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If a violin string vibrates at 440 Hz as its fundamental frequency, what are the frequencies of the first four harmonics?

Short Answer

Expert verified

The first four harmonics are\(440\;{\rm{Hz}}\), \(880\;{\rm{Hz}}\), \(1320\;{\rm{Hz}}\) and \(1760\;{\rm{Hz}}\).

Step by step solution

01

Understanding about the frequency

Whenever a string/wire vibrates and generates sound then the basic (lower) value of frequency at which sound generates refers as fundamental frequency.The value of the frequency of other harmonics can obtain with the help of fundamental frequency.

02

Identification of given data

The given data can be listed below as,

  • Thefundamental frequency is\(f = 440\;{\rm{Hz}}\).
03

Determining the frequencies of first four harmonics

The expression of the frequency of the second harmonics is given by,

\({f_2} = 2f\).

Here,\({f_2}\)is the frequency of the second harmonics.

Substitute all the known values in the above formula.

\(\begin{aligned}{c}{f_2} &= 2\left( {440\;{\rm{Hz}}} \right)\\ &= 880\;{\rm{Hz}}\end{aligned}\)

The expression of the frequency of the third harmonics is given by,

\({f_3} = 3f\).

Here,\({f_3}\)is the frequency of the third harmonics.

Substitute all the known values in the above formula.

\(\begin{aligned}{c}{f_3} &= 3\left( {440\;{\rm{Hz}}} \right)\\ &= 1320\;{\rm{Hz}}\end{aligned}\)

The expression of the frequency of the fourth harmonics is given by,

\({f_4} = 4f\).

Here,\({f_4}\)is the frequency of the fourth harmonics.

Substitute all the known values in the above formula.

\(\begin{aligned}{c}{f_4} &= 4\left( {440\;{\rm{Hz}}} \right)\\ &= 1760\;{\rm{Hz}}\end{aligned}\)

Thus, the first four harmonics are\(440\;{\rm{Hz}}\), \(880\;{\rm{Hz}}\), \(1320\;{\rm{Hz}}\) and \(1760\;{\rm{Hz}}\).

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Most popular questions from this chapter

(III) Consider two objects, A and B, both undergoing SHM, but with different frequencies, as described by the equations \({{\bf{x}}_{\bf{A}}}{\bf{ = }}\left( {{\bf{2}}{\bf{.0}}\;{\bf{m}}} \right){\bf{sin(4}}{\bf{.0t)}}\) and \({{\bf{x}}_{\bf{B}}}{\bf{ = }}\left( {{\bf{5}}{\bf{.0}}\;{\bf{m}}} \right){\bf{sin(3}}{\bf{.0t)}}\), where t is in seconds. After t = 0, find the next three times t at which both objects simultaneously pass through the origin.

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(c) \({\bf{6 \times 1}}{{\bf{0}}^{\bf{3}}}\;{\bf{days}}\)

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