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We have seen that the capacitance C depends on the size and position of the two conductors, as well as on the dielectric constant K. What then did we mean when we said that C is a constant in Eq. 17–7?

Short Answer

Expert verified

The capacitance does not rely on charge and voltage.

Step by step solution

01

Understanding dielectric constant

The dielectric constant is described as the term which is equivalent to the fraction of permittivity of a material and permittivity of a vacuum.

02

Evaluation of the change in capacitance  

The relation of capacitance is given by,

\(Q = CV\)

Here, Cis the capacitance, Qis the amount of charge and Vis the voltage across the capacitor.

In general, the capacitance does not get affected by voltage (V) and amount of charge (Q) stored on capacitor plates. Therefore, when one say that capacitance is constant in the above equation; it means that capacitance does not change with voltage and charge.

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Most popular questions from this chapter

(II) How strong is the electric field between the plates of a \({\bf{0}}{\bf{.80}}\;{\bf{\mu F}}\) air-gap capacitor if they are 2.0 mm apart and each has a charge of \({\bf{62}}\;{\bf{\mu C}}\)?

(II) The work done by an external force to move a \( - {\bf{6}}{\bf{.50}}\;{\bf{\mu C}}\) charge from point A to point B is \({\bf{15}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}\;{\bf{J}}\). If the charge was started from rest and had \({\bf{4}}{\bf{.82 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}\;{\bf{J}}\)of kinetic energy when it reached point B, what must be the potential difference between A and B?

(III) Two equal but opposite charges are separated by a distance d, as shown in Fig. 17–41. Determine a formula for \({{\bf{V}}_{{\bf{BA}}}}{\bf{ = }}{{\bf{V}}_{\bf{B}}}{\bf{ - }}{{\bf{V}}_{\bf{A}}}\)for points B and A on the line between the charges situated as shown.

FIGURE 17-41 Problem 30

(II) The dipole moment, considered as a vector, points from the negative to the positive charge. The water molecule, Fig. 17–42, has a dipole moment \({\bf{\vec p}}\) which can be considered as the vector sum of the two dipole moments, \({{\bf{\vec p}}_{\bf{1}}}\) and \({{\bf{\vec p}}_{\bf{2}}}\) as shown. The distance between each H and the O is about \({\bf{0}}{\bf{.96 \times 1}}{{\bf{0}}^{{\bf{ - 10}}}}\;{\bf{m}}\). The lines joining the centre of the O atom with each H atom make an angle of 104°, as shown, and the net dipole moment has been measured to be \({\bf{p = 6}}{\bf{.1 \times 1}}{{\bf{0}}^{{\bf{ - 30}}}}\;{\bf{C}} \cdot {\bf{m}}\). Determine the charge q on each H atom.

FIGURE 17–42 Problem 34

(II) Draw a conductor in the oblong shape of a football. This conductor carries a net negative charge -Q, Draw in a dozen or so electric field lines and equipotential lines.

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