Chapter 11: Problem 52
In the liquefaction process, why are gases compressed to very high pressures?
Chapter 11: Problem 52
In the liquefaction process, why are gases compressed to very high pressures?
All the tools & learning materials you need for study success - in one app.
Get started for freeA refrigerator operates on the ideal vapor compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid between the pressure limits of 120 and 800 kPa. If the rate of heat removal from the refrigerated space is \(32 \mathrm{kJ} / \mathrm{s}\), the mass flow rate of the refrigerant is \((a) 0.19 \mathrm{kg} / \mathrm{s}\) \((b) 0.15 \mathrm{kg} / \mathrm{s}\) \((c) 0.23 \mathrm{kg} / \mathrm{s}\) \((d) 0.28 \mathrm{kg} / \mathrm{s}\) \((e) 0.81 \mathrm{kg} / \mathrm{s}\)
An ice-making machine operates on the ideal vapor-compression cycle, using refrigerant-134a. The refrigerant enters the compressor as saturated vapor at 20 psia and leaves the condenser as saturated liquid at 80 psia. Water enters the ice machine at \(55^{\circ} \mathrm{F}\) and leaves as ice at \(25^{\circ} \mathrm{F}\). For an ice production rate of \(15 \mathrm{lbm} / \mathrm{h}\), determine the power input to the ice machine \((169 \mathrm{Btu}\) of heat needs to be removed from each \(1 \mathrm{bm}\) of water at \(55^{\circ} \mathrm{F}\) to turn it into ice at \(25^{\circ} \mathrm{F}\) ).
An ideal gas refrigeration cycle using air as the working fluid is to maintain a refrigerated space at \(-23^{\circ} \mathrm{C}\) while rejecting heat to the surrounding medium at \(27^{\circ} \mathrm{C}\). If the pressure ratio of the compressor is \(3,\) determine \((a)\) the maximum and minimum temperatures in the cycle, \((b)\) the coefficient of performance, and ( \(c\) ) the rate of refrigeration for a mass flow rate of \(0.08 \mathrm{kg} / \mathrm{s}\).
A heat pump with refrigerant-134a as the working fluid is used to keep a space at \(25^{\circ} \mathrm{C}\) by absorbing heat from geothermal water that enters the evaporator at \(50^{\circ} \mathrm{C}\) at a rate of \(0.065 \mathrm{kg} / \mathrm{s}\) and leaves at \(40^{\circ} \mathrm{C}\). The refrigerant enters the evaporator at \(20^{\circ} \mathrm{C}\) with a quality of 23 percent and leaves at the inlet pressure as saturated vapor. The refrigerant loses \(300 \mathrm{W}\) of heat to the surroundings as it flows through the compressor and the refrigerant leaves the compressor at \(1.4 \mathrm{MPa}\) at the same entropy as the inlet. Determine ( \(a\) ) the degrees of subcooling of the refrigerant in the condenser, (b) the mass flow rate of the refrigerant, \((c)\) the heating load and the COP of the heat pump, and (d) the theoretical minimum power input to the compressor for the same heating load.
An absorption refrigeration system receives heat from a source at \(120^{\circ} \mathrm{C}\) and maintains the refrigerated space at \(0^{\circ} \mathrm{C}\) If the temperature of the environment is \(25^{\circ} \mathrm{C}\), what is the maximum COP this absorption refrigeration system can have?
What do you think about this solution?
We value your feedback to improve our textbook solutions.