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Do you think a heat pump system will be more cost-effective in New York or in Miami? Why?

Short Answer

Expert verified
Answer: A heat pump system is more cost-effective in Miami compared to New York, mainly due to the difference in climate and energy costs.

Step by step solution

01

Understand the climate in New York and Miami

Begin by researching the climate differences between New York and Miami. New York has a humid continental climate, with significant temperature variations throughout the year. Winters are cold, with average low temperatures in January around 27°F (-3°C), while summers can be hot, with average high temperatures in July around 84°F (29°C). Conversely, Miami has a tropical climate, with high temperatures and humidity throughout the year. January average low temperatures are about 59°F (15°C), and July average highs are around 89°F (32°C).
02

Understand heat pump efficiency

Heat pumps are more efficient at heating and cooling when the temperature difference between the indoor and outdoor environments is smaller. In colder climates like New York, a heat pump may struggle to maintain a comfortable indoor temperature during the winter months without the aid of supplemental heating sources. In warmer climates like Miami, a heat pump would operate more efficiently because the temperature difference is smaller year-round.
03

Compare energy costs in New York and Miami

Compare the cost of electricity in the two cities, as this is the primary energy source for a heat pump system. According to the U.S. Energy Information Administration, the average residential electricity price in New York is 17.62 cents per kWh, while in Miami, the average price is 11.67 cents per kWh.
04

Assess cost-effectiveness of a heat pump system

To determine the cost-effectiveness of a heat pump system in the two cities, consider both the climate conditions and energy costs. In New York, a heat pump may not function efficiently during the winter months, requiring a higher energy use for supplemental heating. Additionally, electricity costs in New York are higher than in Miami. Therefore, the operating costs for a heat pump would be higher in New York compared to Miami. In Miami, a heat pump would be more efficient year-round, leading to lower energy usage, and the electricity costs are lower, making it a more cost-effective option. Based on the analysis, a heat pump system will be more cost-effective in Miami compared to New York, mainly due to the difference in climate and energy costs.

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Most popular questions from this chapter

Refrigerant-134a enters the compressor of a refrigerator as superheated vapor at \(0.20 \mathrm{MPa}\) and \(-5^{\circ} \mathrm{C}\) at a rate of \(0.07 \mathrm{kg} / \mathrm{s},\) and it leaves at \(1.2 \mathrm{MPa}\) and \(70^{\circ} \mathrm{C}\). The refrigerant is cooled in the condenser to \(44^{\circ} \mathrm{C}\) and \(1.15 \mathrm{MPa}\), and it is throttled to 0.21 MPa. Disregarding any heat transfer and pressure drops in the connecting lines between the components, show the cycle on a \(T\) -s diagram with respect to saturation lines, and determine ( \(a\) ) the rate of heat removal from the refrigerated space and the power input to the compressor, \((b)\) the isentropic efficiency of the compressor, and \((c)\) the \(C O P\) of the refrigerator.

A refrigerator operating on the vapor-compression refrigeration cycle using refrigerant-134a as the refrigerant is considered. The temperature of the cooled space and the ambient air are at \(10^{\circ} \mathrm{F}\) and \(80^{\circ} \mathrm{F}\), respectively. \(\mathrm{R}-134\) anters the compressor at 20 psia as a saturated vapor and leaves at 140 psia and \(160^{\circ} \mathrm{F}\). The refrigerant leaves the condenser as a saturated liquid. The rate of cooling provided by the system is 45,000 Btu/h. Determine ( \(a\) ) the mass flow rate of \(R-134\) and the COP, \((b)\) the exergy destruction in each component of the cycle and the secondlaw efficiency of the compressor, and (c) the second-law efficiency of the cycle and the total exergy destruction in the cycle.

The COP of vapor-compression refrigeration cycles improves when the refrigerant is subcooled before it enters the throttling valve. Can the refrigerant be subcooled indefinitely to maximize this effect, or is there a lower limit? Explain

A heat pump water heater (HPWH) heats water by absorbing heat from the ambient air and transferring it to water. The heat pump has a COP of 3.4 and consumes \(6 \mathrm{kW}\) of electricity when running. Determine if this heat pump can be used to meet the cooling needs of a room most of the time for "free" by absorbing heat from the air in the room. The rate of heat gain of a room is usually less than \(45,000 \mathrm{kJ} / \mathrm{h}\).

Consider a heat pump that operates on the ideal vapor compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid between the pressure limits of 0.32 and \(1.2 \mathrm{MPa}\). The coefficient of performance of this heat pump is \((a) 0.17\) \((b) 1.2\) \((c) 3.1\) \((d) 4.9\) \((e) 5.9\)

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