} \mathrm{C}\) and \(100 \mathrm{kPa}\) and the products are found to contain \(9.57 \mathrm{kmol}\) of water vapor per kmol of fuel burned.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free