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Consider a simple ideal Rankine cycle and an ideal regenerative Rankine cycle with one open feed water heater. The two cycles are very much alike, except the feed water in the regenerative cycle is heated by extracting some steam just before it enters the turbine. How would you compare the efficiencies of these two cycles?

Short Answer

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Short Answer: The ideal regenerative Rankine cycle with one open feed water heater has a higher efficiency compared to the simple ideal Rankine cycle. This is because the regenerative cycle incorporates an open feed water heater, which recovers some of the remaining heat of the steam extracted from the turbine. This reduces overall heat rejection in the condenser and requires less heat input in the boiler to produce the same work output, resulting in higher overall efficiency.

Step by step solution

01

Understand the simple ideal Rankine cycle

A simple ideal Rankine cycle consists of four main components: a boiler, a turbine, a condenser, and a feed pump. The process can be summarized in the following steps: 1. Water is pumped from the condenser to the boiler. 2. The water is heated and converted to steam in the boiler. 3. Steam from the boiler expands in the turbine, converting thermal energy into mechanical work. 4. The steam leaves the turbine and enters the condenser, where it is cooled and returns to the liquid state. 5. Condensed water is then pumped back to the boiler, and the cycle repeats.
02

Calculate the efficiency of the simple ideal Rankine cycle

To calculate the efficiency of the simple ideal Rankine cycle, we need to consider the work and heat transfers involved in the four main components. The efficiency is given by the formula: Efficiency = \(\frac{Work_{turbine} - Work_{pump}}{Heat_{input}}\) where \(Work_{turbine}\) is the work done by the turbine, \(Work_{pump}\) is the work required by the pump, and \(Heat_{input}\) is the heat input to the cycle (boiler).
03

Understand the ideal regenerative Rankine cycle with one open feed water heater

A regenerative Rankine cycle with one open feed water heater enhances the efficiency of the simple Rankine cycle. The main difference is the extraction of steam from the turbine before it enters the condenser, which is used to heat the feed water. This results in a higher temperature of the liquid water entering the boiler, increasing the overall efficiency of the cycle.
04

Calculate the efficiency of the ideal regenerative Rankine cycle

To calculate the efficiency of the ideal regenerative Rankine cycle, we need to consider the work and heat transfers involved in the four main components as well as the open feed water heater. The efficiency is given by the formula: Efficiency = \(\frac{Work_{turbine} - Work_{pump}}{Heat_{input}}\) Keep in mind that \(Work_{turbine}\), \(Work_{pump}\), and \(Heat_{input}\) will be different for the regenerative Rankine cycle compared to the simple Rankine cycle due to the feed water heating process.
05

Compare the efficiencies of the simple Rankine cycle and regenerative Rankine cycle

Since the simple Rankine cycle and the regenerative Rankine cycle differ only in the preheating of the feed water, the efficiency of the regenerative Rankine cycle can be expected to be higher. The reason is that the additional open feed water heater recovers some of the remaining heat of the steam extracted from the turbine, reducing the overall heat rejection in the condenser. Consequently, the regenerative Rankine cycle requires less heat input in the boiler to produce the same amount of work output, thus providing a higher overall efficiency.

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Most popular questions from this chapter

How do open feed water heaters differ from closed feed water heaters?

A steam power plant operates on an ideal regenerative Rankine cycle with two open feedwater heaters. Steam enters the turbine at \(8 \mathrm{MPa}\) and \(550^{\circ} \mathrm{C}\) and exhausts to the condenser at \(10 \mathrm{kPa}\). Steam is extracted from the turbine at 0.6 and 0.2 MPa. Water leaves both feedwater heaters as a saturated liquid. The mass flow rate of steam through the boiler is \(16 \mathrm{kg} / \mathrm{s}\). Show the cycle on a \(T\) -s diagram, and determine (a) the net power output of the power plant and ( \(b\) ) the thermal efficiency of the cycle.

Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the boiler at \(5000 \mathrm{kPa},\) the reheat section at \(1200 \mathrm{kPa}\), and the condenser at 20 kPa. The mixture quality at the exit of both turbines is 96 percent. Determine the temperature at the inlet of each turbine and the cycle's thermal efficiency.

The gas-turbine cycle of a combined gas-steam power plant has a pressure ratio of \(12 .\) Air enters the compressor at \(310 \mathrm{K}\) and the turbine at \(1400 \mathrm{K}\). The combustion gases leaving the gas turbine are used to heat the steam at \(12.5 \mathrm{MPa}\) to \(500^{\circ} \mathrm{C}\) in a heat exchanger. The combustion gases leave the heat exchanger at \(247^{\circ} \mathrm{C}\). Steam expands in a high-pressure turbine to a pressure of \(2.5 \mathrm{MPa}\) and is reheated in the combustion chamber to \(550^{\circ} \mathrm{C}\) before it expands in a low-pressure turbine to \(10 \mathrm{kPa} .\) The mass flow rate of steam is \(12 \mathrm{kg} / \mathrm{s}\). Assuming all the compression and expansion processes to be isentropic, determine (a) the mass flow rate of air in the gas-turbine cycle, ( \(b\) ) the rate of total heat input, and ( \(c\) ) the thermal efficiency of the combined cycle.

A steam power plant operates on an ideal reheat regenerative Rankine cycle with one reheater and two feedwater heaters, one open and one closed. Steam enters the high-pressure turbine at \(15 \mathrm{MPa}\) and \(600^{\circ} \mathrm{C}\) and the low-pressure turbine at 1 MPa and \(500^{\circ} \mathrm{C}\). The condenser pressure is 5 kPa. Steam is extracted from the turbine at \(0.6 \mathrm{MPa}\) for the closed feedwater heater and at 0.2 MPa for the open feedwater heater. In the closed feedwater heater, the feedwater is heated to the condensation temperature of the extracted steam. The extracted steam leaves the closed feedwater heater as a saturated liquid, which is subsequently throttled to the open feedwater heater. Show the cycle on a \(T-s\) diagram with respect to saturation lines. Determine \((a)\) the fraction of steam extracted from the turbine for the open feedwater heater, \((b)\) the thermal efficiency of the cycle, and \((c)\) the net power output for a mass flow rate of \(42 \mathrm{kg} / \mathrm{s}\) through the boiler

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