Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the liquefaction process, why are gases compressed to very high pressures?

Short Answer

Expert verified
Answer: Gases are compressed to very high pressures during the liquefaction process to increase their density, make them easier to store and transport, and to bring gas molecules closer together. This enhances the significance of intermolecular attractive forces, which facilitates the gas-to-liquid phase transition.

Step by step solution

01

Definition of Liquefaction Process

Liquefaction process is a technique used to convert a gas into a liquid state by reducing its temperature and increasing its pressure. This process is essential for the storage and transport of gases such as natural gas, helium, and nitrogen.
02

Compressing Gases to High Pressures

The main reason for compressing gases to very high pressures in the liquefaction process is to increase the density of the gas, bringing the gas molecules closer together. Compressing the gas reduces the volume it occupies, and it is easier and more economical to store and transport a gas in a liquid state than in a gaseous state.
03

Boyle's Law and the Liquefaction Process

According to Boyle's Law, the pressure of a gas is inversely proportional to its volume at a constant temperature (P_1 V_1 = P_2 V_2). Thus, when the pressure of a gas is increased, its volume decreases. This change helps to facilitate the conversion of the gas into a liquid state.
04

Effect on Intermolecular Forces

Another important factor is that by increasing the pressure, intermolecular forces between gas molecules have more impact. When gas molecules are brought closer together, attractive forces between them become more significant, making it easier for the gas to transition into a liquid state.
05

Critical Point

The critical point is defined as the temperature and pressure above which a substance cannot exist in the gas and liquid state simultaneously. For the liquefaction process, it is necessary to maintain a temperature and pressure below the critical point of the gas, so that the gas can actually transform into a liquid state. In conclusion, gases are compressed to very high pressures in the liquefaction process mainly to increase their density, make them easier to store and transport, and to bring gas molecules closer together, increasing the significance of intermolecular attractive forces and facilitating the gas-to-liquid phase transition.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A refrigerator operates on the ideal vapor compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid between the pressure limits of 120 and 800 kPa. If the rate of heat removal from the refrigerated space is \(32 \mathrm{kJ} / \mathrm{s}\), the mass flow rate of the refrigerant is \((a) 0.19 \mathrm{kg} / \mathrm{s}\) \((b) 0.15 \mathrm{kg} / \mathrm{s}\) \((c) 0.23 \mathrm{kg} / \mathrm{s}\) \((d) 0.28 \mathrm{kg} / \mathrm{s}\) \((e) 0.81 \mathrm{kg} / \mathrm{s}\)

An ice-making machine operates on the ideal vapor-compression cycle, using refrigerant-134a. The refrigerant enters the compressor as saturated vapor at 20 psia and leaves the condenser as saturated liquid at 80 psia. Water enters the ice machine at \(55^{\circ} \mathrm{F}\) and leaves as ice at \(25^{\circ} \mathrm{F}\). For an ice production rate of \(15 \mathrm{lbm} / \mathrm{h}\), determine the power input to the ice machine \((169 \mathrm{Btu}\) of heat needs to be removed from each \(1 \mathrm{bm}\) of water at \(55^{\circ} \mathrm{F}\) to turn it into ice at \(25^{\circ} \mathrm{F}\) ).

An ideal gas refrigeration cycle using air as the working fluid is to maintain a refrigerated space at \(-23^{\circ} \mathrm{C}\) while rejecting heat to the surrounding medium at \(27^{\circ} \mathrm{C}\). If the pressure ratio of the compressor is \(3,\) determine \((a)\) the maximum and minimum temperatures in the cycle, \((b)\) the coefficient of performance, and ( \(c\) ) the rate of refrigeration for a mass flow rate of \(0.08 \mathrm{kg} / \mathrm{s}\).

A heat pump with refrigerant-134a as the working fluid is used to keep a space at \(25^{\circ} \mathrm{C}\) by absorbing heat from geothermal water that enters the evaporator at \(50^{\circ} \mathrm{C}\) at a rate of \(0.065 \mathrm{kg} / \mathrm{s}\) and leaves at \(40^{\circ} \mathrm{C}\). The refrigerant enters the evaporator at \(20^{\circ} \mathrm{C}\) with a quality of 23 percent and leaves at the inlet pressure as saturated vapor. The refrigerant loses \(300 \mathrm{W}\) of heat to the surroundings as it flows through the compressor and the refrigerant leaves the compressor at \(1.4 \mathrm{MPa}\) at the same entropy as the inlet. Determine ( \(a\) ) the degrees of subcooling of the refrigerant in the condenser, (b) the mass flow rate of the refrigerant, \((c)\) the heating load and the COP of the heat pump, and (d) the theoretical minimum power input to the compressor for the same heating load.

An absorption refrigeration system receives heat from a source at \(120^{\circ} \mathrm{C}\) and maintains the refrigerated space at \(0^{\circ} \mathrm{C}\) If the temperature of the environment is \(25^{\circ} \mathrm{C}\), what is the maximum COP this absorption refrigeration system can have?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free