Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If a 20-passenger plane is not full, sometimes passengers are told they must sit in certain seats and may not move to empty seats. Why might this be?

Short Answer

Expert verified

The passengers are not allowed to move to the empty seats because that can affect the stability of the plane during flight and may cause an accident.

Step by step solution

01

Understand the seat arrangement of a plane

During the motion of any object, its center of mass should be stable.

The seat arrangement of a plane is such that its center of mass is at a stable position. So, if the plane is mostly empty, the passengers are asked to take certain seats, and they are not allowed to leave them.

02

Explanation for certain specific positions of passengers

If the passengers move to the empty seats during the flight,they can change the position of the center of mass of the plane. This can affect the stability of the plane and may cause an accident. That is why the passengers are not allowed to leave their seats.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A neon atom \(\left( {m = 20.0\;{\rm{u}}} \right)\) makes a perfectly elastic collision with another atom at rest. After the impact, the neon atom travels away at a 55.6ยฐ angle from its original direction and the unknown atom travels away at a \( - {50.0^ \circ }\) angle. What is the mass (in u) of the unknown atom? [Hint: You could use the law of sines.]

An atomic nucleus of mass m traveling with speed v collides elastically with a target particle of mass 2m (initially at rest) and is scattered at 90ยฐ.

(a) At what angle does the target particle move after the collision?

(b) What are the final speeds of the two particles?

(c) What fraction of the initial kinetic energy is transferred to the target particle?

A bullet of mass \(m{\bf{ = 0}}{\bf{.0010}}\;{\bf{kg}}\) embeds itself in a wooden block with mass \(M{\bf{ = 0}}{\bf{.999}}\;{\bf{kg}}\), which then compresses a spring \(\left( {k{\bf{ = 140}}\;{\bf{N/m}}} \right)\) by a distance \(x{\bf{ = 0}}{\bf{.050}}\;{\bf{m}}\) before coming to rest. The coefficient of kinetic friction between the block and table is \(\mu {\bf{ = 0}}{\bf{.50}}\).

(a) What is the initial velocity (assumed horizontal) of the bullet?

(b) What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the bullet and the block?

Astronomers estimate that a 2.0-km-diameter asteroid collides with the Earth once every million years. The collision could pose a threat to life on Earth. (a) Assume a spherical asteroid has a mass of 3200 kg for each cubic meter of volume and moves toward the Earth at\(15\;{\rm{km/s}}\). How much destructive energy could be released when it embeds itself in the Earth? (b) For comparison, a nuclear bomb could release about\(4.0 \times {10^{16}}\;{\rm{J}}\). How many such bombs would have to explode simultaneously to release the destructive energy of the asteroid collision with the Earth?

A 28-g rifle bullet travelling\(190\;{\rm{m/s}}\)embeds itself in a 3.1-kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the vertical and horizontal components of the pendulumโ€™s maximum displacement.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free