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What is a water-source heat pump? How does the COP of a water-source heat pump system compare to that of an air-source system?

Short Answer

Expert verified
Answer: Water-source heat pump systems generally have higher COP values and overall efficiency compared to air-source heat pump systems, due to the stable temperature of water sources and less dependency on outside air temperature. The COP of a water-source heat pump system ranges from 3 to 6, while the COP of an air-source heat pump system ranges from 2 to 4.5.

Step by step solution

01

Define a water-source heat pump

A water-source heat pump is a type of heating and cooling system that transfers heat between a building and a nearby water source, such as a lake, river, or even underground water source. These systems use the constant temperature of water that makes them very efficient in both heating and cooling applications.
02

Define an air-source heat pump

An air-source heat pump is a type of heating and cooling system that transfers heat between a building and the outside air. These systems extract heat from the air and transfer it to the building during the heating season, while extracting heat from the building and transferring it to the outside air during the cooling season.
03

Explain Coefficient of Performance (COP)

Coefficient of Performance (COP) is defined as the ratio of useful heat output (or cooling) to the amount of electrical energy input to the system. It is an important parameter to evaluate the efficiency of a heat pump system.
04

Compare COP for water-source and air-source heat pump systems

Water-source heat pump systems generally have higher COP values than air-source heat pump systems because water has a more stable temperature than air, which makes the heat transfer process more efficient. In addition, water-source heat pump systems generally have lower operational costs and are less affected by the outside air temperature, making them more efficient even in extreme weather conditions. The COP of a water-source heat pump system ranges from 3 to 6, while the COP of an air-source heat pump system ranges from 2 to 4.5. In conclusion, water-source heat pump systems generally have higher COP values and overall efficiency compared to air-source heat pump systems, due to the stable temperature of water sources and less dependency on outside air temperature.

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Most popular questions from this chapter

It is proposed to use a solar-powered thermoelectric system installed on the roof to cool residential buildings. The system consists of a thermoelectric refrigerator that is powered by a thermoelectric power generator whose top surface is a solar collector. Discuss the feasibility and the cost of such a system, and determine if the proposed system installed on one side of the roof can meet a significant portion of the cooling requirements of a typical house in your area.

An absorption refrigeration system receives heat from a source at \(120^{\circ} \mathrm{C}\) and maintains the refrigerated space at \(0^{\circ} \mathrm{C}\) If the temperature of the environment is \(25^{\circ} \mathrm{C}\), what is the maximum COP this absorption refrigeration system can have?

A copper and a constantan wire are formed into a closed circuit by connecting the ends. Now one junction is heated by a burning candle while the other is maintained at room temperature. Do you expect any electric current to flow through this circuit?

An ideal gas refrigeration system with three stages of compression with intercooling operates with air entering the first compressor at \(50 \mathrm{kPa}\) and \(-30^{\circ} \mathrm{C}\). Each compressor in this system has a pressure ratio of \(7,\) and the air temperature at the outlet of all intercoolers is \(15^{\circ} \mathrm{C}\) Calculate the COP of this system. Use constant specific heats at room temperature.

An ideal gas refrigeration cycle using air as the working fluid operates between the pressure limits of 80 and \(280 \mathrm{kPa} .\) Air is cooled to \(35^{\circ} \mathrm{C}\) before entering the turbine. The lowest temperature of this cycle is \((a)-58^{\circ} \mathrm{C}\) \((b)-26^{\circ} \mathrm{C}\) \((c) 5^{\circ} \mathrm{C}\) \((d) 11^{\circ} \mathrm{C}\) \((e) 24^{\circ} \mathrm{C}\)

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