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(I) The two plates of a capacitor hold \({\bf{ + 2500}}\;{\bf{\mu C}}\) and \( - {\bf{2500}}\;{\bf{\mu C}}\) of charge, respectively, when the potential difference is 960 V. What is the capacitance.

Short Answer

Expert verified

The capacitance of the capacitor is\(2.6\;\mu {\rm{F}}\).

Step by step solution

01

Understanding the capacitance of a capacitor

The capacitor is a charge storage device. The capacitance of a capacitor depends upon the value of the charge on each plate and the potential difference between the plates.

The charge stored in a capacitor is given by,

\(Q = CV\) … (i)

Here, Q is the charge stored, C is the capacitance and V is the potential difference between the plates.

02

Given Data

The charge on the first plate is,\({q_1} = + 2500\;\mu {\rm{C}}\)

The charge on the second plate is,\({q_2} = - 2500\;\mu {\rm{C}}\)

The potential difference is,\(V = 960\;{\rm{V}}\)

03

Evaluation of the capacitance

From equation (i), thecapacitance is given by,

\(C = \frac{{{q_1}}}{V}\)

Substitute the values in the above expression.

\(\begin{aligned}C &= \frac{{2500\;\mu {\rm{C}} \times \left( {\frac{{{{10}^{ - 6}}\;{\rm{C}}}}{{1\;\mu {\rm{C}}}}} \right)}}{{960\;{\rm{V}}}}\\C &= 2.6 \times {10^{ - 6}}\;{\rm{F}} \times \frac{{{{10}^6}\;\mu {\rm{F}}}}{{1\;{\rm{F}}}}\\C &= 2.6\;\mu {\rm{F}}\end{aligned}\)

Thus, the capacitance of the capacitor is \(2.6\;\mu {\rm{F}}\).

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Most popular questions from this chapter

(II) Point a is 62 cm north of a \( - {\bf{3}}{\bf{.8}}\;{\bf{\mu C}}\) point charge, and point b is 88 cm west of the charge (Fig. 17–40). Determine (a) \({{\bf{V}}_{\bf{b}}} - {{\bf{V}}_{\bf{a}}}\) and (b) \({{\bf{\vec E}}_{\bf{b}}} - {{\bf{\vec E}}_{\bf{a}}}\) (magnitude and direction).

FIGURE 17–40 Problem 27.

When a battery is connected to a capacitor, why do the two plates acquire charges of the same magnitude? Will this be true if the two plates are different sizes or shapes?

A battery establishes a voltage Von a parallel-plate capacitor.After the battery is disconnected, the distance between the plates is doubled without loss of charge. Accordingly,the capacitance _________ and the voltage between theplates _________.

(a) increases; decreases.

(b) decreases; increases.

(c) increases; increases.

(d) decreases; decreases.

(e) stays the same; stays the same.

(II) The dipole moment, considered as a vector, points from the negative to the positive charge. The water molecule, Fig. 17–42, has a dipole moment \({\bf{\vec p}}\) which can be considered as the vector sum of the two dipole moments, \({{\bf{\vec p}}_{\bf{1}}}\) and \({{\bf{\vec p}}_{\bf{2}}}\) as shown. The distance between each H and the O is about \({\bf{0}}{\bf{.96 \times 1}}{{\bf{0}}^{{\bf{ - 10}}}}\;{\bf{m}}\). The lines joining the centre of the O atom with each H atom make an angle of 104°, as shown, and the net dipole moment has been measured to be \({\bf{p = 6}}{\bf{.1 \times 1}}{{\bf{0}}^{{\bf{ - 30}}}}\;{\bf{C}} \cdot {\bf{m}}\). Determine the charge q on each H atom.

FIGURE 17–42 Problem 34

(II) How strong is the electric field between the plates of a \({\bf{0}}{\bf{.80}}\;{\bf{\mu F}}\) air-gap capacitor if they are 2.0 mm apart and each has a charge of \({\bf{62}}\;{\bf{\mu C}}\)?

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