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Why is the Carnot cycle not a realistic model for steam power plants?

Short Answer

Expert verified
Answer: The Carnot cycle is not a realistic model for steam power plants due to its assumptions of reversible processes, ideal working medium, requirement of isothermal expansion and compression, impractical design requirements, and its focus on maximum efficiency that cannot be achieved in real-world power plants.

Step by step solution

01

Reason 1: Reversible Processes

The Carnot cycle is based on reversible processes, meaning that they can proceed in the reverse direction while the system remains in equilibrium. In reality, real processes are irreversible, and energy losses occur due to friction, turbulence, and other factors. A real steam power plant can't operate with completely reversible processes, so it can't achieve the efficiency of a Carnot cycle.
02

Reason 2: Ideal Working Medium

The Carnot cycle assumes an ideal working medium that has no internal friction, does not conduct heat during adiabatic processes, and has an infinite heat capacity. However, in a steam power plant, water and steam are the working medium which exhibit real properties and can't be considered ideal. Thus, the behavior of water/steam will deviate from that of an ideal working medium, affecting the overall efficiency of the power plant.
03

Reason 3: Isothermal Expansion and Compression

The Carnot cycle involves isothermal expansion and compression processes, which require the working medium to maintain a constant temperature while it absorbs or rejects heat. However, in steam power plants, these processes occur at varying temperatures, making it impossible to achieve perfect isothermal conditions in real-life systems.
04

Reason 4: Impractical Design Requirements

A real steam power plant using the Carnot cycle would require complex heat exchangers to maintain constant temperatures during the isothermal processes and infinite heat capacities. It would also require ideal components with no energy losses (e.g., frictionless turbines and pumps). Designing and building such a power plant is practically impossible due to physical limitations and economic constraints.
05

Reason 5: Lower Actual Efficiency

While the Carnot cycle represents the maximum possible efficiency for a heat engine, real steam power plants operate at significantly lower efficiencies. This is due to various factors such as energy losses in the system, non-ideal behavior of the working medium, and the practical limitations of the components. Consequently, steam power plants cannot achieve the efficiency predicted by the Carnot cycle. In conclusion, the Carnot cycle is not a realistic model for steam power plants due to its assumptions of reversible processes, its ideal working medium, impractical design requirements, and its focus on maximum efficiency that cannot be achieved in real-world power plants.

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Most popular questions from this chapter

A steam power plant operates on a simple ideal Rankine cycle between the pressure limits of 1250 and 2 psia. The mass flow rate of steam through the cycle is \(75 \mathrm{lbm} / \mathrm{s}\). The moisture content of the steam at the turbine exit is not to exceed 10 percent. Show the cycle on a \(T-s\) diagram with respect to saturation lines, and determine \((a)\) the minimum turbine inlet temperature, \((b)\) the rate of heat input in the boiler, and \((c)\) the thermal efficiency of the cycle.

A textile plant requires \(4 \mathrm{kg} / \mathrm{s}\) of saturated steam at \(2 \mathrm{MPa},\) which is extracted from the turbine of a cogeneration plant. Steam enters the turbine at \(8 \mathrm{MPa}\) and \(500^{\circ} \mathrm{C}\) at a rate of \(11 \mathrm{kg} / \mathrm{s}\) and leaves at \(20 \mathrm{kPa}\). The extracted steam leaves the process heater as a saturated liquid and mixes with the feedwater at constant pressure. The mixture is pumped to the boiler pressure. Assuming an isentropic efficiency of 88 percent for both the turbine and the pumps, determine \((a)\) the rate of process heat supply, \((b)\) the net power output, and \((c)\) the utilization factor of the plant.

Consider a simple ideal Rankine cycle. If the condenser pressure is lowered while keeping turbine inlet state the same, \((a)\) the turbine work output will decrease. \((b)\) the amount of heat rejected will decrease. \((c)\) the cycle efficiency will decrease. \((d)\) the moisture content at turbine exit will decrease. \((e)\) the pump work input will decrease.

A steam power plant operates on the simple ideal Rankine cycle between the pressure limits of \(10 \mathrm{kPa}\) and \(5 \mathrm{MPa},\) with a turbine inlet temperature of \(600^{\circ} \mathrm{C} .\) The rate of heat transfer in the boiler is \(300 \mathrm{kJ} / \mathrm{s}\). Disregarding the pump work, the power output of this plant is \((a) 93 \mathrm{kW}\) \((b) 118 \mathrm{kW}\) \((c) 190 \mathrm{kW}\) \((d) 216 \mathrm{kW}\) \((e) 300 \mathrm{kW}\)

A steam power plant operates on an ideal Rankine cycle with two stages of reheat and has a net power output of \(75 \mathrm{MW}\). Steam enters all three stages of the turbine at \(550^{\circ} \mathrm{C}\) The maximum pressure in the cycle is \(10 \mathrm{MPa}\), and the minimum pressure is 30 kPa. Steam is reheated at 4 MPa the first time and at 2 MPa the second time. Show the cycle on a \(T-s\) diagram with respect to saturation lines, and determine (a) the thermal efficiency of the cycle, and ( \(b\) ) the mass flow rate of the steam.

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