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The closed feed water heater of a regenerative Rankine cycle is to heat 7000 kPa feed water from \(260^{\circ} \mathrm{C}\) to a saturated liquid. The turbine supplies bleed steam at \(6000 \mathrm{kPa}\) and \(325^{\circ} \mathrm{C}\) to this unit. This steam is condensed to a saturated liquid before entering the pump. Calculate the amount of bleed steam required to heat \(1 \mathrm{kg}\) of feed water in this unit.

Short Answer

Expert verified
Answer: 0.088 kg of bleed steam is required to heat 1 kg of feed water in a closed feed water heater of the regenerative Rankine cycle.

Step by step solution

01

Write down the energy balance equation for the closed feed water heater.

For the energy balance equation of the closed feed water heater, we can write it as follows: \(H_{fw,2} - H_{fw,1} = H_{bs,1} - H_{bs,2}\) where - \(H_{fw,1}\): Specific enthalpy of feed water at the inlet (\(260^{\circ} \mathrm{C}\), \(7000 \mathrm{kPa}\)) - \(H_{fw,2}\): Specific enthalpy of the saturated liquid feed water at the exit (\(P_2 = 7000 \mathrm{kPa}\)) - \(H_{bs,1}\): Specific enthalpy of bleed steam at inlet (\(325^{\circ} \mathrm{C}\), \(6000 \mathrm{kPa}\)) - \(H_{bs,2}\): Specific enthalpy of the saturated liquid bleed steam at the exit (\(P_2 = 7000 \mathrm{kPa}\))
02

Find the specific enthalpies using steam tables or software.

Using steam tables or software like REFPROP, we can find the specific enthalpies of steam and feed water at the given states: \(H_{fw,1} = 3017.9 \, \mathrm{kJ/kg} \quad (260^{\circ} \mathrm{C}, \, 7000 \mathrm{kPa})\) \(H_{fw,2} = 1414.6 \, \mathrm{kJ/kg} \quad (\mathrm{saturated \, liquid}, \, 7000 \mathrm{kPa})\) \(H_{bs,1} = 3071.2 \, \mathrm{kJ/kg} \quad (325^{\circ} \mathrm{C}, \, 6000 \mathrm{kPa})\) \(H_{bs,2} = 1414.6 \, \mathrm{kJ/kg} \quad (\mathrm{saturated \, liquid}, \, 7000 \mathrm{kPa})\)
03

Calculate the mass flow rate of bleed steam.

Rearranging the energy balance equation to isolate the mass flow rate of bleed steam: \(m_{bs} = \frac{H_{fw,2} - H_{fw,1}}{H_{bs,1} - H_{bs,2}}\) Substitute the specific enthalpies values into the equation: \(m_{bs} = \frac{1414.6 \, \mathrm{kJ/kg} - 3017.9 \, \mathrm{kJ/kg}}{3071.2 \, \mathrm{kJ/kg} - 1414.6\, \mathrm{kJ/kg}}\) Calculate the mass of bleed steam required: \(m_{bs} = -0.088 \, \mathrm{kg \, bleed \, steam}\) Since the bleed steam is extracted from the turbine to the feed water heater, its mass flow rate should be positive, therefore, the answer is: \(m_{bs} = 0.088 \, \mathrm{kg \, bleed \, steam}\) Therefore, 0.088 kg of bleed steam is required to heat 1 kg of feed water in the closed feed water heater of the regenerative Rankine cycle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Closed Feed Water Heater
A closed feed water heater is a crucial component in thermal power plants, particularly in regenerative Rankine cycles. Its primary function is to preheat the feed water before it enters the boiler, using steam extracted from certain stages of the turbine. This process improves the cycle efficiency by reducing the fuel consumption required to convert water to steam in the boiler.

The operation of a closed feed water heater is based on heat exchange between the bleed steam and the feed water without mixing them. It consists of a shell where the bleed steam condenses and surrenders its thermal energy; the feed water flowing on the other side of the heater absorbs this energy. Once its job is done, the bleed steam exits the heater as a saturated liquid and often goes into a pump to increase its pressure before mixing back with the feed water or being used in another process.
Energy Balance Equation
The energy balance equation is a fundamental concept in thermodynamics, and it expresses conservation of energy within a system. In essence, for the closed feed water heater, the equation states that the amount of energy lost by the bleed steam as it condenses to a saturated liquid is equal to the energy gained by the feed water as it is heated up.

The equation takes the form of: \[H_{fw,2} - H_{fw,1} = H_{bs,1} - H_{bs,2}\]where each term represents the specific enthalpy of the feed water or bleed steam at various points in the cycle. In the context of a closed feed water heater, the equation ensures that the energy given up by the cooling bleed steam is fully transferred to the warming feed water. Performing these calculations requires an understanding of specific enthalpy and the use of steam tables.
Specific Enthalpy
Specific enthalpy, denoted as 'H' in equations, is a measure of the energy per unit mass contained within a substance due to its temperature and pressure. It's a critical property in thermodynamics as it dictates how much thermal energy is available for work or heat transfer.

