Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Can the diver of Fig. 8–28 do a somersault without having any initial rotation when she leaves the board? Explain.

Short Answer

Expert verified

Yes, the diver can perform a somersault without having any initial rotation when she leaves the board.

Step by step solution

01

Calculation of angular acceleration 

The angular acceleration of an object can be calculated by dividing the value of the torque by the MOI of the object.

Its value is altered inversely to the value of the MOI of the object.

02

Conservation of angular momentum

The diver can perform a somersault without having any initial rotation when she leaves the board. This is because to perform a somersault, the diver requires some initial angular momentum.

According to the law of conservation of angular momentum, when a body is expanded, the moment of inertia is higher; and hence the angular velocity is shorter.

Moreover, when arms and legs are tucked during the somersault, the moment of inertia is smaller; therefore, the angular velocity rises. When she pushes the board while leaving it, it provides her an initial angular momentum about her center of mass.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(II) A bowling ball of mass 7.25 kg and radius 10.8 cm rolls without slipping down a lane at\({\bf{3}}{\bf{.10 m/s}}\).Calculate its total kinetic energy.

A wheel of mass M has radius R. It is standing vertically on the floor, and we want to exert a horizontal force F at its axle so that it will climb a step against which it rests (Fig. 8–60). The step has height h, where h < R. What minimum force F is needed?

Determine the angular momentum of the Earth (a) about its rotation axis (assume the Earth is a uniform sphere), and (b) in its orbit around the Sun (treat the Earth as a particle orbiting the Sun).

Most of our Solar System’s mass is contained in the Sun, and the planets possess almost all of the Solar System’s angular momentum. This observation plays a key role in theories attempting to explain the formation of our Solar System. Estimate the fraction of the Solar System’s total angular momentum that is possessed by planets using a simplified model which includes only the large outer planets with the most angular momentum. The central Sun (mass\(1.99 \times {10^{30}}\;{\rm{kg}}\), radius\(6.96 \times {10^8}\;{\rm{m}}\)) spins about its axis once every 25 days and the planets Jupiter, Saturn, Uranus, and Neptune move in nearly circular orbits around the Sun with orbital data given in the Table below. Ignore each planet’s spin about its own axis.

Planet

Mean Distance from Sun\(\left( { \times {{10}^6}\;{\rm{km}}} \right)\)

Orbital Period

(Earth Years)

Mass

\(\left( { \times {{10}^{25}}\;{\rm{kg}}} \right)\)

Jupiter

778

11.9

190

Saturn

1427

29.5

56.8

Uranus

2870

84.0

8.68

Neptune

4500

165

10.2

A small mass m on a string is rotating without friction in a circle. The string is shortened by pulling it through the axis of rotation without any external torque, Fig. 8–39. What happens to the tangential velocity of the object?

(a) It increases.

(b) It decreases.

(c) It remains the same.

FIGURE 8-39

MisConceptual Questions 10 and 11.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free