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(II) Two automobiles are equipped with the same single frequency horn. When one is at rest and the other is moving toward the first at 18 m/s, the driver at rest hears a beat frequency of 4.5 Hz. What is the frequency the horns emit? Assume\(T = 20^\circ {\rm{C}}\).

Short Answer

Expert verified

The frequency of horn is \(81.2\;{\rm{Hz}}\).

Step by step solution

01

Understanding the frequency of the automobile

In this problem, the frequency emitted by the automobile will be smaller than the frequency received by the automobile.

02

Given Data

The beat frequency is\({f_{\rm{b}}} = 4.5\;{\rm{Hz}}\).

The speed of the automobile is\(v = 18\;{\rm{m/s}}\).

The temperature is\(T = 20^\circ {\rm{C}}\).

03

Evaluating the frequency of the horn

The relation to the calculate frequency is given by,

\({f_{\rm{h}}} = \left( {\frac{{{v_{\rm{s}}}}}{v} - 1} \right){f_{\rm{b}}}\)

Here, \({v_{\rm{s}}}\) is the speed of the sound.

On plugging the values in the above relation.

\(\begin{aligned}{l}{f_{\rm{h}}} &= \left( {\frac{{343\;{\rm{m/s}}}}{{18\;{\rm{m/s}}}} - 1} \right)\left( {4.5\;{\rm{Hz}}} \right)\\{f_{\rm{h}}} &= 81.2\;{\rm{Hz}}\end{aligned}\)

Thus, \({f_{\rm{h}}} = 81.2\;{\rm{Hz}}\) is the required frequency emitted by the horn.

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Most popular questions from this chapter

A guitar string vibrates at a frequency of 330 Hz with a wavelength 1.40 m. The frequency and wavelength of this sound in air (20ยฐC) as it reaches our ears is

(a) same frequency, same wavelength.

(b) higher frequency, same wavelength.

(c) lower frequency, same wavelength.

(d) same frequency, longer wavelength.

(e) same frequency, shorter wavelength.

Question: A tuning fork is set into vibration above a vertical open tube filled with water (Fig 12-40). The water level is allowed to drop slowly. As it does so, the air in the tube above the water level is heard to resonate with the tuning fork when the distance from the tube opening to the water level is 0.125 m and again at 0.395 m. What is the frequency of the tuning fork?

FIGURE 12โ€“40 Problem 79.

At a rock concert, a dB meter registered 130 dB when placed 2.5 m in front of a loudspeaker on stage. (a) What was the power output of the speaker, assuming uniform spherical spreading of the sound and neglecting absorption in the air? (b) How far away would the sound level be 85 dB?

A uniform narrow tube \({\bf{1}}{\bf{.70}}\;{\bf{m}}\) long is open at both ends. It resonates at two successive harmonics of frequencies \({\bf{275}}\;{\bf{Hz}}\) and \({\bf{330}}\;{\bf{Hz}}\) . What is (a) the fundamental frequency, and (b) the speed of sound in the gas in the tube?

Question: (II) (a) Estimate the power output of sound from a person speaking in normal conversation. Use Table 12-2. Assume the sound spreads roughly uniformly over a sphere centered on the mouth. (b) How many people would it take to produce a total sound output of 60 W of ordinary conversation? (Hint: Add intensities, not dBs.)

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