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Using EES (or other) software, investigate the effect of the condenser pressure on the COP of an ideal vapor-compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid. Assume the evaporator pressure is kept constant at \(150 \mathrm{kPa}\) while the condenser pressure is varied from 400 to \(1400 \mathrm{kPa}\). Plot the COP of the refrigeration cycle against the condenser pressure, and discuss the results.

Short Answer

Expert verified
In this exercise, we have studied the effect of condenser pressure on the Coefficient of Performance (COP) of an ideal vapor-compression refrigeration cycle using R-134a as the working fluid. By setting up a simulation software (EES), we modeled the refrigeration cycle with a constant evaporator pressure of 150 kPa. We varied the condenser pressure from 400 kPa to 1400 kPa and calculated the COP for each case. Finally, we plotted the COP against the condenser pressure and analyzed the results. From the generated plot, we observed that as the condenser pressure increases, the COP of the cycle decreases. This indicates that higher condenser pressures lead to lower energy efficiency for the refrigeration cycle. Therefore, it is crucial to maintain optimal condenser pressure levels to ensure efficient operation of the refrigeration system using R-134a as the working fluid.

Step by step solution

01

Setup the simulation software

First, set up the simulation software (EES or any other) of your choice. Input the given parameters: working fluid as R-134a, evaporator pressure constant at 150 kPa, and condenser pressure to be varied from 400 to 1400 kPa. Hint: If you are using EES, select the built-in property functions to define the refrigerant properties and cycle parameters.
02

Model the ideal vapor-compression refrigeration cycle

An ideal vapor-compression refrigeration cycle consists of four main components: evaporator, compressor, condenser, and expansion valve. Start by calculating the properties of the refrigerant at each of these components (saturated states where relevant). Use the given evaporator pressure and the condenser pressure in your calculations. Hint: Use the property functions at state points 1 (evaporator inlet), 2 (compressor inlet), 3 (condenser inlet), and 4 (expansion valve inlet).
03

Calculate the Coefficient of Performance (COP)

The Coefficient of Performance (COP) is the ratio of the desired output (cooling effect) to the input work (work of compression) in the refrigeration cycle. Calculate the COP using the following formula: COP = \(\frac{h_{1} - h_{4}}{h_{2} - h_{1}}\) Where \(h_{1}\), \(h_{2}\), \(h_{3}\), and \(h_{4}\) are the enthalpy values at state points 1, 2, 3, and 4 respectively.
04

Vary the condenser pressure

Now, vary the condenser pressure from 400 to 1400 kPa in a suitable interval, e.g., increments of 100 kPa. Calculate the COP for each of these condenser pressures using the formula derived in Step 3.
05

Create the plot

Using the resulting data for each condenser pressure and their respective COPs, create a plot in your simulation software showing the COP as a function of the condenser pressure.
06

Analyze the results

Discuss the relationship between condenser pressure and COP from the generated plot. Based on your analysis, you can draw conclusions about the effect of changing condenser pressure on the performance of an ideal vapor-compression refrigeration cycle using R-134a as the working fluid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Performance (COP)
In the context of vapor-compression refrigeration cycles, the Coefficient of Performance (COP) is a critical measure of efficiency. It is the ratio of the desired effect, which for a refrigerator is the amount of heat removed from the cooled space, to the work input required to remove that heat.

For the ideal refrigeration cycle, the formula to calculate COP is: \[\text{COP} = \frac{h_{1} - h_{4}}{h_{2} - h_{1}}\]where \(h_{x}\) represents the enthalpy at particular points in the cycle. A higher COP means that the refrigeration cycle is more efficient, as it requires less work to achieve the same cooling effect.

