Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider a circular copper wire formed by connecting the two ends of a copper wire. The connection point is now heated by a burning candle. Do you expect any current to flow through the wire?

Short Answer

Expert verified
Answer: No, there will not be any current flow in the wire, as there is no potential difference across the circuit, despite the increased resistance at the heated connection point.

Step by step solution

01

Understanding the properties of Copper and its temperature dependence

Copper is a good conductor of electricity, which means it has a low resistivity. Resistivity of a material generally increases with temperature. If we heat copper, its resistance will increase.
02

Analyzing the Circular Circuit

In the given problem, a copper wire is connected to form a circular loop and the connection point is heated. Since the heated connection point has increased resistance, the wire now forms a closed circuit with non-uniform resistance.
03

Current Flow in a Closed Circuit

In order for current to flow in a closed circuit, there must be a potential difference (voltage) across the circuit. In this case, there is no voltage source mentioned, which implies that there is no potential difference across the circular copper wire.
04

Determining the possibility of current flow

As there is no potential difference across the circular copper wire, there would not be any current flow in the wire, despite the increased resistance at the heated connection point. In conclusion, no current will flow through the circular copper wire when the connection point is heated by a burning candle, since there is no potential difference across the circuit.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How does a thermocouple work as a temperature measurement device?

A heat pump that operates on the ideal vaporcompression cycle with refrigerant-134a is used to heat a house and maintain it at \(75^{\circ} \mathrm{F}\) by using underground water at \(50^{\circ} \mathrm{F}\) as the heat source. The house is losing heat at a rate of \(60,000 \mathrm{Btu} / \mathrm{h} .\) The evaporator and condenser pressures are 50 and 120 psia, respectively. Determine the power input to the heat pump and the electric power saved by using a heat pump instead of a resistance heater.

Write an essay on air- , water- , and soil-based heat pumps. Discuss the advantages and the disadvantages of each system. For each system identify the conditions under which that system is preferable over the other two. In what situations would you not recommend a heat pump heating system?

Consider a heat pump that operates on the ideal vapor compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid between the pressure limits of 0.32 and \(1.2 \mathrm{MPa}\). The coefficient of performance of this heat pump is \((a) 0.17\) \((b) 1.2\) \((c) 3.1\) \((d) 4.9\) \((e) 5.9\)

An absorption refrigeration system is to remove heat from the refrigerated space at \(2^{\circ} \mathrm{C}\) at a rate of \(28 \mathrm{kW}\) while operating in an environment at \(25^{\circ} \mathrm{C}\). Heat is to be supplied from a solar pond at \(95^{\circ} \mathrm{C}\). What is the minimum rate of heat supply required?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free