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What happens to the gravitational potential energy when water at the top of a waterfall falls to the pool below?

Short Answer

Expert verified

As the water falls from the top of the waterfall, the gravitational potential energy of water decreases.

Step by step solution

01

Understanding variation of gravitational potential energy with height

The magnitude of gravitational energy is directly proportional to the height above the ground (taking potential energy at ground level to be zero).

02

Formula of gravitational potential energy

When we take potential energy at ground level to be zero, the formula for gravitational potential energy for an object of mass m, which is at vertical height h, is \[E = mgh\].

03

Analysing potential energy when the water falls from the top

Initially, water was at a greater height from the ground in comparison to its final position. Thus, we can conclude from the gravitational potential energy formula that potential energy will reduce when the water falls.

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Most popular questions from this chapter

In Fig. 6-31, water balloons are tossed from the roof of a building, all with the same speed but with different launch angles. Which one has the highest speed when it hits the ground? Ignore air resistance. Explain your answer.

Fig. 6-31 Problem 12

(II) A man doing push-ups pauses in the position shown in Fig. 9โ€“65. His mass \({\bf{m = 68}}\;{\bf{kg}}\). Determine the normal force exerted by the floor (a) on each hand; (b) on each foot.

A 125-kg astronaut (including space suit) acquires a speed of \({\bf{2}}{\bf{.50}}\;{{\bf{m}} \mathord{\left/{\vphantom {{\bf{m}} {\bf{s}}}} \right.\\} {\bf{s}}}\) by pushing off with her legs from a 1900-kg space capsule.

(a) What is the change in speed of the space capsule?

(b) If the push lasts 0.600 s, what is the average force exerted by each on the other? As the reference frame, use the position of the capsule before the push. (c) What is the kinetic energy of each after the push?

A projectile is fired at an upward angle of from the top of a 135-m-high cliff with a speed of. What will be its speed when it strikes the ground below? (Use conservation of energy.)

A hand exerts a constant horizontal force on a block that is free to slide on a frictionless surface (Fig. 6โ€“30). The block starts from rest at point A, and by the time it has traveled a distance d to point B it is traveling with speed \({v_{\rm{B}}}\). When the block has traveled another distance d to point C, will its speed be greater than, less than, or equal to \(2{v_{\rm{B}}}\)? Explain your reasoning.

FIGURE 6โ€“30 Question 8.

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