Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A cubic box of volume 6.15ร—10โˆ’2m3 is filled with air at atmospheric pressure at 15ยฐC. The box is closed and heated to 165ยฐC. What is the net force on each side of the box?

Short Answer

Expert verified

The force on each side of the box is 8207 N.

Step by step solution

01

Given data

The volume of the box isV=6.15ร—10โˆ’2m3.

The initial temperature isT1=15โˆ˜C=288K.

The final temperature isT2=165โˆ˜C=438K.

The initial pressure of the air inside the box isP1=1atm.

LetP2be the final pressure of the air inside the box.

LetLbe the sides of the cubic box.

Assume that there is no change in the volume of the box.

02

Concepts

The force on any side of the box equals the product of the pressure and area.

For this problem, you have to useP1T1=P2T2equation.

03

Calculation

Now, from the ideal gas law, you get:

cPV=nRTPT=nRV

The volume is constant in the process. Therefore,

cP1T1=P2T2P2=P1T2T1P2=(1atm)438K288KP2=1.52atm

Now, the extra pressure inside the box is:

cฮ”P=P2โˆ’P1=1.52atmโˆ’1atm=0.52atm=0.52ร—1.013ร—105Pa

Again, you get:

cL3=VL=V1/3L2=V2/3L2=(6.15ร—10โˆ’2m3)2/3

Therefore, the area of a side of the box is (6.15ร—10โˆ’2m3)2/3.

Now, the force on the side of the box is:

cF=P2L2=(0.52ร—1.013ร—105Pa)ร—(6.15ร—10โˆ’2m3)2/3=8207N

Hence, the force on each side of the box is 8207 N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free