Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Why do we study the reversed Carnot cycle even though it is not a realistic model for refrigeration cycles?

Short Answer

Expert verified
Answer: Studying the reversed Carnot cycle is important because it defines the upper limit of efficiency for refrigeration cycles and heat pumps, serves as a basis for comparing the performance of real-world systems to the ideal case, and provides a deeper understanding of fundamental thermodynamic principles like heat transfer, work, entropy, and system reversibility.

Step by step solution

01

Understanding the Carnot Cycle

The Carnot cycle is an idealized thermodynamic cycle that consists of four reversible processes: Two isothermal processes and two adiabatic processes. This cycle is named after Sadi Carnot, who introduced it as an idealized heat engine model with maximum possible efficiency.
02

The Reversed Carnot Cycle

The reversed Carnot cycle, as the name suggests, is the Carnot cycle in reverse order. Instead of producing work as in the original Carnot cycle, the reversed Carnot cycle requires work input to transfer heat from a lower temperature reservoir to a higher temperature reservoir. This process is used for refrigeration and heat pumps.
03

Importance of studying the reversed Carnot cycle

Although the reversed Carnot cycle is not a realistic model for refrigeration cycles, it serves as an important learning tool for several reasons: 1. Theoretical boundaries: The reversed Carnot cycle defines the upper limit of efficiency for all refrigeration cycles and heat pumps. It helps to understand the maximum performance that any real-world refrigeration system can achieve. 2. Basis for comparison: By studying the reversed Carnot cycle, we can compare the efficiency of real-world refrigeration cycles to the ideal case. This comparison can help identify areas of improvement in existing technologies. 3. Fundamental understanding: The reversed Carnot cycle provides a deeper understanding of the fundamental thermodynamic principles at play in refrigeration and heat pump processes. It serves as a tool for better grasping the concepts of heat transfer, work, entropy, and system reversibility.
04

In conclusion

Although the reversed Carnot cycle is not a realistic model, it is crucial to study because it provides a better understanding of fundamental concepts in thermodynamics and serves as an ideal benchmark for real-world refrigeration cycles' performance.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Design a thermoelectric refrigerator that is capable of cooling a canned drink in a car. The refrigerator is to be powered by the cigarette lighter of the car. Draw a sketch of your design. Semiconductor components for building thermoelectric power generators or refrigerators are available from several manufacturers. Using data from one of these manufacturers, determine how many of these components you need in your design, and estimate the coefficient of performance of your system. A critical problem in the design of thermoelectric refrigerators is the effective rejection of waste heat. Discuss how you can enhance the rate of heat rejection without using any devices with moving parts such as a fan.

A heat pump with refrigerant-134a as the working fluid is used to keep a space at \(25^{\circ} \mathrm{C}\) by absorbing heat from geothermal water that enters the evaporator at \(50^{\circ} \mathrm{C}\) at a rate of \(0.065 \mathrm{kg} / \mathrm{s}\) and leaves at \(40^{\circ} \mathrm{C}\). The refrigerant enters the evaporator at \(20^{\circ} \mathrm{C}\) with a quality of 23 percent and leaves at the inlet pressure as saturated vapor. The refrigerant loses \(300 \mathrm{W}\) of heat to the surroundings as it flows through the compressor and the refrigerant leaves the compressor at \(1.4 \mathrm{MPa}\) at the same entropy as the inlet. Determine ( \(a\) ) the degrees of subcooling of the refrigerant in the condenser, (b) the mass flow rate of the refrigerant, \((c)\) the heating load and the COP of the heat pump, and (d) the theoretical minimum power input to the compressor for the same heating load.

Consider a regenerative gas refrigeration cycle using helium as the working fluid. Helium enters the compressor at \(100 \mathrm{kPa}\) and \(-10^{\circ} \mathrm{C}\) and is compressed to \(300 \mathrm{kPa}\). Helium is then cooled to \(20^{\circ} \mathrm{C}\) by water. It then enters the regenerator where it is cooled further before it enters the turbine. Helium leaves the refrigerated space at \(-25^{\circ} \mathrm{C}\) and enters the regenerator. Assuming both the turbine and the compressor to be isentropic, determine ( \(a\) ) the temperature of the helium at the turbine inlet, ( \(b\) ) the coefficient of performance of the cycle, and ( \(c\) ) the net power input required for a mass flow rate of \(0.45 \mathrm{kg} / \mathrm{s}\).

Air enters the compressor of an ideal gas refrigeration cycle at \(40^{\circ} \mathrm{F}\) and 10 psia and the turbine at \(120^{\circ} \mathrm{F}\) and 30 psia. The mass flow rate of air through the cycle is 0.5 lbm/s. Determine \((a)\) the rate of refrigeration, \((b)\) the net power input, and ( \(c\) ) the coefficient of performance.

It is proposed to run a thermoelectric generator in conjunction with a solar pond that can supply heat at a rate of \(7 \times 10^{6} \mathrm{kJ} / \mathrm{h}\) at \(90^{\circ} \mathrm{C}\). The waste heat is to be rejected to the environment at \(22^{\circ} \mathrm{C}\). What is the maximum power this thermoelectric generator can produce?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free