Understanding COP helps in designing systems that are cost-effective and energy-efficient. For instance, when making decisions about equipment for cooling applications, one must consider the COP among other factors such as initial cost or maintenance expenses.
Condenser Pressure
In a vapor-compression refrigeration cycle, the condenser pressure plays a pivotal role in determining the system's overall performance. Influencing the temperature at which condensation occurs, higher pressures correspond to higher temperatures. This relationship affects the thermal gradient between the condensing refrigerant and the ambient temperature, which in turn impacts the efficiency of heat rejection from the refrigerant to the surroundings.

The investigation into how condenser pressure affects the COP shows that there is a balancing act between the pressure and efficient operation. Notably, if the pressure is too high, the cycle may have to do more work to achieve a given level of cooling, thus potentially reducing the COP. Conversely, lower pressures can improve COP up to the point where other cycle aspects may become less effective, such as an increase in the required compressor displacement volume.
R-134a Refrigerant Properties
The refrigerant R-134a, also known as Tetrafluoroethane, is commonly used in refrigeration and air conditioning applications. Its properties, both thermodynamic and environmental, have made it a prominent replacement for older refrigerants that were harmful to the ozone layer.

Important properties of R-134a affecting refrigeration cycles include its boiling point, specific heat, and pressure-enthalpy characteristics. During the cycle, it undergoes phase changes and temperature variations that are reliant upon these thermodynamic properties. Understanding these properties is crucial for accurate cycle analysis and simulation.

Refrigerant properties must be correctly input into simulation software to achieve realistic and reliable results. They affect all parts of the cycle, especially the heat transferred during the condensation and evaporation processes, and thus affect the system's COP markedly.
Thermodynamic Simulation Software
Modern engineering extensively utilizes thermodynamic simulation software, such as EES, to model and analyze refrigeration cycles and other thermal systems. This software aids engineers and students alike in understanding complex processes by providing a platform to simulate real-world conditions.

By inputting various parameters like evaporator and condenser pressures, refrigerant characteristics, and component information, users can visualize how changes affect the system's performance. The ability to systematically vary conditions, such as the condenser pressure, and immediately see the effect on the COP provides invaluable insight into refrigeration cycle optimization.

Suitable for both educational and professional applications, simulation software offers a powerful tool for thermodynamic analysis, promoting a more profound comprehension of how vapor-compression refrigeration cycles behave under different operating conditions.

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Most popular questions from this chapter

A reversible absorption refrigerator consists of a reversible heat engine and a reversible refrigerator. The system removes heat from a cooled space at \(-15^{\circ} \mathrm{C}\) at a rate of \(70 \mathrm{kW}\) The refrigerator operates in an environment at \(25^{\circ} \mathrm{C}\). If the heat is supplied to the cycle by condensing saturated steam at \(150^{\circ} \mathrm{C},\) determine \((a)\) the rate at which the steam condenses, and (b) the power input to the reversible refrigerator. (c) If the COP of an actual absorption chiller at the same temperature limits has a COP of \(0.8,\) determine the second-law efficiency of this chiller.

A refrigerator uses refrigerant-134a as the working fluid and operates on the ideal vapor-compression refrigeration cycle except for the compression process. The refrigerant enters the evaporator at \(120 \mathrm{kPa}\) with a quality of 34 percent and leaves the compressor at \(70^{\circ} \mathrm{C}\). If the compressor consumes \(450 \mathrm{W}\) of power, determine \((a)\) the mass flow rate of the refrigerant, ( \(b\) ) the condenser pressure, and ( \(c\) ) the COP of the refrigerator.

How does the COP of a cascade refrigeration system compare to the COP of a simple vapor-compression cycle operating between the same pressure limits?

A copper and a constantan wire are formed into a closed circuit by connecting the ends. Now one junction is heated by a burning candle while the other is maintained at room temperature. Do you expect any electric current to flow through this circuit?

An absorption refrigeration system that receives heat from a source at \(95^{\circ} \mathrm{C}\) and maintains the refrigerated space at \(0^{\circ} \mathrm{C}\) is claimed to have a COP of \(3.1 .\) If the environmental temperature is \(19^{\circ} \mathrm{C}\), can this claim be valid? Justify your answer.

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