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Chapter 8: 8-16Q (page 198)

When a motorcyclist leaves the ground on a jump and leaves the throttle on (so the rear wheel spins), why does the front of the cycle rise up?

Short Answer

Expert verified

The front wheel of the cycle rises up to conserve the angular momentum.

Step by step solution

01

Understanding torque and conservation of momentum

In this problem, the momentum of the total system is conserved as the motorcycle leaves the ground. Also, in this situation, the total torque is equal to zero.

02

Direction of the motorcycle

When a motorcycle is leaving the ground level, and its throttle is on, its rear wheel will rotate faster because there is no torque acting on it. So, in conserving the angular momentum of the motorcycle, the front wheel should rise in the direction opposite to the rear wheel.

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Most popular questions from this chapter

Question:(II) A ball of radius rrolls on the inside of a track of radius R(see Fig. 8–53). If the ball starts from rest at the vertical edge of the track, what will be its speed when it reaches the lowest point of the track, rolling without slipping?

A solid sphere of a 0.72 m diameter can be rotated about an axis through its center by a torque, which accelerates it uniformly from rest through a total of 160 revolutions in 15.0 s. What is the mass of the sphere?

The radius of the roll of paper shown in Fig. 8–67 is 7.6 cm and its moment of inertia is \(I = 3.3 \times {10^{ - 3}}\;{\rm{kg}} \cdot {{\rm{m}}^2}\). A force of 3.5 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of \(I = 0.11\;{\rm{m}} \cdot {\rm{N}}\) is exerted on the roll which gradually brings it to a stop. Assuming that the paper’s thickness is negligible, calculate (a) the length of paper that unrolls during the time that the force is applied (1.3 s) and (b) the length of paper that unrolls from the time the force ends to the time when the roll has stopped moving

Question:(II) A nonrotating cylindrical disk of moment of inertia I is dropped onto an identical disk rotating at angular speed\(\omega \). Assuming no external torques, what is the final common angular speed of the two disks?

A small mass m on a string is rotating without friction in a circle. The string is shortened by pulling it through the axis of rotation without any external torque, Fig. 8–39. What happens to the angular velocity of the object?

(a) It increases.

(b) It decreases.

(c) It remains the same.

FIGURE 8-39

Mis-Conceptual Questions 10 and 11.
See all solutions

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