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The speed of waves on a string is \({\bf{97}}{\rm{ }}{\bf{m}}{\rm{/}}{\bf{s}}\).If the frequency of standing waves is 475 Hz, how far apart are two adjacent nodes?

Short Answer

Expert verified

The length between two adjacent nodes is \(0.10{\rm{ m}}\).

Step by step solution

01

Relation of fundamental frequency

In order to determine the length of the string, the expression of the fundamental frequency is used.

02

Given data

The speed of the wave is \(\nu = 97{\rm{ m/s}}\).

The frequency of the standing waves is \(f = 475{\rm{ Hz}}\).

03

Calculation of the length between the adjacent nodes

The length between two adjacent nodes is calculated as:

\(l = \frac{\nu }{{2{f_1}}}\)

Substitute the known values in the above equation.

\(\begin{aligned}{c}l &= \frac{{97{\rm{ m/s}}}}{{2 \times 475{\rm{ Hz}}}}\\ &= 0.10{\rm{ m}}\end{aligned}\)

Thus, the adjacent nodes are \(0.10{\rm{ m}}\)apart.

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