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A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 2500 psia in the boiler and 5 psia in the condenser. What is the minimum temperature required at the turbine inlet such that the quality of the steam leaving the turbine is not below 80 percent. When operated at this temperature, what is the thermal efficiency of this cycle?

Short Answer

Expert verified
Answer: To find the minimum temperature at the turbine inlet, we need to analyze the Rankine cycle and use the given information on boiler and condenser pressures. The temperature at the turbine inlet can be calculated using the entropy at state 3 and the saturated steam tables. Once the temperature is determined, the thermal efficiency of the cycle can be calculated using the work done by the turbine and pump and the heat input to the cycle.

Step by step solution

01

Initial Information and Calculations

First, we need to convert the given pressures to SI units (pascals): Boiler pressure (P_2) = 2500 psia = 2500 * 6894.76 Pa = 17,236,900 Pa Condenser pressure (P_1) = 5 psia = 5 * 6894.76 Pa = 34,473.8 Pa Now, let's calculate the enthalpy and entropy of water vapor and liquid at both pressures: State 2 (P_2): Enthalpy of vapor (h_2v) = h_fg (P_2) Entropy of vapor (s_2v) = s_fg (P_2) State 1 (P_1): Enthalpy of liquid (h_1f) = h_f (P_1) Enthalpy of vapor (h_1g) = h_g (P_1) Entropy of vapor (s_1g) = s_g (P_1) We can use steam tables to find these values.
02

Turbine Inlet Temperature

We are given that the quality of steam leaving the turbine should not be below 80%. So, we have: X = 0.8 where X is the quality of steam. We can now calculate the entropy of the steam at state 3 using the isentropic expansion process (s_3 = s_2v). The quality of steam at the outlet can be determined as follows: s_3 = s_1f + X * (s_1g - s_1f) Now, we can calculate the temperature at the turbine inlet (T_3) using the entropy at state 3: T_3 = T_{sat}(s_3)
03

Turbine Work, Pump Work, and Heat Input

Next, we can calculate the work done by the turbine (W_turbine), the work done by the pump (W_pump), and the heat input to the cycle (Q_in): W_turbine = h_3 - h_4 = h_3 - (h_1f + X * (h_1g-h_1f)) W_pump = v_1 * (P_2 - P_1) ≈ h_2f - h_1f Q_in = h_3 - h_2v
04

Thermal Efficiency

Finally, we can find the thermal efficiency (η) of the Rankine cycle using the following formula: η = (W_turbine - W_pump) / Q_in Now, we have calculated the minimum required temperature at the turbine inlet and the thermal efficiency of the cycle.

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Most popular questions from this chapter

An ideal reheat Rankine cycle with water as the working fluid operates the boiler at \(15,000 \mathrm{kPa}\), the reheater at \(2000 \mathrm{kPa}\), and the condenser at \(100 \mathrm{kPa}\). The temperature is \(450^{\circ} \mathrm{C}\) at the entrance of the high-pressure and low pressure turbines. The mass flow rate through the cycle is \(1.74 \mathrm{kg} / \mathrm{s} .\) Determine the power used by pumps, the power produced by the cycle, the rate of heat transfer in the reheater, and the thermal efficiency of this system.

Why is the Carnot cycle not a realistic model for steam power plants?

A steam power plant operates on an ideal regenerative Rankine cycle with two open feedwater heaters. Steam enters the turbine at \(8 \mathrm{MPa}\) and \(550^{\circ} \mathrm{C}\) and exhausts to the condenser at \(10 \mathrm{kPa}\). Steam is extracted from the turbine at 0.6 and 0.2 MPa. Water leaves both feedwater heaters as a saturated liquid. The mass flow rate of steam through the boiler is \(16 \mathrm{kg} / \mathrm{s}\). Show the cycle on a \(T\) -s diagram, and determine (a) the net power output of the power plant and ( \(b\) ) the thermal efficiency of the cycle.

Consider a combined gas-steam power plant. Water for the steam cycle is heated in a well-insulated heat exchanger by the exhaust gases that enter at \(800 \mathrm{K}\) at a rate of \(60 \mathrm{kg} / \mathrm{s}\) and leave at \(400 \mathrm{K} .\) Water enters the heat exchanger at \(200^{\circ} \mathrm{C}\) and \(8 \mathrm{MPa}\) and leaves at \(350^{\circ} \mathrm{C}\) and \(8 \mathrm{MPa}\). If the exhaust gases are treated as air with constant specific heats at room temperature, the mass flow rate of water through the heat exchanger becomes \((a) 11 \mathrm{kg} / \mathrm{s}\) \((b) 24 \mathrm{kg} / \mathrm{s}\) \((c) 46 \mathrm{kg} / \mathrm{s}\) \((d) 53 \mathrm{kg} / \mathrm{s}\) \((e) 60 \mathrm{kg} / \mathrm{s}\)

Consider a cogeneration plant for which the utilization factor is \(1 .\) Is the irreversibility associated with this cycle necessarily zero? Explain.

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