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Can a small force ever exert a greater torque than a larger force? Explain.

Short Answer

Expert verified

It is true that asmall force can exert a greater torque than a larger force if the perpendicular distance is large enough for the smaller force.

Step by step solution

01

Understanding the application of force on the lever arm

Consider the application of force on the lever arm. The lever arm distance is large. Apply the force on the lever arm.The torque that acts on the lever arm is the product of lever arm distance (perpendicular distance) and the force applied on the lever arm.

The value of torque is more when the distance or length of the lever arm is more, and the value of force acting on the lever is less and vice versa.

Consider a wrench which can be represented as:

02

Determination of the torque due to a larger force

Consider that a force\(\left( F \right)\)of 10 N acts on the lever arm having a distance\(\left( r \right)\)of 2 m.

The torque acting on the lever arm can be expressed as:

\(T = F \times r\)

Substitute the values in the above equation.

\(T = 10{\rm{ N}} \times 2{\rm{ m}}\)

\(T = 20{\rm{ N}} \cdot {\rm{m}}\) … (i)

Thus, the torque due to a large force and a small lever distance is\(20{\rm{ N}} \cdot {\rm{m}}\).

03

Determination of the torque due to a smaller force

Consider that a force\(\left( F \right)\)of 5 N acts on the lever arm having a distance\(\left( r \right)\)of 5 m.

The torque acting on the lever arm can be expressed as:

\(T = F \times r\)

Substitute the values in the above equation.

\(T = 5{\rm{ N}} \times 5{\rm{ m}}\)

\(T = 25{\rm{ N}} \cdot {\rm{m}}\) … (ii)

Thus, the torque due to a small force and a large lever distance is\(25{\rm{ N}} \cdot {\rm{m}}\).

From equations (i) and (ii), it is clear that the torque due to a small force and a large lever distance is greater than the torque due to a large force and a small lever distance.

Thus, it is true that a small force can exert a greater torque than a larger force if the perpendicular distance is large enough for the smaller force.

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Most popular questions from this chapter

A small mass m on a string is rotating without friction in a circle. The string is shortened by pulling it through the axis of rotation without any external torque, Fig. 8–39. What happens to the tangential velocity of the object?

(a) It increases.

(b) It decreases.

(c) It remains the same.

FIGURE 8-39

MisConceptual Questions 10 and 11.

If the coefficient of static friction between a car’s tires and the pavement is 0.65, calculate the minimum torque that must be applied to the 66-cm-diameter tire of a 1080-kg automobile in order to “lay rubber” (make the wheels spin, slipping as the car accelerates). Assume each wheel supports an equal share of the weight.

The solid dot shown in Fig. 8–36 is a pivot point. The board can rotate about the pivot. Which force shown exerts the largest magnitude torque on the board?

FIGURE 8-36MisConceptual Question 4.

A small solid sphere and a small thin hoop are rolling along a horizontal surface with the same translational speed when they encounter a 20° rising slope. If these two objects roll up the slope without slipping, which will rise farther up the slope?

(a) The sphere.

(b) The hoop.

(c) Both the same.

(d) More information about the objects' mass and diameter is needed.

A 4.00-kg mass and a 3.00-kg mass are attached to opposite ends of a very light 42.0-cm-long horizontal rod (Fig. 8–61). The system is rotating at angular speed\(\omega = 5.60\;{\rm{rad/s}}\)about a vertical axle at the center of the rod. Determine (a) the kinetic energy KE of the system, and (b) the net force on each mass.

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