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During a regeneration process, some steam is extracted from the turbine and is used to heat the liquid water leaving the pump. This does not seem like a smart thing to do since the extracted steam could produce some more work in the turbine. How do you justify this action?

Short Answer

Expert verified
Answer: Extracting steam from the turbine and using it to heat the liquid water leaving the pump in a regeneration process is considered a justified action because it increases the overall thermal efficiency of the power plant. Although it may seem counterintuitive, this action minimizes heat loss, saves fuel consumption, reduces thermal stress on the system components, and enhances the performance of the thermal power plant, which ultimately outweighs the potential decrease in output work.

Step by step solution

01

Understand Thermal Efficiency in Thermal Power Plants

Thermal efficiency is a measure of how well a thermal power plant converts heat into useful work. The higher the thermal efficiency, the more work is obtained from the same amount of heat input, and the less heat is wasted. The efficiency of a thermal power plant can be improved by minimizing the heat rejection, or in other words, by maximizing the heat transfer within the system.
02

Discussing Heat Transfer and Carnot Cycle Assumption

Heat transfer is the process by which thermal energy is exchanged between the working fluid and the surroundings. In an ideal thermal power plant, we assume a reversible Carnot cycle that involves two isothermal processes and two adiabatic processes. However, in practice, the Rankine cycle is commonly used to represent the working principle of a thermal power plant, which has some irreversible processes and is not as efficient.
03

Introduce Regeneration in Thermal Power Plants

Regeneration is a practical method to improve the thermal efficiency of a power plant operating on the Rankine cycle. By extracting some steam from the turbine and using it to heat the liquid water leaving the pump, we decrease the temperature difference between the working fluid and the heat source. This results in a reduction of heat losses and hence higher thermal efficiency.
04

Explain the Benefits of Regeneration

By extracting steam to heat the liquid water, less heat is required from the external source (boiler). This saves fuel consumption and reduces the operating cost. Additionally, regeneration can minimize the temperature difference between the working fluid and the surroundings, leading to a decreased risk of thermal stress on the system components and increasing the lifespan of the plant.
05

Justifying the Action of Extracting Steam

In conclusion, extracting steam from the turbine and using it to heat the liquid water leaving the pump in the regeneration process may seem counterintuitive as it could produce more work in the turbine. However, this action increases the overall thermal efficiency of the power plant by minimizing heat loss, saving fuel consumption, and reducing thermal stress on the system components. Therefore, despite somewhat decreasing the output work, this action significantly improves the performance of the thermal power plant and is thus justified.

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Most popular questions from this chapter

Consider a steam power plant that operates on the ideal reheat Rankine cycle. The plant maintains the boiler at \(5000 \mathrm{kPa},\) the reheat section at \(1200 \mathrm{kPa}\), and the condenser at 20 kPa. The mixture quality at the exit of both turbines is 96 percent. Determine the temperature at the inlet of each turbine and the cycle's thermal efficiency.

A steam power plant operates on an ideal reheat regenerative Rankine cycle with one reheater and two feedwater heaters, one open and one closed. Steam enters the high-pressure turbine at \(15 \mathrm{MPa}\) and \(600^{\circ} \mathrm{C}\) and the low-pressure turbine at 1 MPa and \(500^{\circ} \mathrm{C}\). The condenser pressure is 5 kPa. Steam is extracted from the turbine at \(0.6 \mathrm{MPa}\) for the closed feedwater heater and at 0.2 MPa for the open feedwater heater. In the closed feedwater heater, the feedwater is heated to the condensation temperature of the extracted steam. The extracted steam leaves the closed feedwater heater as a saturated liquid, which is subsequently throttled to the open feedwater heater. Show the cycle on a \(T-s\) diagram with respect to saturation lines. Determine \((a)\) the fraction of steam extracted from the turbine for the open feedwater heater, \((b)\) the thermal efficiency of the cycle, and \((c)\) the net power output for a mass flow rate of \(42 \mathrm{kg} / \mathrm{s}\) through the boiler

Turbine bleed steam enters an open feed water heater of a regenerative Rankine cycle at 40 psia and \(280^{\circ} \mathrm{F}\) while the cold feed water enters at \(110^{\circ} \mathrm{F}\). Determine the ratio of the bleed steam mass flow rate to the inlet feed water mass flow rate required to heat the feed water to \(250^{\circ} \mathrm{F}\)

Consider an ideal steam regenerative Rankine cycle with two feedwater heaters, one closed and one open. Steam enters the turbine at \(10 \mathrm{MPa}\) and \(600^{\circ} \mathrm{C}\) and exhausts to the condenser at \(10 \mathrm{kPa}\). Steam is extracted from the turbine at 1.2 MPa for the closed feedwater heater and at 0.6 MPa for the open one. The feedwater is heated to the condensation temperature of the extracted steam in the closed feedwater heater. The extracted steam leaves the closed feedwater heater as a saturated liquid, which is subsequently throttled to the open feedwater heater. Show the cycle on a \(T-s\) diagram with respect to saturation lines, and determine \((a)\) the mass flow rate of steam through the boiler for a net power output of \(400 \mathrm{MW}\) and \((b)\) the thermal efficiency of the cycle.

Pressurized feedwater in a steam power plant is to be heated in an ideal open feedwater heater that operates at a pressure of 2 MPa with steam extracted from the turbine. If the enthalpy of feedwater is \(252 \mathrm{kJ} / \mathrm{kg}\) and the enthalpy of extracted steam is \(2810 \mathrm{kJ} / \mathrm{kg}\), the mass fraction of steam extracted from the turbine is \((a) 10\) percent \((b) 14\) percent \((c) 26\) percent \((d) 36\) percent \((e) 50\) percent

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