Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Bonnie sits on the outer rim of a merry-go-round, and Jill sits midway between the centre and the rim. The merry-go-round makes one complete revolution every 2 seconds. Jill’s linear velocity is:

(a) the same as Bonnie’s.

(b) twice Bonnie’s.

(c) half of Bonnie’s.

(d) one-quarter of Bonnie’s.

(e) four times Bonnie’s.

Short Answer

Expert verified

The correct answer is option (c) half of Bonnie’s.

Step by step solution

01

Given data

The time required to complete the revolution is \(t = 2\;{\rm{s}}\).

02

Understanding linear velocity

In this problem, one of the misconceptions is that if Jill and Bonnie consume equal time to complete the merry-go-round, their linear velocities will be equivalent.

03

Determine the velocity of Jill

Bonnie is sitting on the outer edge of the merry-go-round, whereas Jill is sitting midway between the center and the rim. So, the distance traveled by Bonnie will be more compared to the distance covered by Jill.

The relation of the linear velocity of Bonnie is:

\({v_{\rm{B}}} = \omega r\)

Here, r is the radius of the ride and \(\omega \) is the angular velocity.

The relation of the linear velocity of Jill is:

\(\begin{aligned}{l}{v_{\rm{J}}} = \omega \left( {\frac{r}{2}} \right)\\{v_{\rm{J}}} = \left( {\frac{1}{2}} \right)\omega r\\{v_{\rm{J}}} = \left( {\frac{1}{2}} \right){v_{\rm{B}}}\end{aligned}\)

Thus, option (c) is the correct answer.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free