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Chapter 9: Q9-12Q (page 230)

Why is it not possible to sit upright in a chair and rise to your feet without first leaning forward?

Short Answer

Expert verified

It is not possible to sit upright in a chair and rise to your feet without first leaning forward because torque is exerted by gravity.

Step by step solution

01

Understanding the position of center of mass

In this problem, the person will not be able to stand if they try to rise from the sitting position because their center of mass is not over their point of support.

02

Explanation for the significance when you try to sit upright in a chair and rise to your feet without leaning forward

When a person is normally sitting on a chair, they try to rise to their feet without first leaning in the forward direction. In such a case, gravity will apply torque about the feet, rotating them back into the chair. Leaning forward causes the center of mass to be over their feet for standing up safely.

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Most popular questions from this chapter

(II) At depths of 2000 m in the sea, the pressure is about 200 times atmospheric pressure\(\left( {{{\bf{P}}_{\bf{a}}}{\bf{ = 1}}{\bf{.0 \times 1}}{{\bf{0}}^{\bf{5}}}\;{\bf{N/}}{{\bf{m}}^{\bf{2}}}} \right)\). By what percentage does the interior space of an iron bathysphere’s volume change at this depth?

(II) A 15-cm-long tendon was found to stretch 3.7 mm by a force of 13.4 N. The tendon was approximately round with an average diameter of 8.5 mm. Calculate Young’s modulus of this tendon.

Place yourself facing the edge of an open door. Position your feet astride the door with your nose and abdomen touching the door’s edge. Try to rise on your tiptoes. Why can’t this be done?

A ground retaining wall is shown in Fig. 9–36a. The ground, particularly when wet, can exert a significant force F on the wall. (a) What force produces the torque to keep the wall upright? (b) Explain why the retaining wall in Fig. 9–36b would be much less likely to overturn than that in Fig. 9–36a.

Calculate \({F_{\rm{A}}}\) and \({F_{\rm{B}}}\) for the beam shown in Fig. 9–56. The downward forces represent the weights of machinery on the beam. Assume that the beam is uniform and has a mass of 280 kg.
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