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Consider a cogeneration plant for which the utilization factor is \(0.5 .\) Can the exergy destruction associated with this plant be zero? If yes, under what conditions?

Short Answer

Expert verified
Answer: In theory, a cogeneration plant with a utilization factor of 0.5 can have zero exergy destruction under ideal conditions. However, such a situation is practically unattainable in real-world applications due to inevitable irreversibilities and energy losses present in any energy conversion process. For zero exergy destruction to occur, the plant would need to operate with no irreversibilities, using the most efficient equipment and optimal operating conditions, and its internal processes must be entirely reversible.

Step by step solution

01

Define utilization factor and exergy destruction

Utilization factor is the ratio of the actual useful energy output from a cogeneration plant to the ideal useful energy output. In this exercise, the utilization factor is given as 0.5, which means that the plant is only providing 50% of its potential useful output. Exergy destruction is the energy loss due to irreversibilities in a process. It is the difference between the initial exergy (the maximum work that the system could potentially provide) and the final exergy (the actual work that the system provides).
02

Analyze the relationship between utilization factor and exergy destruction

The utilization factor gives us important information about the efficiency of the cogeneration plant. A high utilization factor means that the plant is operating efficiently and producing more useful energy output, which results in lower exergy destruction due to fewer irreversibilities. On the other hand, a low utilization factor means that the plant is operating less efficiently and producing less useful energy output, which results in higher exergy destruction due to more irreversibilities.
03

Determine if exergy destruction can be zero

In the case of a cogeneration plant with a utilization factor of 0.5, this means that the plant is only operating at 50% of its potential useful output. The remaining 50% of the potential output is not being utilized and may be lost due to irreversibilities. However, it does not necessarily mean that the exergy destruction must be nonzero. In order to have zero exergy destruction, the plant would need to operate with no irreversibilities or energy losses, meaning that all of the energy input to the plant is transformed into useful output. Mathematically, this would mean that the exergy efficiency of the plant is 100%.
04

Identify the conditions for zero exergy destruction

It's important to note that having a zero exergy destruction in a real-world cogeneration plant is practically impossible, due to the presence of various unavoidable irreversibilities, such as friction, heat transfer, and other losses. However, in a theoretical scenario, for the exergy destruction to be zero, the cogeneration plant would need to operate under ideal conditions and have the following properties: 1. The plant must be designed and operated in such a way that it minimizes any energy losses and irreversibilities. This would require the use of the most efficient equipment and optimal operating conditions. 2. The internal processes and energy transformations within the plant must be entirely reversible, meaning that no energy is lost or dissipated in any form. In conclusion, while it is theoretically possible for a cogeneration plant with a utilization factor of 0.5 to have zero exergy destruction under ideal conditions, such a situation is practically unattainable in real-world applications due to inevitable irreversibilities and energy losses that are present in any energy conversion process.

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Most popular questions from this chapter

A steam power plant operates on an ideal reheat Rankine cycle between the pressure limits of \(15 \mathrm{MPa}\) and 10 kPa. The mass flow rate of steam through the cycle is \(12 \mathrm{kg} / \mathrm{s} .\) Steam enters both stages of the turbine at \(500^{\circ} \mathrm{C}\) If the moisture content of the steam at the exit of the low pressure turbine is not to exceed 10 percent, determine \((a)\) the pressure at which reheating takes place, ( \(b\) ) the total rate of heat input in the boiler, and \((c)\) the thermal efficiency of the cycle. Also, show the cycle on a \(T\) -s diagram with respect to saturation lines.

A steam power plant operates on an ideal Rankine cycle with two stages of reheat and has a net power output of \(75 \mathrm{MW}\). Steam enters all three stages of the turbine at \(550^{\circ} \mathrm{C}\) The maximum pressure in the cycle is \(10 \mathrm{MPa}\), and the minimum pressure is 30 kPa. Steam is reheated at 4 MPa the first time and at 2 MPa the second time. Show the cycle on a \(T-s\) diagram with respect to saturation lines, and determine (a) the thermal efficiency of the cycle, and ( \(b\) ) the mass flow rate of the steam.

A large food-processing plant requires \(1.5 \mathrm{lbm} / \mathrm{s}\) of saturated or slightly superheated steam at 140 psia, which is extracted from the turbine of a cogeneration plant. The boiler generates steam at 800 psia and \(1000^{\circ} \mathrm{F}\) at a rate of \(10 \mathrm{lbm} / \mathrm{s}\) and the condenser pressure is 2 psia. Steam leaves the process heater as a saturated liquid. It is then mixed with the feedwater at the same pressure and this mixture is pumped to the boiler pressure. Assuming both the pumps and the turbine have isentropic efficiencies of 86 percent, determine \((a)\) the rate of heat transfer to the boiler and ( \(b\) ) the power output of the cogeneration plant.

A textile plant requires \(4 \mathrm{kg} / \mathrm{s}\) of saturated steam at \(2 \mathrm{MPa},\) which is extracted from the turbine of a cogeneration plant. Steam enters the turbine at \(8 \mathrm{MPa}\) and \(500^{\circ} \mathrm{C}\) at a rate of \(11 \mathrm{kg} / \mathrm{s}\) and leaves at \(20 \mathrm{kPa}\). The extracted steam leaves the process heater as a saturated liquid and mixes with the feedwater at constant pressure. The mixture is pumped to the boiler pressure. Assuming an isentropic efficiency of 88 percent for both the turbine and the pumps, determine \((a)\) the rate of process heat supply, \((b)\) the net power output, and \((c)\) the utilization factor of the plant.

By writing an energy balance on the heat exchanger of a binary vapor power cycle, obtain a relation for the ratio of mass flow rates of two fluids in terms of their enthalpies.

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