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Chapter 17: Q9Q (page 473)

Draw in a few equipotential lines in Fig. 16–32b and c.

FIGURE 16-32

Short Answer

Expert verified

The equipotential lines are shown below,

Step by step solution

01

Understanding of equipotential line

The line along which the electric potential is constant is known as the equipotential line. For a test charge, the equipotential lines are circular.

02

Equipotential lines for the given system of charges

The equipotential lines are shown below for those charge configurations,

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Most popular questions from this chapter

(III) A \({\bf{2}}{\bf{.50}}\;{\bf{\mu F}}\) capacitor is charged to 746 V and a \({\bf{6}}{\bf{.80}}\;{\bf{\mu F}}\) capacitor is charged to 562 V. These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. What will be the potential difference across each and the charge on each? [Hint: Charge is conserved.]

If the electric field \({\bf{\vec E}}\) is uniform in a region, what can you infer about the electric potential V? If V is uniform in a region of space, what can you infer about \({\bf{\vec E}}\).

(II) An electron starting from rest acquires 4.8 keV of KE in moving from point A to point B. (a) How much KE would a proton acquire, starting from rest at B and moving to point A? (b) Determine the ratio of their speeds at the end of their respective trajectories.

(II) An electric field greater than about \({\bf{3 \times 1}}{{\bf{0}}^{\bf{6}}}\;{\bf{V/m}}\)causes air to break down (electrons are removed from the atoms and then recombine, emitting light). See Section 17–2 andTable 17–3. If you shuffle along a carpet and then reach for a doorknob, a spark flies across a gap you estimate to be 1 mm between your finger and the doorknob. Estimate the voltage between your finger and the doorknob. Why is no harm done?

How does the energy stored in a capacitor change when a dielectric is inserted if (a) the capacitor is isolated so Q does not change; (b) the capacitor remains connected to a battery so V does not change? Explain.
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