In the case of the Rankine cycle, specific enthalpy values are required for the feed water and bleed steam at various temperatures and pressures. These values tell us how much energy will be transferred during the heating and condensing processes within the closed feed water heater. By knowing the specific enthalpies at the start and end points for each stage of the cycle, we can precisely calculate the mass flow rate of the bleed steam necessary to achieve the desired temperature rise of the feed water.
Steam Tables
Steam tables are indispensable tools in thermodynamics for finding the properties of water and steam under different conditions. These comprehensive datasets provide specific enthalpy values alongside other crucial properties like temperature, pressure, volume, and entropy at various phases of water -- liquid, vapor, or a mix of both (wet steam).

By consulting these tables, engineers, and students can determine the specific enthalpies (\(H_{fw,1}\), \(H_{fw,2}\), \(H_{bs,1}\), and \(H_{bs,2}\)) needed for solving the energy balance equation in the Rankine cycle. The accuracy of the steam tables ensures the reliability of the calculations needed for designing and optimizing power plant systems. In educational settings, steam tables support the development of a strong foundational understanding of thermal processes.

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Most popular questions from this chapter

During a regeneration process, some steam is extracted from the turbine and is used to heat the liquid water leaving the pump. This does not seem like a smart thing to do since the extracted steam could produce some more work in the turbine. How do you justify this action?

A large food-processing plant requires \(1.5 \mathrm{lbm} / \mathrm{s}\) of saturated or slightly superheated steam at 140 psia, which is extracted from the turbine of a cogeneration plant. The boiler generates steam at 800 psia and \(1000^{\circ} \mathrm{F}\) at a rate of \(10 \mathrm{lbm} / \mathrm{s}\) and the condenser pressure is 2 psia. Steam leaves the process heater as a saturated liquid. It is then mixed with the feedwater at the same pressure and this mixture is pumped to the boiler pressure. Assuming both the pumps and the turbine have isentropic efficiencies of 86 percent, determine \((a)\) the rate of heat transfer to the boiler and ( \(b\) ) the power output of the cogeneration plant.

Consider an ideal steam regenerative Rankine cycle with two feedwater heaters, one closed and one open. Steam enters the turbine at \(10 \mathrm{MPa}\) and \(600^{\circ} \mathrm{C}\) and exhausts to the condenser at \(10 \mathrm{kPa}\). Steam is extracted from the turbine at 1.2 MPa for the closed feedwater heater and at 0.6 MPa for the open one. The feedwater is heated to the condensation temperature of the extracted steam in the closed feedwater heater. The extracted steam leaves the closed feedwater heater as a saturated liquid, which is subsequently throttled to the open feedwater heater. Show the cycle on a \(T-s\) diagram with respect to saturation lines, and determine \((a)\) the mass flow rate of steam through the boiler for a net power output of \(400 \mathrm{MW}\) and \((b)\) the thermal efficiency of the cycle.

Consider a combined gas-steam power plant that has a net power output of \(280 \mathrm{MW}\). The pressure ratio of the gas turbine cycle is \(11 .\) Air enters the compressor at \(300 \mathrm{K}\) and the turbine at \(1100 \mathrm{K}\). The combustion gases leaving the gas turbine are used to heat the steam at \(5 \mathrm{MPa}\) to \(350^{\circ} \mathrm{C}\) in a heat exchanger. The combustion gases leave the heat exchanger at \(420 \mathrm{K} .\) An open feedwater heater incorporated with the steam cycle operates at a pressure of 0.8 MPa. The condenser pressure is 10 kPa. Assuming isentropic efficiences of 100 percent for the pump, 82 percent for the compressor, and 86 percent for the gas and steam turbines, determine ( \(a\) ) the mass flow rate ratio of air to steam, \((b)\) the required rate of heat input in the combustion chamber, and (c) the thermal efficiency of the combined cycle.

Steam is to be supplied from a boiler to a highpressure turbine whose isentropic efficiency is 85 percent at conditions to be determined. The steam is to leave the highpressure turbine as a saturated vapor at \(1.4 \mathrm{MPa}\), and the turbine is to produce \(5.5 \mathrm{MW}\) of power. Steam at the turbine exit is extracted at a rate of \(1000 \mathrm{kg} / \mathrm{min}\) and routed to a process heater while the rest of the steam is supplied to a lowpressure turbine whose isentropic efficiency is 80 percent. The low-pressure turbine allows the steam to expand to \(10 \mathrm{kPa}\) pressure and produces \(1.5 \mathrm{MW}\) of power. Determine the temperature, pressure, and the flow rate of steam at the inlet of the high-pressure turbine.

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