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Why is the reversed Carnot cycle executed within the saturation dome not a realistic model for refrigeration cycles?

Short Answer

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Answer: The reversed Carnot cycle executed within the saturation dome is not a realistic model for refrigeration cycles due to several reasons: 1. Isothermal heat transfer is difficult to achieve in practice, requiring infinitely large heat exchangers. 2. The isentropic (adiabatic) compression and expansion processes assume no heat loss or friction, which is unrealistic in real-life systems. 3. The two-phase nature of the working fluid within the saturation dome makes it difficult to effectively transfer heat and introduces mechanical complications and inefficiencies due to phase change during compression and expansion processes. These challenges make the reversed Carnot cycle within the saturation dome an ideal theoretical concept but an unrealistic model for practical refrigeration cycles.

Step by step solution

01

Introduction to Reversed Carnot Cycle

The reversed Carnot cycle is a theoretical thermodynamic cycle used to represent the ideal refrigeration cycle. It consists of two isothermal processes (in which the temperature remains constant) and two adiabatic processes (in which there is no heat exchange). In the reversed Carnot cycle, heat is extracted from a low-temperature source, and the heat is rejected at a high-temperature sink while consuming work input.
02

Understanding the Saturation Dome

The saturation dome represents the phase transition between a liquid and vapor phase in a pressure-temperature (P-T) or temperature-entropy (T-s) diagram. Within the saturation dome, a substance can exist in both liquid-vapor equilibrium and two-phase equilibrium. For a refrigeration cycle, the working fluid undergoes transitions between the liquid and vapor phases as it absorbs and rejects heat.
03

Overview of Practical Refrigeration Cycles

In a practical refrigeration cycle, the working fluid undergoes a closed-loop process of evaporation, compression, condensation, and expansion. This cycle aims to efficiently extract heat from a low-temperature source and reject it to a high-temperature sink, while minimizing work input and maintaining continuous operation.
04

Reversed Carnot Cycle within Saturation Dome

In the reversed Carnot cycle executed within the saturation dome, the working fluid would undergo isothermal heat transfer at constant temperature during both the evaporation and condensation processes. This would maintain the working fluid within the dome, meaning it would always be in a mixture of liquid and vapor states.
05

Inefficiencies and Unreality of Reversed Carnot Cycle

There are several reasons why the reversed Carnot cycle executed within the saturation dome is not a realistic model for refrigeration cycles: 1. Isothermal heat transfer is difficult to achieve in practice, as it requires infinitely large heat exchangers to maintain a constant temperature during evaporation and condensation. 2. The isentropic (adiabatic) compression and expansion processes assume no heat loss or friction, which is also unrealistic in real-life systems. 3. The two-phase nature of the working fluid within the saturation dome makes it difficult to effectively transfer heat. Moreover, the simultaneous existence of liquid and vapor in compressors and expanders introduces mechanical complications and inefficiencies due to the phase change during compression and expansion processes. In summary, although the reversed Carnot cycle within the saturation dome presents an ideal theoretical concept, the practical challenges in implementing such a cycle makes it an unrealistic model for refrigeration cycles. Instead, actual refrigeration cycles use alternative processes and components to achieve efficient and practical heat transfer and work input.

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Most popular questions from this chapter

Air enters the compressor of an ideal gas refrigeration cycle at \(7^{\circ} \mathrm{C}\) and \(35 \mathrm{kPa}\) and the turbine at \(37^{\circ} \mathrm{C}\) and \(160 \mathrm{kPa}\). The mass flow rate of air through the cycle is \(0.2 \mathrm{kg} / \mathrm{s}\). Assuming variable specific heats for air, determine ( \(a\) ) the rate of refrigeration, \((b)\) the net power input, and \((c)\) the coefficient of performance.

A refrigerator operates on the ideal vapor compression refrigeration cycle with \(\mathrm{R}-134 \mathrm{a}\) as the working fluid between the pressure limits of 120 and 800 kPa. If the rate of heat removal from the refrigerated space is \(32 \mathrm{kJ} / \mathrm{s}\), the mass flow rate of the refrigerant is \((a) 0.19 \mathrm{kg} / \mathrm{s}\) \((b) 0.15 \mathrm{kg} / \mathrm{s}\) \((c) 0.23 \mathrm{kg} / \mathrm{s}\) \((d) 0.28 \mathrm{kg} / \mathrm{s}\) \((e) 0.81 \mathrm{kg} / \mathrm{s}\)

A gas refrigeration system using air as the working fluid has a pressure ratio of \(5 .\) Air enters the compressor at \(0^{\circ} \mathrm{C}\). The high- pressure air is cooled to \(35^{\circ} \mathrm{C}\) by rejecting heat to the surroundings. The refrigerant leaves the turbine at \(-80^{\circ} \mathrm{C}\) and then it absorbs heat from the refrigerated space before entering the regenerator. The mass flow rate of air is \(0.4 \mathrm{kg} / \mathrm{s} .\) Assuming isentropic efficiencies of 80 percent for the compressor and 85 percent for the turbine and using constant specific heats at room temperature, determine ( \(a\) ) the effectiveness of the regenerator, \((b)\) the rate of heat removal from the refrigerated space, and \((c)\) the COP of the cycle. Also, determine ( \(d\) ) the refrigeration load and the COP if this system operated on the simple gas refrigeration cycle. Use the same compressor inlet temperature as given, the same turbine inlet temperature as calculated, and the same compressor and turbine efficiencies.

A copper and a constantan wire are formed into a closed circuit by connecting the ends. Now one junction is heated by a burning candle while the other is maintained at room temperature. Do you expect any electric current to flow through this circuit?

It is proposed to run a thermoelectric generator in conjunction with a solar pond that can supply heat at a rate of \(7 \times 10^{6} \mathrm{kJ} / \mathrm{h}\) at \(90^{\circ} \mathrm{C}\). The waste heat is to be rejected to the environment at \(22^{\circ} \mathrm{C}\). What is the maximum power this thermoelectric generator can produce?

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