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Car A hits car B (initially at rest and of equal mass) from behind while going\(38\;{\rm{m/s}}\). Immediately after the collision, car B moves forward at\(15\;{\rm{m/s}}\)and car A is at rest. What fraction of the initial kinetic energy is lost in the collision?

Short Answer

Expert verified

In the collision, 0.85 of the original kinetic energy was lost.

Step by step solution

01

Definition of kinetic energy

The energy possessed by a body by its motion is called kinetic energy.Mathematically it is given by

\(KE = \frac{1}{2}m{v^2}\), … (i)

Here, m is the mass, and v is the velocity of the body.

02

Identification of the given data

The masses of car A and car B are equal, such that\({m_{\rm{A}}} = {m_{\rm{B}}} = m\).

The initial speed of car B is\({v_{\rm{B}}} = 0\).

The initial speed of car A is\({v_{\rm{A}}} = 38\;{\rm{m/s}}\).

The speed of car B after the collision is\({v_{\rm{B}}}^\prime = 15\;{\rm{m/s}}\).

The speed of car A after the collision is \({v_{\rm{A}}}^\prime = 0\).

03

 Step 3: Determining the kinetic energy of the system before and after collision

The initial kinetic energy of the system before the collision is as follows:

\(\begin{array}{c}K{E_{{\rm{initial}}}} = \frac{1}{2}{m_{\rm{A}}}v_{\rm{A}}2 + \frac{1}{2}{m_{\rm{B}}}v_{\rm{B}}2\\ = \frac{1}{2}m{\left( {38\;{\rm{m/s}}} \right)2} + 0\\ = 720m\;{\rm{J}}\end{array}\)

The final kinetic energy of the system after the collision is as follows:

\(\begin{array}{c}K{E_{{\rm{final}}}} = \frac{1}{2}{m_{\rm{A}}}{v_{\rm{A}}}{\prime 2} + \frac{1}{2}{m_{\rm{B}}}{v_{\rm{B}}}{\prime 2}\\ = 0 + \frac{1}{2}m{\left( {15\;{\rm{m/s}}} \right)2}\\ = 110m\;{\rm{J}}\end{array}\)

04

Determining the fraction of kinetic energy lost during the collision

\(\begin{array}{c}K{E_{{\rm{lost}}}} = \frac{{K{E_{{\rm{initial}}}} - K{E_{{\rm{final}}}}}}{{K{E_{{\rm{initial}}}}}}\\ = \frac{{\left( {720m\;{\rm{J}}} \right) - \left( {110m\;{\rm{J}}} \right)}}{{\left( {720m\;{\rm{J}}} \right)}}\\ \approx 0.85\end{array}\)

Thus, the fraction of kinetic energy lost during the collision process is 0.85.

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